time()函的问题

[熊猫过隙]

IDE:VC++6.0

#include<iostream.h>
#include<time.h>

int seqsearch(int a[],int n,int x)
{
	int i = 0;
	
	while (i<n && a[i]!=x)
	{
		i++;
	}
	if (i==n) return -1;
}

main()
{
	int a[10] = {12,23,52,75,48,25,36,29,65,47};
	int i,k;
	double start,stop;


 
    time(&start);
	k = seqsearch(a,10,65);
    time(&stop);
	double runTime = stop -start;

	cout << " "<< 10 << " " << runTime << endl;

	for(i=0; i<10; i++)
	{
		cout << a[i] << " ";
	}
	cout << endl;

	return 0;
}

调试信息
--------------------Configuration: SeqSearch - Win32 Debug--------------------
Compiling...
SeqSearcg.cpp
D:\alexa\VC\SeqSearch\SeqSearcg.cpp(23) : error C2664: 'time' : cannot convert parameter 1 from 'double *' to 'long *'
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
D:\alexa\VC\SeqSearch\SeqSearcg.cpp(25) : error C2664: 'time' : cannot convert parameter 1 from 'double *' to 'long *'
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
执行 cl.exe 时出错.

SeqSearch.exe - 1 error(s), 0 warning(s)


多谢!

[帅得不敢出门]

double start,stop;

改成long

[donle1000]

LZ是不是要表达这个意思?

#include<iostream.h>
#include<time.h>

int seqsearch(int a[],int n,int x)
{
    int i = 0;
    
    while (i<n && a[i]!=x)
    {
        i++;
    }
    if (i==n) return -1;
}

main()
{
    int a[10] = {12,23,52,75,48,25,36,29,65,47};
    int i,k;
    clock_t start,stop;

	
	
    start = clock();
    k = seqsearch(a,10,65);
    stop = clock();
    clock_t runTime = stop -start;
	
    cout << " "<< 10 << " " << runTime << endl;
	
    for(i=0; i<10; i++)
    {
        cout << a[i] << " ";
    }
    cout << endl;
	
    return 0;
}

[帅得不敢出门]

一般用time_t

[帅得不敢出门]

time_t time(
time_t *timer
);

[ylywyn136]

[Quote=引用 1 楼 zmlovelx 的回复:]
double start,stop;

改成long
[/Quote]..

[liliangbao]

[Quote=引用 2 楼 donle1000 的回复:]
LZ是不是要表达这个意思?


C/C++ code
#include<iostream.h>
#include<time.h>

int seqsearch(int a[],int n,int x)
{
int i = 0;

while (i<n && a[i]!=x)
{
i++;
}
if (i==n) return -1;
}

main()
{
int a[10] = {12,23,52,75,48,25,36,29,65,47};
int i,k;
clock_t start,stop;



start = clock();
k = seqsearch(a,10,65);
…
[/Quote]
正解~
time_t time(long *tloc); 因此参数使用错了~

[mengde007]

调试信息很清楚……

[熊猫过隙]

试过改成long.
虽然没有错误了能运行程序了.
但是结果是0,显然不对.

二楼的改法,运行的结果和你建议的改法的结果是一样的.

[old-six-programmer]

因为time返回返回从公元1970年1月1日的UTC时间从0时0分0秒算起到现在所经过的秒数
显然时间粒度太大

可以使用gettimeofday
可以精确到微妙

[Quote=引用 8 楼 xhz_panda 的回复:]
试过改成long.
虽然没有错误了能运行程序了.
但是结果是0,显然不对.

二楼的改法,运行的结果和你建议的改法的结果是一样的.
[/Quote]

[猫已经找不回了]

直接用time_t来声明就可以了。