取出数字数组中不重复出项的项

[a5385987]

如（1，3，3，4，5，4） 应该得到1，5

[jingsong2008]

if (str.compareTo(""))
str.Remove()

[Garnett_KG]

// Linq

            int[] ary = new int[] { 1, 3, 3, 4, 5, 4 };

            var q = from x in ary
                    group x by x into Y
                    where Y.Count() == 1
                    select Y.Key;

            foreach (var t in q)
            {
                Console.WriteLine(t);
            }

[LemIST]

ArrayList al = new ArrayList();
        al.AddRange(new int[] { 7, 2, 8, 2, 3, 4, 2, 5, 6 });
        al.Sort();
        for (int i = 0; i < al.Count; i++)
        {
            int j = i + 1;
            for (; j < al.Count && al[j].Equals(al[i]); j++) ;
            if (j - i > 1)
                al.RemoveRange(i--, j);
        }
        foreach (int i in al)
            Console.WriteLine(i);

[yafeya]

// 去除所有重复的,显示1,3,4,5
private static int[] GetIntArrayWithoutRepeat(int[] paraArray)
        {
            ArrayList result = new ArrayList();
            bool repeat = false;
            for (int i = 0; i < paraArray.Length; i++)
            {
                for (int j = i + 1; j < paraArray.Length; j++)
                {
                    if (paraArray[j] == paraArray[i])
                    {
                        repeat = true;
                    }
                }
                if(!repeat)
                {
                    result.Add(paraArray[i]);
                }
                repeat = false;
            }
            return (int[])result.ToArray(typeof(int));
        }

剔除所有重复的,显示1,5

private static int[] GetNoRepeat(int[] paraArray)
        {
            int repeattimes = 0;
            ArrayList result = new ArrayList();
            for (int i = 0; i < paraArray.Length; i++)
            {
                for (int j = paraArray.Length - 1; j >= 0; j--)
                {
                    if (paraArray[i] == paraArray[j])
                    {
                        repeattimes++;
                    }
                }
                if (repeattimes == 1)
                {
                    result.Add(paraArray[i]);
                }
                repeattimes = 0;
            }
            return (int[])result.ToArray(typeof(int));
        }

[ljhcy99]

ArrayList list= new ArrayList();
int [] data = {1，3，3，4，5，4};
if(data.length >0)
list.Add(data[0].ToString());
foreach(int i in data)
{
if(!list.contains(i.tostring()))
{
list.Add(i.toString());
}
}

list 里面就是不重复数据

[xv8844]

[Quote=引用 5 楼 ljhcy99 的回复:]
ArrayList list= new ArrayList();
int [] data = {1，3，3，4，5，4};
if(data.length >0)
list.Add(data[0].ToString());
foreach(int i in data)
{
if(!list.contains(i.tostring()))
{
list.Add(i.toString());
}
}

list 里面就是不重复数据
[/Quote]

C#经验交流群6624014期待您的加入，共同学习共同进步

[clark523]

试试下面的代码，它的耗时是2N

string[] str=new string[]{"1","2","5","5","3","4","7","7","9"}
List<string> list=new List<string>();
foreach(string temp in str)
{
 list.add(temp);
}
Dictionary<string,int> dString=new Dictionary<string,int>();
foreach(string temp in list)
{
 if(dString.containKey(temp))
 {
  dString[temp]++;
 }else
 {
  dString.add(temp,0);
 }
}
for(int i=list.count-1;i--;i>=0)
{
 string temp=list[i];
 if(dString[temp]>1)
 {
   list.remove(i);
 }
}

这段代码运行后，list中剩下的就是楼主你想要的数据了

[wenjie0728]

[Quote=引用 5 楼 ljhcy99 的回复:]
ArrayList list= new ArrayList();
int [] data = {1，3，3，4，5，4};
if(data.length >0)
list.Add(data[0].ToString());
foreach(int i in data)
{
if(!list.contains(i.tostring()))
{
list.Add(i.toString());
}
}

list 里面就是不重复数据
[/Quote]
这样不对 这样list里的值是：49 51 52 53

如下是值放在ArrayList 中：
System.Collections.ArrayList dd = new System.Collections.ArrayList();
System.Collections.ArrayList aa = new System.Collections.ArrayList();
dd.Add(1);
dd.Add(3);
dd.Add(3);
dd.Add(4);
dd.Add(5);
dd.Add(4);
dd.Add(9);
for (int i = 0; i < dd.Count; i++)
{
if (dd.LastIndexOf(dd[i]) == dd.IndexOf(dd[i])) //判断位置
{
aa.Add(dd[i]);
}
else
continue;
}
结果是:1 5 9