Unable to compile class for JSP 错误什么原因,怎么解决

Ghosthuo 2009-03-11 08:19:36
总是报这个错误:


org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 9 in the jsp file: /userlist1.jsp

Generated servlet error:
[javac] Compiling 1 source file

C:\Program Files\Apache Software Foundation\Tomcat 6.0\work\Catalina\localhost\Second\org\apache\jsp\userlist1_jsp.java:7: 软件包 model 不存在
import model.User;
^
C:\Program Files\Apache Software Foundation\Tomcat 6.0\work\Catalina\localhost\Second\org\apache\jsp\userlist1_jsp.java:54: 找不到符号
符号: 类 User
位置: 类 org.apache.jsp.userlist1_jsp
List<User> ul =(List<User>) request.getAttribute("userlist");





jsp页代码:


<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%@ page import="model.User"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>UserList.jsp</title>
</head>
<%
List<User> ul =(List<User>) request.getAttribute("userlist");
%>
<body>
<table> 
<%
if(ul.isEmpty()){
Iterator userlist = ul.iterator();
wahile(userlist.hasNext()){
User user = (User)userlist.next();
%>
<tr><td>用户ID:</td><td><%=user.getUid()%></td></tr>
<tr><td>用户名:</td><td><%=user.getUname()%></td></tr>
<%
}
}
%>
</table>
</body>
</html>




action 代码


public ActionForward jumptouserlist(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {

List<User> ul = this.userbusinessimp.getUserList();
request.setAttribute("userlist", ul);
return mapping.findForward("userlist");
}


...全文
319 15 打赏 收藏 转发到动态 举报
AI 作业
写回复
用AI写文章
15 条回复
切换为时间正序
请发表友善的回复…
发表回复
hwy000 2009-03-12
  • 打赏
  • 举报
回复
把发布目录下的work下的jsp文件删除,重新发布编译.做JAVA的WEB很容易出现容器的JSP没有更新这种情况
Ghosthuo 2009-03-12
  • 打赏
  • 举报
回复
楼上的能说清楚些吗
Ghosthuo 2009-03-12
  • 打赏
  • 举报
回复
楼上说的那种情况确实是有可能,



不等了,,结帐吧,,,
susoft2008 2009-03-11
  • 打赏
  • 举报
回复
设置 自动编译。。。。
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
可以了,,
重装了一下tomcat 后不出错了,,
具体是怎么回事还没有弄清楚。。。

再等等。。。看看有没有什么好的解释,,,,
pearskill 2009-03-11
  • 打赏
  • 举报
回复
检查tomcat/webapps中的你应用下的web-inf/classes/model中有没有User.class
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
我调试过,到达userlist1.jsp之前没有发生错误,也能取到正取的数据

可一到页面就会发生错误。。

如果页面是一个空页(即不导入什么包),也可以正常运行。。。
Sou2012 2009-03-11
  • 打赏
  • 举报
回复
类没有
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
包名是model没有错呀,
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
<%@ page import="model.User"%>
不是导入包了吗
blueram 2009-03-11
  • 打赏
  • 举报
回复
C:\Program Files\Apache Software Foundation\Tomcat 6.0\work\Catalina\localhost\Second\org\apache\jsp\userlist1_jsp.java:7: 软件包 model 不存在
import model.User;
^

问题不就在这吗,看看你包名
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
web.xml 代码


<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>3</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>3</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>


彩虹咖啡 2009-03-11
  • 打赏
  • 举报
回复
它在userlist1.jsp 这个页面中没有找到你的model
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
applicationContext.xml


<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">


<bean id="dataSource"
class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName"
value="com.mysql.jdbc.Driver">
</property>
<property name="url"
value="jdbc:mysql://localhost:3306/jobtest">
</property>
<property name="username" value="root"></property>
<property name="password" value="root"></property>
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource"></ref>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">
org.hibernate.dialect.MySQLDialect
</prop>
</props>
</property>
<property name="mappingResources">
<list>
<value>model/Admin.hbm.xml</value>
<value>model/User.hbm.xml</value></list>
</property>
</bean>

<bean id="userDAOImp" class="daoimp.UserDAOImp">
<property name="sessionFactory">
<ref bean="sessionFactory"/>
</property>
</bean>

<bean id="userBusinessImp" class="businessimp.UserBusinessImp">
<property name="userdaoimp">
<ref bean="userDAOImp"/>
</property>
</bean>

<bean name="/login" class="struts.action.LoginAction">
<property name="userbusinessimp">
<ref bean="userBusinessImp"/>
</property>
</bean>
<bean name="/jumptouserlist" class="struts.action.UserAction">
<property name="userbusinessimp">
<ref bean="userBusinessImp"/>
</property>
</bean>
</beans>
Ghosthuo 2009-03-11
  • 打赏
  • 举报
回复
struts-config.xml 代码


<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN" "http://struts.apache.org/dtds/struts-config_1_2.dtd">

<struts-config>
<data-sources />
<form-beans >
<form-bean name="loginForm" type="org.apache.struts.validator.DynaValidatorActionForm">
<form-property name="username" type="java.lang.String" />
<form-property name="password" type="java.lang.String" />
</form-bean>
<form-bean name="userForm" type="org.apache.struts.validator.DynaValidatorActionForm">
<form-property name="uid" type="java.lang.Integer" />
<form-property name="username" type="java.lang.String" />
<form-property name="password" type="java.lang.String" />
</form-bean>

</form-beans>

<global-exceptions />
<global-forwards />
<action-mappings >
<action
attribute="loginForm"
name="loginForm"
parameter="login"
path="/login"
scope="request"
validate="false"
type="org.springframework.web.struts.DelegatingActionProxy" />

<action
parameter="jumptouserlist"
path="/jumptouserlist"
scope="request"
type="org.springframework.web.struts.DelegatingActionProxy">
<forward name="userlist" path="/userlist1.jsp"></forward>
</action>

</action-mappings>

<message-resources parameter="struts.ApplicationResources" />


<plug-in className="org.springframework.web.struts.ContextLoaderPlugIn">
<set-property property="contextConfigLocation" value="/WEB-INF/applicationContext.xml"/>
</plug-in>
</struts-config>


81,122

社区成员

发帖
与我相关
我的任务
社区描述
Java Web 开发
社区管理员
  • Web 开发社区
加入社区
  • 近7日
  • 近30日
  • 至今
社区公告
暂无公告

试试用AI创作助手写篇文章吧