怎样消重这些重复数值?

3tzjq 2009-03-04 09:39:40
测试表:

IF EXISTS (SELECT name FROM sysobjects
WHERE name = '库存表')
DROP Table 库存表
GO
IF EXISTS (SELECT name FROM sysobjects
WHERE name = '入库')
DROP Table 入库
GO
IF EXISTS (SELECT name FROM sysobjects
WHERE name = '发料')
DROP Table 发料
GO
IF EXISTS (SELECT name FROM sysobjects
WHERE name = '退料')
DROP Table 退料
GO
IF EXISTS (SELECT name FROM sysobjects
WHERE name = '报废')
DROP Table 报废
GO

create table 基础表
(ID varchar(10),MType varchar(15),Unit varchar(10))
insert into 基础表 select 'M01','CAP','K'
insert into 基础表 select 'M02','RES','PCS'

create table 库存表
(ID varchar(10),Qty numeric(15,4))--Qty 为结存量
insert into 库存表 select 'M01',20
insert into 库存表 select 'M02',1500

create table 入库
(ID varchar(10),Qty numeric(15,4),date1 datetime)
insert into 入库 select 'M01',1.5, '2008-5-15'
insert into 入库 select 'M01',5.5, '2008-5-15'
insert into 入库 select 'M01',2.5, '2008-5-16'
insert into 入库 select 'M02',500, '2008-5-15'
insert into 入库 select 'M01',5.5, '2008-8-05'
insert into 入库 select 'M02',2500, '2008-5-05'

create table 发料
(ID varchar(10),Qty numeric(15,4),date1 datetime)
insert into 发料 select 'M01',2.5,'2008-6-10'
insert into 发料 select 'M01',1 ,'2008-5-15'
insert into 发料 select 'M02',1500, '2008-6-10'

create table 退料
(ID varchar(10),Qty numeric(15,4),date1 datetime)
insert into 退料 select 'M01',0.22 ,'2008-5-15'
insert into 退料 select 'M01',0.05 ,'2008-7-15'
insert into 退料 select 'M02',50 ,'2008-6-15'

create table 报废
(ID varchar(10),Qty numeric(15,4),date1 datetime)
insert into 报废 select 'M01',0.05, '2008-7-20'
insert into 报废 select 'M01',0.12, '2008-5-15'
insert into 报废 select 'M02',20, '2008-7-20'



SQL问题语句(如果日期相同,就有重复记录):


select A.ID AS 物料编码, 库存表.Qty 初存,入库.Qty AS 入库, 发料.Qty AS 发料,退料.Qty AS 退料,报废.Qty AS 报废,A.date1 日期,库存表.Qty 结存
INTO #TEMP
from(
select ID, date1 from 入库
union
select ID, date1 from 发料
union
select ID, date1 from 退料
union
select ID, date1 from 报废
union
select ID ,NULL FROM 库存表)A
LEFT JOIN 入库 ON A.ID=入库.ID and A.date1=入库.date1
LEFT JOIN 发料 ON A.ID=发料.ID and A.date1=发料.date1
LEFT JOIN 退料 ON A.ID=退料.ID and A.date1=退料.date1
LEFT JOIN 报废 ON A.ID=报废.ID and A.date1=报废.date1
LEFT JOIN 库存表 ON A.ID=库存表.ID
order by A.ID,A.date1 ASC


但如果进行汇总,其中重复数据就翻倍了:

select A.ID AS 物料编码, 库存表.Qty 初存,SUM(入库.Qty) AS 入库, SUM(发料.Qty)AS 发料,SUM(退料.Qty)AS 退料,SUM(报废.Qty)AS 报废,A.date1 日期,库存表.Qty 结存
INTO #TEMP
from(
select ID, date1 from 入库
union
select ID, date1 from 发料
union
select ID, date1 from 退料
union
select ID, date1 from 报废
union
select ID ,NULL FROM 库存表)A
LEFT JOIN 入库 ON A.ID=入库.ID and A.date1=入库.date1
LEFT JOIN 发料 ON A.ID=发料.ID and A.date1=发料.date1
LEFT JOIN 退料 ON A.ID=退料.ID and A.date1=退料.date1
LEFT JOIN 报废 ON A.ID=报废.ID and A.date1=报废.date1
LEFT JOIN 库存表 ON A.ID=库存表.ID
group by A.ID,库存表.Qty,A.date1
order by A.ID,A.date1 ASC

declare @InNum numeric(15,4) ,@InitNum numeric(15,4) ,@物料编码 varchar(10),@入库 numeric(15,4),@初存 numeric(15,4),
@发料 numeric(15,4),@退料 numeric(15,4),@报废 numeric(15,4),@结存 numeric(15,4),@日期 datetime,@D datetime

Declare My_cur Cursor
for
Select 物料编码,初存,入库, 发料,退料,报废 ,结存,日期 from #TEMP
SET @InNum=0
SET @InitNum=0
SET @D = NULL

