循环赋值

[onlylovedotnet]

for (int i = 0; i < table.Columns.Count - 10; i++)
{
this.dgv.Rows[rowNum].Cells[i].Value = rows[0][i]+s;
this.dgv.Rows[rowNum].Cells[i+1].Value = rows[0][i+1]+s;
}


table是一个datatable,table.Columns.Count 始终是偶数，比如count-10=18,那么i=0;i+1=1,当下次循环时，i=2;i+1=3,再下次i=4;i+1=5.
以此类推，但是i+1不能超过18
这个应该怎样实现，谢谢。

[我姓区不姓区]

for (int i = 0; i < table.Columns.Count - 10; i+=2)
{
this.dgv.Rows[rowNum].Cells[i].Value = rows[0][i]+s;
this.dgv.Rows[rowNum].Cells[i+1].Value = rows[0][i+1]+s;
}

[teerhu]

[Quote=引用 1 楼 ojlovecd 的回复:]
for (int i = 0; i < table.Columns.Count - 10; i+=2)
{
this.dgv.Rows[rowNum].Cells[i].Value = rows[0][i]+s;
this.dgv.Rows[rowNum].Cells[i+1].Value = rows[0][i+1]+s;
}
[/Quote]
支持

[bing300]

[Quote=引用 1 楼 ojlovecd 的回复:]
for (int i = 0; i < table.Columns.Count - 10; i+=2)
{
this.dgv.Rows[rowNum].Cells[i].Value = rows[0][i]+s;
this.dgv.Rows[rowNum].Cells[i+1].Value = rows[0][i+1]+s;
}
[/Quote]


OK!

[readfuture]

[Quote=引用 1 楼 ojlovecd 的回复:]
for (int i = 0; i < table.Columns.Count - 10; i+=2)
{
this.dgv.Rows[rowNum].Cells[i].Value = rows[0][i]+s;
this.dgv.Rows[rowNum].Cells[i+1].Value = rows[0][i+1]+s;
}
[/Quote]
正解