在Xml中指定标签中取内容

[zhouxingyu896]

简单的Xml文件如下
<?xml version="1.0" encoding="gbk"?>
<root>
<introduce>总体语音系统规划文档</introduce>
<currentPart>在线</currentPart>

</root>
现在知道Xml中有<currentPart>这个标签,就指定这个标签,然后取出内容
怎么完成？
高手指教！
谢谢

[ericzhangbo1982111]

XmlDocument doc = new XmlDocument("");
doc.GetElementById("currentPart")

[zhouxingyu896]

要在不知道这个标签的情况下,怎么判断Xml文件有没有这个标签？

[A海阔天空]

 /// <summary>
    /// 获取指定节点的值
    /// </summary>
    /// <param name="strXmlFile">XML文件</param>
    /// <param name="strSelectNodes">节点的Xpath</param>
    /// <param name="strSelectSingleNode">要获取的改节点名称</param>
    /// <returns>ArrayList</returns>
    public ArrayList GetSpecifyNodeValue(String strXmlFile, String strSelectNodes, String strSelectSingleNode)
    {
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.Load(strXmlFile);
        ArrayList al = new ArrayList();
        XmlNodeList xmlNL = xmlDoc.SelectNodes(strSelectNodes);
        foreach (System.Xml.XmlNode xmlN in xmlNL)
        {
            XmlElement xe = (XmlElement)xmlN.SelectSingleNode(strSelectSingleNode);
            al.Add(xe.InnerText);
        }
        return al;
    }


    /// <summary>
    /// 获取指定节点的属性
    /// </summary>
    /// <param name="strXmlFile">XML文件</param>
    /// <param name="strSelectNodes">节点的Xpath</param>
    /// <param name="strSelectSingleNode">要获取的改节点名称</param>
    /// <param name="strAttribute">要获取的改节点的属性名称</param>
    /// <returns>ArrayList</returns>
    public ArrayList GetSpecifyNodeAttribute(String strXmlFile, String strSelectNodes, String strSelectSingleNode, String strAttribute)
    {
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.Load(strXmlFile);
        ArrayList al = new ArrayList();
        XmlNodeList xmlNL = xmlDoc.SelectNodes(strSelectNodes);
        foreach (System.Xml.XmlNode xmlN in xmlNL)
        {
            XmlElement xe = (XmlElement)xmlN.SelectSingleNode(strSelectSingleNode);
            al.Add(xe.GetAttribute(strAttribute));
        }
        return al;
    }

[zyang198811]

string path = @"F:\Project\SX2005\12ha_activity\lrbug\ipXML\UploadCount.xml";
DataSet dsCount = new DataSet();
dsCount.ReadXml(path);
string value=dsCount.Tables[0].rows[0]["currentPart"].ToString();
//注value就是你要的值

[danier9687]

路人甲