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分享--只为了方便代码写作,而且该命令不会经常执行,所以对语句的复杂程度不考虑SELECT tableA.sname, B.Total
FROM tableA INNER JOIN
(SELECT sid, SUM(fen) AS Total
FROM TableB
GROUP BY sid) B ON tableA.sid = B.sid
SELECT a.Sname,b.Total
FROM TableA
INNER JOIN
(
SELECT sid,SUM(fen) as Total
FROM TableB
) B
ON a.sid=b.sID