求助,xsd解析xml问题
用java解析xml时老是报错, 程序走到parser.setProperty(SCHEMA_SOURCE, xsdfile); 这一句时报以下错误:如下:
org.xml.sax.SAXNotRecognizedException: http://java.sun.com/xml/jaxp/properties/schemaSource
at org.apache.xerces.framework.XMLParser.setProperty(XMLParser.java:1682)
at org.apache.xerces.parsers.SAXParser.setProperty(SAXParser.java:770)
at org.apache.xerces.jaxp.SAXParserImpl.setProperty(SAXParserImpl.java:183)
at com.hr.basic.TestXml.validatexmlbyxsd(TestXml.java:45)
at com.hr.basic.TestXml.main(TestXml.java:63)
false
java程序为:
package com.hr.basic;
import java.io.File;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.ErrorHandler;
import org.xml.sax.XMLReader;
import org.xml.sax.helpers.DefaultHandler;
public class TestXml {
/**
* 使用xsd验证xml
*
* @param xmlfilename
* String xml文件 包括路径
* @param xsdfilename
* String xsd文件 包括路径
* @param validatesuccess
* boolean 是否验证成功 成功返回true,
* @return boolean 成功返回true 失败返回false
*/
public boolean validatexmlbyxsd(String xmlfilename, String xsdfilename,
boolean validatesuccess) {
File xmlfile = new File("e:\\standard\\NewFile.xml");
File xsdfile = new File("e:\\standard\\IntegrationXMLSchemazh.xsd");
File xsdfile2 = new File("e:\\standard\\Symbolizer.xsd");
// 检测原文件和验证文件是否存在
if (!((xmlfile.exists()) && (xsdfile.exists())))
return false;
final String SCHEMA_LANGUAGE = "http://java.sun.com/xml/jaxp/properties/schemaLanguage";
final String XML_SCHEMA = "http://www.w3.org/2001/XMLSchema";
final String SCHEMA_SOURCE = "http://java.sun.com/xml/jaxp/properties/schemaSource";
SAXParserFactory factory = SAXParserFactory.newInstance();
factory.setNamespaceAware(true);
factory.setValidating(true);
try {
SAXParser parser = factory.newSAXParser();
parser.setProperty(SCHEMA_SOURCE, xsdfile);
parser.setProperty(SCHEMA_LANGUAGE, XML_SCHEMA);
// parser.setProperty(SCHEMA_SOURCE, xsdfile2);
XMLReader xmlReader = parser.getXMLReader();
xmlReader.setContentHandler(new DefaultHandler());
//xmlReader.setErrorHandler(new ErrorHandler(System.out));
//xmlReader.parse("file:/D:/test/xml/test4.xml");
xmlReader.parse("file:/D:/standard/xml/NewFile.xml");
validatesuccess = true;
} catch (Exception ex) {
ex.printStackTrace();
validatesuccess = false;
}
return validatesuccess;
}
public static void main(String[] args) {
boolean b = new TestXml().validatexmlbyxsd("test4.xml", "test4.xsd",
false);
System.out.println(b);
}
}