关于cout的一个疑问

[一个人单干]

对于字符类型以外的数组与指针，使用cout输出的是地址，但对于字符数组与字符指针，用cout输出的是字符串。

这是为什么？谁能用cout的函数原型解释一下

[oyljerry]

cout中输出的时候做了字符串处理

[Paradin]

因为输出流类重载了operator<<,对各种类型有自定义的操作。

ostream& operator<< (bool& val );
ostream& operator<< (short& val );
ostream& operator<< (unsigned short& val );
ostream& operator<< (int& val );
ostream& operator<< (unsigned int& val );
ostream& operator<< (long& val );
ostream& operator<< (unsigned long& val );
ostream& operator<< (float& val );
ostream& operator<< (double& val );
ostream& operator<< (long double& val );
ostream& operator<< (void*& val );

ostream& operator<< (streambuf* sb );

ostream& operator<< (ostream& ( *pf )(ostream&));
ostream& operator<< (ios& ( *pf )(ios&));
ostream& operator<< (ios_base& ( *pf )(ios_base&));

*** the following functions are not members but GLOBAL functions:

ostream& operator<< (ostream& out, char c );
ostream& operator<< (ostream& out, signed char c );
ostream& operator<< (ostream& out, unsigned char c );

ostream& operator<< (ostream& out, const char* s );
ostream& operator<< (ostream& out, const signed char* s );
ostream& operator<< (ostream& out, const unsigned char* s );

[yangqidong]

cout不是函数，是一个预定义的对象
对输出起作用的实际是 < <符号的重载函数，这个函数接受很多种类型参数，建议看看运算符重载

[liliangbao]

cout原型不知，但是我理解是：
cout输出字符数组与字符指针就是输出字符串，可能是和传统的c输出函数统一吧！毕竟C++是C的升级版~

[mengde007]

cout是iostream类的一个对象，它的一个成员operator < <运用了重载机制，因此能承受多种类型

[leewon1988]

2L正解

[ypb362148418]

看看STL源码里面的ios和iostream的声明与里面的函数重载

[CJoneL]

操作符重载问题