一个hashmap页面显示问题（在线等）

[caoyi1201]

有两个数据库，一个是订单Orders，一个是订单项表Orderitems

action里面数据
LinkedHashMap<List<Orders>,List<Orderitems>> map = new LinkedHashMap<List<Orders>,List<Orderitems>>();
List<Orders> l=odd.findOrder(u.getUsersId());
for(int i=0;i<l.size();i++){

List<Orderitems> l1=odd.findOrderitems(l.get(i).getOrdersId());
map.put(l, l1);
}
request.setAttribute("showorder", map);
return mapping.findForward("suss");


两个方法，肯定对，已测
public List findOrder(final Long userId) {
try{

result=(List)this.getHibernateTemplate().execute( new HibernateCallback(){
public Object doInHibernate(Session s) throws HibernateException,SQLException{
DateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");



Date dd = new Date();
java.sql.Date d = new java.sql.Date(dd.getTime());

Calendar c=Calendar.getInstance();
c.setTime(d);
int month=c.get(Calendar.MONTH)-1;
log.info("month------------"+month);
log.info("Calendar.MONTH----------------"+c.get(Calendar.MONTH));
log.info("YEAR--------------"+c.get(Calendar.YEAR));
c.set(c.get(Calendar.YEAR), month,c.get(Calendar.DAY_OF_MONTH));
String d0=sdf.format(c.getTime());
Date d1=java.sql.Date.valueOf(d0);

c.setTime(d);
int day=c.get(Calendar.DAY_OF_MONTH)+1;
log.info("day------------"+day);
log.info("Calendar.MONTH----------------"+c.get(Calendar.MONTH));
log.info("YEAR--------------"+c.get(Calendar.YEAR));
c.set(c.get(Calendar.YEAR),c.get(Calendar.MONTH),day);
String d2=sdf.format(c.getTime());
Date d3=java.sql.Date.valueOf(d2);

log.info("d1--------------------"+d1);
log.info("d---------------------"+d);
log.info("d2---------------------"+d2);
log.info("d3---------------------"+d3);
Query q = s
.createQuery("from Orders o where o.users.usersId=? and o.createtime >=? and o.createtime <=? order by o.createtime desc");


q.setLong(0, userId);
q.setDate(1, d1);
q.setDate(2, d3);
return q.list();

}

});
}catch (RuntimeException re) {

throw re;
}
return result;

}


public List findOrderitems(final Long ordersId) {
try{

result=(List)this.getHibernateTemplate().execute( new HibernateCallback(){
public Object doInHibernate(Session s) throws HibernateException,SQLException{
Query q = s
.createQuery("from Orderitems oi where oi.orders.ordersId=?");
q.setLong(0, ordersId);
return q.list();

}

});
}catch (RuntimeException re) {

throw re;
}
return result;

}

页面
<logic:notEmpty name="showorder">
<logic:iterate id="o" name="showorder" indexId="i">

<DIV class=Box-Center>
<TABLE>
<TBODY>
<TR>
<TD class=OrderInfo>
<LI>
<EM>订单时间：</EM>
<fmt:formatDate value="${o.key.createtime}" type="both" />
<LI>
<EM>订 单 号：</EM>#${o.key.ordersId }
<LI>
<EM>收 货 人：</EM>${o.key.address.username}
</LI>
</TD>
<TD class=OrderDetail>
<LI>
<EM>商品：</EM>
<logic:iterate id="oi" name="o"
property="value" indexId="i">
<LI class=Detail>
${oi.product.productname}
</LI>
</logic:iterate>

</TD>
<TD class=OrderOption>
<A href=""><IMG border=0 alt=查看订单
src="image/az-want-to-view-orders.gif"> </A>
</TD>
</TR>
</TBODY>
</TABLE>
</DIV>


</logic:iterate>
</logic:notEmpty>


问一下，为什么这种ER表达式无法显示，有什么错误吗？

还有LinkedHashMap有自己的key排序吗？因为我两个都是数组。。

或者各位大大能提供更好的方法，谢谢

[caoyi1201]

<logic:notEmpty name="showorder">
<logic:iterate id="o" name="showorder" indexId="i">
<DIV class=Box-Center>
<TABLE>
<TBODY>
<TR>
<TD class=OrderInfo>
<LI>
<EM>订单时间：</EM>
<fmt:formatDate value="${o.key[i].createtime}" type="both" />
<LI>
<EM>订 单 号：</EM>${i}---#${o.key[i].ordersId }
<LI>
<EM>收 货 人：</EM>${o.key[i].address.username}
</LI>
</TD>
<TD class=OrderDetail>
<LI>
<EM>商品：</EM>
<logic:iterate id="oi" name="o" property="value" indexId="i">
<LI class=Detail>
${oi.product.productname}
</logic:iterate>
</LI>

</TD>
<TD class=OrderOption>
<A href=""><IMG border=0 alt=查看订单
src="image/az-want-to-view-orders.gif"> </A>
</TD>
</TR>
</TBODY>
</TABLE>
</DIV>


</logic:iterate>
</logic:notEmpty>




换成这样是出来了，但是他没有循环，不知什么缘故，打入o.key[0].ordersId 和o.key[1].ordersId是两个不同的值，能取到

[caoyi1201]

<logic:notEmpty name="showorder">
<logic:iterate id="o" name="showorder" indexId="i">
<DIV class=Box-Center>
<TABLE>
<TBODY>
<TR>
<TD class=OrderInfo>
<LI>
<EM>订单时间：</EM>
<fmt:formatDate value="${o.key.createtime}" type="both" />
<LI>
<EM>订 单 号：</EM>${i}---#${o.key.ordersId }
<LI>
<EM>收 货 人：</EM>${o.key.address.username}
</LI>
</TD>
<TD class=OrderDetail>
<LI>
<EM>商品：</EM>
<logic:iterate id="oi" name="o" property="value" indexId="i">
<LI class=Detail>
${oi.product.productname}
</logic:iterate>
</LI>

</TD>
<TD class=OrderOption>
<A href=""><IMG border=0 alt=查看订单
src="image/az-want-to-view-orders.gif"> </A>
</TD>
</TR>
</TBODY>
</TABLE>
</DIV>


</logic:iterate>
</logic:notEmpty>



action里改成map.put(l.get(i), l1);

就好了