字符串拆分问题

[dpzc_love]

USE TEMPDB
GO
--建表
IF OBJECT_ID('ARRAYS','U') IS NOT NULL
DROP TABLE ARRAYS
GO
CREATE TABLE ARRAYS
(ARRAYID VARCHAR(10) NOT NULL,ARRAYVALUE VARCHAR(100) NOT NULL)
GO
INSERT INTO ARRAYS
SELECT 'A','20,22,25,25,14' UNION ALL
SELECT 'B','30,33,28' UNION ALL
SELECT 'C','12,10,8,12,12,13,12,14,10,9' UNION ALL
SELECT 'D','-4,-5,-6,-4,-2'
GO
--需要得到的结果
ARRAYID	ELEMENT
A	20
A	22
A	25
A	25
A	14
B	30
B	33
B	28
C	12
C	10
C	8
C	12
C	12
C	13
C	12
C	14
C	10
D	-4
D	-5
D	-6
D	-4
D	-2

请不要用存储过程,函数,游标.各位牛牛.怎么写这个SQL?

[dpzc_love]

自己先顶一下

[快乐_石头]

--合并分拆表
/******************************************************************************************************************************************************
合并分拆表数据

整理人：中国风(Roy)

日期:2008.06.06
******************************************************************************************************************************************************/

--> --> (Roy)生成測試數據
 
if not object_id('Tab') is null
    drop table Tab
Go
Create table Tab([Col1] int,[Col2] nvarchar(1))
Insert Tab
select 1,N'a' union all
select 1,N'b' union all
select 1,N'c' union all
select 2,N'd' union all
select 2,N'e' union all
select 3,N'f'
Go

合并表:

SQL2000用函数:

go
if object_id('F_Str') is not null
    drop function F_Str
go
create function F_Str(@Col1 int)
returns nvarchar(100)
as
begin
    declare @S nvarchar(100)
    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1
    return @S
end
go
Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab

go

SQL2005用XML:

方法1:

select 
    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')
from 
    (select distinct COl1 from Tab) a
Cross apply
    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b

方法2:

select 
    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))
from 
    (select distinct COl1 from Tab) a
cross apply
    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)
                .query('<Tab>
                {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}
                {concat("",string(/Tab[last()]/@COl2))}
                </Tab>')
                )b

SQL05用CTE:

;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
,Roy2 as
(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 
union all 
select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)


生成结果:
/*
Col1        COl2
----------- ------------
1           a,b,c
2           d,e
3           f

(3 行受影响)
*/


拆分表:

--> --> (Roy)生成測試數據
 
if not object_id('Tab') is null
    drop table Tab
Go
Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
Go

SQL2000用辅助表:
if object_id('Tempdb..#Num') is not null
    drop table #Num
go
select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select 
    a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) 
from 
    Tab a,#Num b
where
    charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','


SQL2005用Xml:

select 
    a.COl1,b.Col2
from 
    (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
    (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b




SQL05用CTE:

;with roy as 
(select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
)
select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)

生成结果:
/*
Col1        COl2
----------- -----
1           a
1           b
1           c
2           d
2           e
3           f
*/

[liangCK]

SELECT
    A.ARRAYID,
    SUBSTRING(A.ARRAYVALUE,B.number,CHARINDEX(',',A.ARRAYVALUE+',',B.number)-B.number) AS ARRAYVALUE
FROM ARRAYS AS A
    JOIN master.dbo.spt_values AS B
ON B.type='p'
    AND B.number BETWEEN 1 AND LEN(A.ARRAYVALUE)
    AND SUBSTRING(','+A.ARRAYVALUE,B.number,1)=',';

[liangCK]

USE TEMPDB
GO
--建表
IF OBJECT_ID('ARRAYS','U') IS NOT NULL
DROP TABLE ARRAYS
GO
CREATE TABLE ARRAYS
(ARRAYID VARCHAR(10) NOT NULL,ARRAYVALUE VARCHAR(100) NOT NULL)
GO
INSERT INTO ARRAYS
SELECT 'A','20,22,25,25,14' UNION ALL
SELECT 'B','30,33,28' UNION ALL
SELECT 'C','12,10,8,12,12,13,12,14,10,9' UNION ALL
SELECT 'D','-4,-5,-6,-4,-2'
GO

SELECT
    A.ARRAYID,
    SUBSTRING(A.ARRAYVALUE,B.number,CHARINDEX(',',A.ARRAYVALUE+',',B.number)-B.number) AS ARRAYVALUE
FROM ARRAYS AS A
    JOIN master.dbo.spt_values AS B
ON B.type='p'
    AND B.number BETWEEN 1 AND LEN(A.ARRAYVALUE)
    AND SUBSTRING(','+A.ARRAYVALUE,B.number,1)=',';

DROP TABLE ARRAYS;

/*
ARRAYID    ARRAYVALUE
---------- ----------------------------------------------------------------------------------------------------
A          20
A          22
A          25
A          25
A          14
B          30
B          33
B          28
C          12
C          10
C          8
C          12
C          12
C          13
C          12
C          14
C          10
C          9
D          -4
D          -5
D          -6
D          -4
D          -2

(23 row(s) affected)


*/

[--小F--]

眼睛都看花了 学习下

[ai_li7758521]

分拆列值 

原著：邹建 
改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)  2007-12-16  广东深圳 

有表tb, 如下: 
id          value 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
欲按id,分拆value列, 分拆后结果如下: 
id          value 
----------- -------- 
1          aa 
1          bb 
2          aaa 
2          bbb 
2          ccc 

1. 旧的解决方法(sql server 2000) 
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b 

SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id) 
FROM tb A, # B 
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ',' 

DROP TABLE # 

2. 新的解决方法(sql server 2005) 

create table tb(id int,value varchar(30)) 
insert into tb values(1,'aa,bb') 
insert into tb values(2,'aaa,bbb,ccc') 
go 
SELECT A.id, B.value 
FROM( 
    SELECT id, [value] = CONVERT(xml,' <root> <v>' + REPLACE([value], ',', ' </v> <v>') + ' </v> </root>') FROM tb 
)A 
OUTER APPLY( 
    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v) 
)B 

DROP TABLE tb 

/* 
id          value 
----------- ------------------------------ 
1          aa 
1          bb 
2          aaa 
2          bbb 
2          ccc 

(5 行受影响) 
*/

[dpzc_love]

呵呵.赞!结贴