关于cout的一个疑问

[一个人单干]

对于字符类型以外的数组与指针，使用cout输出的是地址，但对于字符数组与字符指针，用cout输出的是字符串。

这是为什么？谁能用cout的函数原型解释一下

[一个人单干]

发重了 大家去这个帖子吧 双倍给分
http://topic.csdn.net/u/20090331/19/06090f08-e662-4e40-8306-fe4f3863a1ef.html

[Paradin]

操作符重载
库定义的行为

basic_ostream& operator<< (bool& val );
basic_ostream& operator<< (short& val );
basic_ostream& operator<< (unsigned short& val );
basic_ostream& operator<< (int& val );
basic_ostream& operator<< (unsigned int& val );
basic_ostream& operator<< (long& val );
basic_ostream& operator<< (unsigned long& val );
basic_ostream& operator<< (float& val );
basic_ostream& operator<< (double& val );
basic_ostream& operator<< (long double& val );
basic_ostream& operator<< (void*& val );
basic_ostream& operator<< (basic_streambuf<charT,traits>* sb );
basic_ostream& operator<< (basic_ostream& ( *pf )(istream&));
basic_ostream& operator<< (basic_ios<charT,traits>& ( *pf )(basic_ios<charT,traits>&));
basic_ostream& operator<< (ios_base& ( *pf )(ios_base&));


template <class charT, class traits>
basic_ostream<charT,traits>& operator<< (basic_ostream<charT,traits>& os, charT ch );

template <class charT, class traits>
basic_ostream<charT,traits>& operator<< (basic_ostream<charT,traits>& os, char ch );

template <class charT, class traits>
basic_ostream<charT,traits>& operator<< (basic_ostream<charT,traits>& os, const charT* str );

template <class charT, class traits>
basic_ostream<charT,traits>& operator<< (basic_ostream<charT,traits>& os, const char* str );

// template specializations:

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, char ch );

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, signed char ch );

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, unsigned char ch );

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, const char* str );

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, const signed char* str );

template <class traits>
basic_ostream<char,traits>& operator<< (basic_ostream<char,traits>& os, const unsigned char* str );

[yangqidong]

cout不是函数，是一个预定义的对象
对输出起作用的实际是<<符号的重载函数，这个函数接受很多种类型参数，建议看看运算符重载

[ydntlk]

cout是ostream的类对象。ostream是一个类模板。
ostream重载了操作符<<，可以输出字符串。

[liliangbao]

cout原型不知，但是我理解是：
cout输出字符数组与字符指针就是输出字符串，可能是和传统的c输出函数统一吧！毕竟C++是C的升级版~

[mengde007]

cout是iostream类的一个对象，它的一个成员operator<<运用了重载机制，因此能承受多种类型