在程序中执行exe文件后怎么得到exe 文件的输出

[李V四]

比如exe 文件的功能为

int main
{
count<<"ok\n";
return 1;
}
我在另外的程序中调用它
WinExec("文件名"，SW_SHOW)我怎么得到前面的输出结果
我试了
WinExec("文件名 >> 1.txt",SW_SHOW);不行
直接在dos下运行 文件名 >> 1.txt则可以

[zhaoloudy]

朋友，参考下面的：

去看看msdn中consoles[win32]中的console screen buffers 以及console functions 部分。
你可以把console程序的输出用SetStdHandle()重定向到另一个Handle中去


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http://codeguru.earthweb.com/misc/redirect.shtml
You can specify a console for console application so that it doesn't create a new console as it runs. Related API:AllocConsole, CreateProcess.
Or you can redirect their output to somewhere else in order to solve your problem. Hope the following links are useful to you.
http://codeguru.earthweb.com/console/QuickWin.shtml
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http://vip.6to23.com/NowCan1/tech/pipe.htm
看这个绝对满足要求。

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[In355Hz]

MSDN 里查找 "Creating a Child Process with Redirected Input and Output"