程序改错603

[lingang1]

下面的程序含有二义性,要求不修改主程序,通过重定义成员函数Show的方法解决名字冲突.
#include <iostream.h>
class Base1{
protected:
int m;
public:
void Show(){cout<<m<<endl;}
};
class Base2{
protected:
int n;
public:
void Show(){cout<<n<<endl;}
};
class Derived:public Base1,public Base2{
public:
void Set(int x,int y){m=x;n=y;}
};

void main(){
Derived Obj;
Obj.Set(45,87);
Obj.Show();
Obj.Base1::Show();
Obj.Base2::Show();
}

[ericming200409]

顶

[milosz]

#include <iostream.h> 
class Base1{ 
protected: 
    int m;
public: 
    void Show(){cout<<m<<endl;} 
}; 

class Base2{ 
protected: 
    int n; 
public: 
    void Show(){cout<<n<<endl;} 
}; 

class Derived:public Base1,public Base2{ 
public: 
	void Set(int x,int y){m=x;n=y;}
	void Show(){cout<<cout<<m<<"\n"<<n<<endl;}  //重定义
}; 

void main(){ 
Derived Obj; 
Obj.Set(45,87); 
Obj.Show();
Obj.Base1::Show(); 
Obj.Base2::Show(); 
}

[liubuweiright]

学习....

[酣眠]

挺好的。应该就是这个。