看看我的!
name text2_2
data segment
s db 5 dup(?)
data ends
code segment
assume cs:code,ds:data
start:mov ax,data
mov ds,ax
mov cx,5
mov si,4 ;现赋值5,使其指向第五个字节
loop1:mov ah,01h
int 21h
mov s[si],al
dec si
loop loop1 ;循环输入5个数,从高字节si=4起保存,到低字节si=0结束!
mov cx,5
mov si,0
loop2:mov dl,s[si]
mov ah,2
int 21h
inc si
loop loop2 ;从si=0,到si=4顺序输出!
mov ah,4ch
int 21h
code ends
end start