sql查询问题！！想取到第a条与第b条中间的（包括a）的所有数据，怎么写？？？

[iceman09]

sql查询问题！！想取到第a条与第b条中间的（包括a）的所有数据，怎么写？？？
（a<b）a,b是从外面传进来的整形变量。

[psxfghost]

select * from (select identity(1,1) as id,top b * from table) a where a.id not in(select identity(1,1) as id top a id from table)

[CrazyFor]

查询N-M条记录。
select IDENTITY(int,1,1) as iid,* into #temptable from yourtable
select top M-N * from #temptable where iid>=N

OR:

select top M-N * from yourTable where id not in(select top N-1 id from table)
ID为表具有唯一值的任何字段

[yoki]

方法一：取出前n条和前m条然后取出其差(n-m)
select top(n-m) *
from table
where 关键字段 not in(select top m 关键字段 from table)

方法二：先取出前n条的,再倒过来取出n-m就可以
select top(n-m+1) *
from (select top n * from table order by 关键字段 desc)
order by 关键字段

[psxfghost]

更正:
select * from (select identity(1,1) as id,top b * from table) a where a.id not in(select b.id from (select identity(1,1) as id, top a * from table) as b)

或者
select identity(1,1) as id, * into #temp from table
select * from #temp where id>=a and id<=b

[19191919]

select top b-a * from yourTable where id not in(select top a-1 id from table)
ID为表具有唯一值的任何字段或任何字段的组合
同时注意top 后面不支持参数，如果含参数执行要用exec
exec('select top '+@b-@a 的变量 +' * from yourTable where id not in(select top' + @a-1 的变量+' id from table)'
)
如果没有唯一值，按照蚂蚁的就可以了