图片旋转90度

2009-05-09 10:33:58 163 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

java 90度旋转图片 import org.slf4j.Logger; import org.slf4j.LoggerFactory; import javax.imageio.*; import java.awt.image.BufferedImage; import java.io.File; public class ImageUtils { private static Logger LOGGER = LoggerFactory.getLogger(ImageUtils.class); /** . 阅读详情

我写的代码是：
dim d_Image As Image
d_Image = Bitmap.FromFile("C:\Documents and Settings\All Users\Documents\My Pictures\示例图片\aaa.JPG")
Dim NewImage As Bitmap = New Bitmap(d_Image.Height, d_Image.Width)
Dim G As Graphics
G = Graphics.FromImage(NewImage)
G.TranslateTransform(d_Image.Height, 0)
G.RotateTransform(90)
G.DrawImage(d_Image, 0, 0, d_Image.Height, d_Image.Width)

这样得到的图在NewImage，可是现在有个问题，就是在原来的图片d_Image在旋转的时候，因为宽度比高度要大，所以在转成９０度后，宽度就被截成了和高度一样的，请问有什么办法解决，或有别的方法实现这个旋转

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【数字图像处理第四版课后习题答案】第2章数字图像基础（含英文原版）如图 P2.3 所示，视网膜图像中与点相对应的直径 x 是由类似的三角形得到的。即得出 x = 0.085d。根据第 2.1 节中的讨论，并结合一些自由解释，我们可以将眼窝视为一个方形传感器阵列，拥有大约 337,000 个元素，这相当于一个大约 580×580 个元素的阵列。假设元素间距相等，则在 1.5 毫米长的直线上有 580 个元素和 579 个空间，共计 1,159 个。换句话说，如果一个点的直径 d＜1.3×10-6 m，或者 d＜15.3×10 m，眼睛就无法检测到这个点。阅读详情

wzckr

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切换为时间正序

bw555 2009-05-09

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转完再缩放下就好了



    Private Sub Form1_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles Me.Paint

        Dim d_Image As Image

        d_Image = Bitmap.FromFile("C:\Documents and Settings\All Users\Documents\My Pictures\示例图片\Sunset.jpg")

        Dim NewImage As New Bitmap(d_Image.Width, d_Image.Height)

        Dim G As Graphics

        G = Graphics.FromImage(NewImage)

        G.TranslateTransform(d_Image.Width, 0)

        G.RotateTransform(90)

        G.DrawImage(d_Image, 0, 0, d_Image.Height, d_Image.Width)

        Dim NewImage1 As New Bitmap(d_Image.Height, d_Image.Width)

        G = Graphics.FromImage(NewImage1)

        G.DrawImage(NewImage, 0, 0, d_Image.Height, d_Image.Width)

        e.Graphics.DrawImage(NewImage1, 0, 0)

    End Sub

bw555 2009-05-09

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    Private Sub Form1_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles Me.Paint

        Dim d_Image As Image

        d_Image = Bitmap.FromFile("C:\Documents and Settings\All Users\Documents\My Pictures\示例图片\Sunset.jpg")

        Dim NewImage As New Bitmap(d_Image.Width, d_Image.Height)

        Dim G As Graphics

        G = Graphics.FromImage(NewImage)

        G.DrawRectangle(Pens.Black, 0, 0, NewImage.Width, NewImage.Height)

        G.TranslateTransform(d_Image.Width, 0)

        G.RotateTransform(90)

        G.DrawImage(d_Image, 0, 0, d_Image.Height, d_Image.Width)

        e.Graphics.DrawImage(NewImage, 0, 0, 300, 400)

    End Sub

[Quote=引用楼主 wzckr 的帖子:]
我写的代码是：
dim d_Image As Image
d_Image = Bitmap.FromFile("C:\Documents and Settings\All Users\Documents\My Pictures\示例图片\aaa.JPG")
Dim NewImage As Bitmap = New Bitmap(d_Image.Height, d_Image.Width)
Dim G As Graphics
G = Graphics.FromImage(NewImage)
G.TranslateTransform(d_Image.Height, 0)
G.RotateTransform(90)
G.DrawImage(d_Image, 0, 0, d_Image.Height, d_Image.Width)

…
[/Quote]

zgke 2009-05-09

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G.DrawImage(d_Image, 0, 0, d_Image.Height, d_Image.Width) ;这不对把.

你画旋转了90 绘制的时候还是绘制正的

G.DrawImage(d_Image, 0, 0, d_Image.Width, d_Image.Height) ;

图片旋转90度

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