如何查询出一个公司各个部门中工资最高的两个人

[yulu380393306]

--如何找出一个公司各个部门中工资最高的两个人？
--TB_Dept(部门表) 有Dept_id,Dept_name,employee_id
--TB_Employee(雇员表) 　有 employee_id,employee_name,Dept_id
--TB_pay(工资表) employee_id,pay(工资)

[InsistOnDoing]

比较支持Josy的做法。
提个问题，TB_PAY是不是可以直接合并到TB_Employee(雇员表)中,然后TB_Dept(部门表) employee_id不能有这个字段。
select *
from TB_Employee as a
where employee_id in(
select top 2 employee_id
from TB_Employee as b,TB_Pay as c
where a.Dept_id =b.Dept_id
and b.employee_id=c.employee_id
order by c.pay desc
)

[yulu380393306]

大家的做法都有问题,但回帖，也非常感谢

[htl258_Tony]

---------------------------------
--  Author: liangCK 小梁
--  Title : 查每个分组前N条记录
--  Date  : 2008-11-13 17:19:23
---------------------------------

--> 生成测试数据: #T
IF OBJECT_ID('tempdb.dbo.#T') IS NOT NULL DROP TABLE #T
CREATE TABLE #T (ID VARCHAR(3),GID INT,Author VARCHAR(29),Title VARCHAR(39),Date DATETIME)
INSERT INTO #T
SELECT '001',1,'邹建','深入浅出SQLServer2005开发管理与应用实例','2008-05-10' UNION ALL
SELECT '002',1,'胡百敬','SQLServer2005性能调校','2008-03-22' UNION ALL
SELECT '003',1,'格罗夫Groff.J.R.','SQL完全手册','2009-07-01' UNION ALL
SELECT '004',1,'KalenDelaney','SQLServer2005技术内幕存储引擎','2008-08-01' UNION ALL
SELECT '005',2,'Alex.Kriegel.Boris.M.Trukhnov','SQL宝典','2007-10-05' UNION ALL
SELECT '006',2,'飞思科技产品研发中心','SQLServer2000高级管理与开发','2007-09-10' UNION ALL
SELECT '007',2,'胡百敬','SQLServer2005数据库开发详解','2008-06-15' UNION ALL
SELECT '008',3,'陈浩奎','SQLServer2000存储过程与XML编程','2005-09-01' UNION ALL
SELECT '009',3,'赵松涛','SQLServer2005系统管理实录','2008-10-01' UNION ALL
SELECT '010',3,'黄占涛','SQL技术手册','2006-01-01'

--SQL查询如下:

--按GID分组,查每个分组中Date最新的前2条记录


--1.字段ID唯一时:
SELECT * FROM #T AS T WHERE ID IN(SELECT TOP 2 ID FROM #T WHERE GID=T.GID ORDER BY Date DESC)

--2.如果ID不唯一时:
SELECT * FROM #T AS T WHERE 2>(SELECT COUNT(*) FROM #T WHERE GID=T.GID AND Date>T.Date)

--SQL Server 2005 使用新方法

--3.使用ROW_NUMBER()进行排位分组
SELECT ID,GID,Author,Title,Date
FROM
(
   SELECT rid=ROW_NUMBER() OVER(PARTITION BY GID ORDER BY Date DESC),*
   FROM #T
) AS T
WHERE rid<=2

--4.使用APPLY
SELECT DISTINCT b.*
FROM #T AS a
CROSS APPLY
(
    SELECT TOP(2) * FROM #T WHERE a.GID=GID ORDER BY Date DESC
) AS b


--结果
/*

ID   GID         Author                        Title                                   Date
---- ----------- ----------------------------- --------------------------------------- -----------------------
003  1           格罗夫Groff.J.R.                 SQL完全手册                                 2009-07-01 00:00:00.000
004  1           KalenDelaney                  SQLServer2005技术内幕存储引擎                   2008-08-01 00:00:00.000
005  2           Alex.Kriegel.Boris.M.Trukhnov SQL宝典                                   2007-10-05 00:00:00.000
007  2           胡百敬                           SQLServer2005数据库开发详解                    2008-06-15 00:00:00.000
009  3           赵松涛                           SQLServer2005系统管理实录                     2008-10-01 00:00:00.000
010  3           黄占涛                           SQL技术手册                                 2006-01-01 00:00:00.000

(6 行受影响)
*/

[-晴天]

tb_dept表中不该有employee_id

[百年树人]

[Quote=引用楼主 yulu380393306 的帖子:]
--如何找出一个公司各个部门中工资最高的两个人？
--TB_Dept(部门表) 有Dept_id,Dept_name,employee_id
--TB_Employee(雇员表) 　有 employee_id,employee_name,Dept_id
--TB_pay(工资表) employee_id,pay(工资)
[/Quote]

select 
  *
from
  TB_Employee a
where
  employee_id 
in(select top 2 employee_id 
   from (select a.dept_id,c.employee_id,c.pay from TB_Dept a,TB_Pay c where a.employee_id=b.employee_id) t 
   where dept_id=a.dept_id order by pay desc
   )

[-晴天]

create table TB_Dept(Dept_id int,Dept_name nvarchar(10))
create table TB_Employee(employee_id int,employee_name nvarchar(10),Dept_id int)
create table TB_pay(employee_id int,pay money)
go
select c.Dept_name,a.pay
 from tb_pay a inner join tb_employee b on a.employee_id=b.employee_id
 inner join tb_dept c on b.dept_id=c.dept_id
 where a.employee_id in(
select top 2 t1.employee_id from tb_pay t1 inner join tb_employee t2 on t1.employee_id=t2.employee_id
 where t2.dept_id=c.dept_id order by t1.pay)
go
drop table tb_dept,tb_employee,tb_pay