图片旋转！！

[aaaa3105563]

有一个图片 在屏幕中间显示 想让这个图片沿着顺时针一秒的旋转 这么弄···求教··

[lambochan]

easy job..

[zzz822163]

http://www.51log.net/dev/5010/5017325.htm

[zxfone]

so easy。。
使用CxImage类库，先加载图片，然后调用CxImage：：Rotate（）方法，随便你调什么角度，代码量不超过10行。。

[lucklizhan]

根据坐标来做旋转变换，再插值！

http://game.chinaitlab.com/devdoc/720850.html

[flm007]

如果你只旋转90°那么GDI+很简单就可以实现了！！
如果你要任意角旋转，那就要计算旋转圆心，坐标，还要保持足够大旋转空间不然会变形

[leechrockgames]

//2D图rotate/move/scale

void scr_rotate(LHxx2DIMAGE *sc,float angle,float scale)
{
	float dx,dy,dw,dh;//临时变量
	float sw = sc->LHxxIw;//image width
	float sh = sc->LHxxIh;//image height 
	float sclx,scly,sclw,sclh;//复位并放缩的坐标（局部坐标系－－image的坐标系）
	
	float hotx =sw/2;//旋转中心
	float hoty =sh/2;
	//复位  放缩 ， 旋转  ，平移

    float xscale=scale;
	float yscale=scale;

	

	//复位并放缩后的区域
	sclx = -hotx*scale;
	scly = -hoty*scale;


	sclw = (sw - hotx);
	sclh = (sh - hoty);

	float sint, cost;
	sint = sinf(angle);
	cost = cosf(angle);

	float w=sc->LHxxIw/2,h=sc->LHxxIh/2;

	LHxxSCREENVERTEX* ss;
    sc->LHxx2DMVertexBuffer->Lock( 0, 0, (void**)&ss, 0 );

	((LHxxSCREENVERTEX *)ss)[0].LHxxSx = sclx*cost - scly*sint + sc->LHxxIx+w;
	((LHxxSCREENVERTEX *)ss)[0].LHxxSy = sclx*sint + scly*cost + sc->LHxxIy+h;	

	((LHxxSCREENVERTEX *)ss)[1].LHxxSx = sclw*cost - scly*sint + sc->LHxxIx+w;
	((LHxxSCREENVERTEX *)ss)[1].LHxxSy = sclw*sint + scly*cost + sc->LHxxIy+h;	

	((LHxxSCREENVERTEX *)ss)[2].LHxxSx = sclx*cost - sclh*sint + sc->LHxxIx+w;
	((LHxxSCREENVERTEX *)ss)[2].LHxxSy = sclx*sint + sclh*cost + sc->LHxxIy+h;	

	((LHxxSCREENVERTEX *)ss)[3].LHxxSx = sclw*cost - sclh*sint + sc->LHxxIx+w;
	((LHxxSCREENVERTEX *)ss)[3].LHxxSy = sclw*sint + sclh*cost + sc->LHxxIy+h;


    sc->LHxx2DMVertexBuffer->Unlock();
}

[my5123]

GDI+
SetTransform(Matrix*)
或
RotateAt(...)