10000条记录求第70到80

[tjmfj]

问一个sql，各位大侠不要笑我弱。
表A（char(20) NAME, int NO）,里面有10000条记录。其中，NAME表示人的名字，NO表示每个人的会员号，每个人各不相同。
要求写一个SQL语句，实现输出会员号第70位到第80位的人的情况。
谢谢。

[htl258_Tony]

select top 10 * from (select top 80 * from a order by no desc) t order by no

[htl258_Tony]

 select top 10 * from (select top 80 * from a order by no desc) t order by no

[ChinaJiaBing]

select * from 表 where 会员号 between 70 and 80

[百年树人]

取n到m行

1. 
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 

2. 
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 
set rowcount n   --只取n条结果
select * from 表变量 order by columnname desc 

3. 
select top n * from  
(select top m * from tablename order by columnname) a 
order by columnname desc 


4.如果tablename里没有其他identity列，那么： 
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 

取n到m条的语句为： 
select * from #temp where id0 > =n and id0  <= m 

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行： 
exec sp_dboption 你的DB名字,'select into/bulkcopy',true 


5.如果表里有identity属性，那么简单： 
select * from tablename where identity_col between n and m  

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
 select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

[SQLnewlearner]

select top 10 * from a where no not in (select top 69 no from a order by no ) order by no

[ChinaJiaBing]

select * from
(select row_number()over (order by 会员号) id ,* from 表) A where id between 70 and 80

[sdhdy]

--如果没有标识字段的话

alter table 表A add id1 int identity(1,1)
select * from 表A where id1 between 70 and 80
alter table 表A drop column id1

[Rotel-刘志东]

 select top 10 * from (select top 80 * from a order by no desc) t order by no

[liudeqing2008]

五楼的最好了！