这样的链表如何删除元素

[悟迟]

class CData
{
public:
	CData() {m_nData = rand();};
	~CData() {};
	int m_nDelete;
	int  m_nData;
};
typedef list<CData*> lCData;
typedef list<CData*>::iterator liCData;
typedef list<CData*>::const_iterator lciCData;
lCData g_data;
int _tmain(int argc, _TCHAR* argv[])
{
    int i = 0;
	CData* pNewClass = NULL;
	liCData pData;
	for (i=0; i<10; i++)
	{
		pNewClass = new CData();
		pNewClass->m_nDelete = i % 2;
		g_data.push_back(pNewClass);
	}

	//  请问，如何删除m_nDelete = 0的元素？
}

[liliangbao]

帮顶~

[猫已经找不回了]

访问CData::m_nDelete 数据，为0，则删除之。并delete掉。

[yayafu]

循环叠代链表元素,判断m_Delete==0就g_data.erase(it),然后delete *it

[maosher]

for (liCData iter = g_data.begin(); iter != g_data.end(); ++iter)
{
if (0 == (*iter)->m_nData)
{
g_data.erase(iter);
}
}