用友员函数除去字符

[woshi420]

就是说把a里面含有b字符串里面的字符除掉
我写了个 不过不行 帮我改下 谢谢
#include<iostream.h>
#include<string.h>
class string
{
public:
string(char *m);
~string();
display();
friend operator -(string,string);
private:
char *str;
};
string::isplay()
{
cout<<str<<endl;
}
string::string(char* m)
{
str=new char[strlen(m)+1];
strcpy(str,m);
}
string::~string()
{
delete []str;
}
operator -(string a,string b)
{
for(int m=0;*((b.str)[m])!='\0';m++)
for(int n=0;*((a.str)[n])!='\0';n++)
if(*((a.str)[n])==*((b.str)[m]))
for(int i=n;*((a.str)[i])!='\0';i++)
*((a.str)[i])=*((a.str)[i+1]);
return 0;
}
int main()
{
string a("wokao"),b("ka");
a-b;
a.display();
return 0;
}

[donle1000]

标准库有个string都不用....

#include <iostream> 
#include <cstring>
using namespace std;
 
class Sstring 
{ 
public: 
	Sstring(char *m); 
	~Sstring(); 
	void display(); 
	friend Sstring &operator -(Sstring &,Sstring &); 
private: 
	char *str; 
}; 
void Sstring::display() 
{ 
	cout <<str <<endl; 
} 
Sstring::Sstring(char* m) 
{ 
	str=new char[strlen(m)+1]; 
    strcpy(str,m); 
} 
Sstring::~Sstring() 
{ 
	delete []str; 
} 
Sstring &operator -(Sstring &a,Sstring &b) 
{ 
	for(int m=0;b.str[m]!='\0';m++) 
		for(int n=0;a.str[n]!='\0';n++) 
			if(a.str[n]==b.str[m])
				for(int i=n;a.str[i]!='\0';i++) 
					a.str[i]=a.str[i+1]; 
				return a; 
} 
int main() 
{ 
	Sstring a("wokao"),b("ka"); 
	a-b; 
	a.display(); 
	return 0; 
} 

[woshi420]

谢谢了