关于C中的拆分字符串

[huntian8]

请问一个字符串“abc/def@111” 如果把他拆分成 3部分放到3个变量中
“abc” "def" "111"
最好写出全部过程，感激不尽

[ltc_mouse]

试试strtok或者sprintf

char a[]="abc/def@111";
char b[8], c[8], d[8];
sprintf(a, "%[^/]/%[^@]@%s", b, c, d);

[morris88]

char str[]="abc/def@111"; 
char *a, *b, *c;

a = str;
b = strok(a, '\/');
*b = 0;
++b;
c = strok(b, '\@');
*c = 0;
++c;

// a, b, c 

[morris88]

char str[]="abc/def@111"; 
char *a, *b, *c;

a = str;
b = strtok(a, '\/');
c = strtok(b, '\@');

[mengde007]

#include<string> 
#include <iostream> 
using namespace std; 
int main() 
{ 

	char a[]="abc/def@111";
	char b[3][6]={0};
	int m=0;
	int i=0;
	int j=0;
	while(a[m]!='\0')
	{
		if(a[m]!='/'&&a[m]!='@')
		{
			b[i][j]=a[m];
			m++;
			j++;
		}
		else
		{	
			i++;
			m++;
			j=0;
		}
	}
	for(i=0;i<3;i++)
		for(j=0;j<6;j++)
		{
			cout<<b[i][j];
		}
return 0; 
}

[猫已经找不回了]

万能的sscanf

int main() 
{ 
	char str[]="abc/def@111";
	char s1[5],s2[5],s3[5];
	sscanf(str,"%[^/]/%[^@]@%s",s1,s2,s3);
	cout<<s1<<endl;
	cout<<s2<<endl;
	cout<<s3<<endl;
}     

[ltc_mouse]

lz忽略我2楼说的sprintf吧，错了~
应该是sscanf，如7楼所示

[ylywyn136]

char a[]="abc/def@111";
char b[3],c[3],d[3];
int i=0;
int j=0;
while(a[i]!= '\0')
{
if(i<3)
..
else if[a<6]
..
}

[huntian8]

要根据/ 和@拆分。。。。。啊