有关TreeView中节点的问题，谢谢

[zengjun1980]

向TreeView 添加子节点只能这样吗：
treMain.Nodes.Add(myNode) ‘这是根节点
treMain.Nodes(0).Nodes.Add(myNode1) ‘这是子节点
treMain.Nodes(0).Nodes(0).Nodes.Add(myNode1) ‘这是子子节点

可不可在定义myNode1的时候提定父节点是myNode后就同样用treMain.Nodes.Add(myNode1)来添加

[terryxin]

是啊，用递归吧。是个好方法

[zengjun1980]

很急呀，各位幫幫驚忙吧!謝謝了，閏該給分!!

[hepp]

递归是个好方法。。。

[sinbalionking]

试过了吗？
应该可以的吧

[snowjin78]

下面的例子经过本人调试成功。 数据库的表结构是cur_id,par_id,f_name.其中：所有的根结点的par_id为-1；而且所有的字段均为VARCHAR2类型。
Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
'在此处放置初始化页的用户代码
If Not IsPostBack Then
intiTree(TreeView2.Nodes, "-1")
End If
End Sub

Private Sub intiTree(ByRef Nds As TreeNodeCollection, ByVal parentId As String)
Dim sql As String = "select * from xj.treeview where par_id='" + parentId + "'"
Dim myDataAdapter As New OleDbDataAdapter(sql, con)
Dim ds As New DataSet()
myDataAdapter.Fill(ds, "tree")
Dim mydatable As DataTable
mydatable = ds.Tables("tree")
If mydatable.Rows.Count = 0 Then
Exit Sub
End If
Dim drv As DataRowView
Dim tmpNd As TreeNode
For Each drv In mydatable.DefaultView
tmpNd = New TreeNode()
Dim strid As String
strid = drv("CUR_ID")
tmpNd.ID = strid
tmpNd.Text = drv("F_NAME")
Nds.Add(tmpNd)
intiTree(tmpNd.Nodes, strid)
Next
End Sub

[erictang2003]

好烦,到处都是VB.NET
最近C#少了点!