xml的选择读取

andy20022 2009-03-19 06:08:18

<?xml version="1.0" standalone="yes"?>
<message>
<city id="1" title="湖南">
<name key="11" value="长沙"/>
<name key="12" value="珠洲"/>
</city>
<city id="2" title="广东">
<name key="21" value="深圳"/>
<name key="22" value="广州"/>
</city>
</message>
我绑定city到dropdownlist了，我想根据dropdownlist选择的值把name绑定到dropdownlist2
如何做？

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wuyq11 2009-03-20

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http://www.cnblogs.com/AntiGameZ/archive/2007/03/21/607512.html

CutBug 2009-03-19

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protected void DropDownList1_SelectedIndexChanged(object sender, EventArgs e)

    {

        XmlDocument xmlDoc = new XmlDocument();

        xmlDoc.LoadXml(@"<?xml version=""1.0"" standalone=""yes""?> 

                <message> 

                  <city id=""1"" title=""湖南""> 

                    <name key=""11"" value=""长沙""/> 

                    <name key=""12"" value=""珠洲""/> 

                  </city> 

                  <city id=""2"" title=""广东""> 

                    <name key=""21"" value=""深圳""/> 

                    <name key=""22"" value=""广州""/> 

                  </city> 

                </message> ");

        XmlNodeList list = xmlDoc.SelectNodes("//city[@id='" + "2" + "']/name");

        foreach (XmlNode node in list)

        {

            DropDownList2.Items.Add(new ListItem(node.Attributes["value"].Value, node.Attributes["key"].Value));

        }

    }