Open My_cur
Fetch Next From My_cur
Into @物料编码,@初存,@入库,@发料,@退料,@报废,@结存,@日期
While(@@Fetch_Status=0)
begin
update #TEMP Set 初存 = CASE WHEN @D IS NULL THEN 结存 ELSE @InitNum END ,结存=isnull(@InNum,0)+ISNULL(@入库,0)-ISNULL(@发料,0)+ISNULL(@退料,0)-ISNULL(@报废,0)+isnull(@结存,0)
where 物料编码=@物料编码 AND 日期=@日期 and 日期 is not null
Select @InitNum = 结存 From #TEMP Where 物料编码=@物料编码 AND 日期=@日期 and 日期 is not null
Select @InNum=isnull(@InNum,0)+ISNULL(@入库,0)-ISNULL(@发料,0)+ISNULL(@退料,0)-ISNULL(@报废,0)
Select @D=@日期

Fetch Next From My_cur Into @物料编码,@初存,@入库,@发料,@退料,@报废,@结存,@日期
end
Close My_cur
Deallocate My_cur

SELECT * FROM #TEMP

drop table #TEMP


其中M01的"退料","报废"实际是0.22 和 0.12 ,由于有两行数据,结果成了0.44 和 0.24了
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xjwangbb 2009-03-04
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有点不知所云 你到底想要什么样的结果
hrb2008 2009-03-04
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想了半天好像就想到一种办法。
select

(select Qty from 库存表 where 库存表.id=a.id) as 初存 ,
(select SUM(入库.Qty) from 入库 where 入库.id=a.id and a.date1 = 入库.date1) AS 入库,
(select SUM(发料.Qty) from 发料 where 发料.id=a.id and a.date1 = 发料.date1) AS 发料,
(select SUM(退料.Qty) from 退料 where 退料.id=a.id and a.date1 = 退料.date1) AS 退料,
(select SUM(报废.Qty) from 报废 where 报废.id=a.id and a.date1 = 报废.date1) AS 报废,
A.date1 日期
-- 结存这应该有个算术计算吧
from
(
select ID, date1 from 入库
union
select ID, date1 from 发料
union
select ID, date1 from 退料
union
select ID, date1 from 报废
union
select ID ,NULL FROM 库存表)A
zzxap 2009-03-04
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链接的表有重复的数据就会出现这样的问题的,要保证链接表的行唯一
快乐_石头 2009-03-04
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--参考
--处理表重复记录(查询和删除)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)

日期:2008.06.06
******************************************************************************************************************************************************/

--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)

--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go


--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)

方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID

方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)

方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1

方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)

方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0

方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)

方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)

方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)

--SQL2005:

方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID

方法11:

select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1

生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1

(2 行受影响)
*/


--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)

方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID

方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID

方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1

方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)

方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0

方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)

方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)

方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)

--SQL2005:

方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID

方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1

生成结果2:
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2

(2 行受影响)
*/



--2、删除重复记录有大小关系时,保留大或小其中一个记录


--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go

--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条
方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID<a.ID)

方法2:
delete a from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null

方法3:
delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)

方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select min(ID)from #T group by Name)

方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0

方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)

方法7:
delete a from #T a where ID>any(select ID from #T where Name=a.Name)



select * from #T

生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1

(2 行受影响)
*/


--II、Name相同ID保留最大的一条记录:

方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID>a.ID)

方法2:
delete a from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null

方法3:
delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)

方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select max(ID)from #T group by Name)

方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0

方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)

方法7:
delete a from #T a where ID<any(select ID from #T where Name=a.Name)


select * from #T
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2

(2 行受影响)
*/





--3、删除重复记录没有大小关系时,处理重复值


--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([Num] int,[Name] nvarchar(1))
Insert #T
select 1,N'A' union all
select 1,N'A' union all
select 1,N'A' union all
select 2,N'B' union all
select 2,N'B'
Go

方法1:
if object_id('Tempdb..#') is not null
drop table #
Select distinct * into # from #T--排除重复记录结果集生成临时表#

truncate table #T--清空表

insert #T select * from # --把临时表#插入到表#T中

--查看结果
select * from #T

/*
Num Name
----------- ----
1 A
2 B

(2 行受影响)
*/

--重新执行测试数据后用方法2
方法2:

alter table #T add ID int identity--新增标识列
go
delete a from #T a where exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录
go
alter table #T drop column ID--删除标识列

--查看结果
select * from #T

/*
Num Name
----------- ----
1 A
2 B

(2 行受影响)

*/

--重新执行测试数据后用方法3
方法3:
declare Roy_Cursor cursor local for
select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1
declare @con int,@Num int,@Name nvarchar(1)
open Roy_Cursor
fetch next from Roy_Cursor into @con,@Num,@Name
while @@Fetch_status=0
begin
set rowcount @con;
delete #T where Num=@Num and Name=@Name
set rowcount 0;
fetch next from Roy_Cursor into @con,@Num,@Name
end
close Roy_Cursor
deallocate Roy_Cursor

--查看结果
select * from #T
/*
Num Name
----------- ----
1 A
2 B

(2 行受影响)
*/
dawugui 2009-03-04
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又是这么多表?友情帮顶.晚上有空慢慢看,
3tzjq 2009-03-04
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不好意思!上楼的图片放反了,下面那张才是"没汇总...数量的结果(有重复值)"
3tzjq 2009-03-04
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这里没汇总...数量的结果(有重复值):


这是汇总...数量的结果(数值翻倍):


此SQL该怎么改,才使不出现重复记录已正确汇总呢?

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