关于弹出式菜单的设计，遇到的困难？请解决，有分送.

[islyb5001]

我想设计一个弹出式菜单，包括有“操作”，“退出”，其中“操作”选项还是一个弹出式类型菜单（popup menu）包括有竖分，横分。两个选项。我的程序是这样的：

CXPMenu t_Menu;
t_Menu.CreatePopupMenu();

t_ItemInfo[0].sText = "操作(&N)\tCtrl + O";
t_ItemInfo[0].uIdNormal = IDI_ICON1;
t_ItemInfo[0].uIdSelect = IDI_ICON2;
t_Menu.AppendMenu(MF_OWNERDRAW, 0, (LPCTSTR)(&(t_ItemInfo[0])));

t_ItemInfo[1].sText = "退出(&O)\tCtrl + Q";
t_ItemInfo[1].uIdNormal = IDI_ICON3;
t_ItemInfo[1].uIdSelect = IDI_ICON4;
t_Menu.AppendMenu(MF_OWNERDRAW, 1, (LPCTSTR)(&(t_ItemInfo[1])));


我的问题是，我如何用appendmenu来修改第一个操作选项为popup类型，并且如何添加它的选项竖分，横分？其它的可以请朋友不要看。谢谢回答。

[ukyoking]

see here

http://expert.csdn.net/Expert/topic/1874/1874707.xml?temp=.1426355

[feiniaoliang]

先加入！！
CXPMenu t_PopMenu;
t_PopMenu.CreatePopupMenu();

t_ItemInfo[0].sText = "竖分";
t_ItemInfo[0].uIdNormal = IDI_ICON1;
t_ItemInfo[0].uIdSelect = IDI_ICON2;
t_PopMenu.AppendMenu(MF_OWNERDRAW, 0, (LPCTSTR)(&(t_ItemInfo[0])));

t_ItemInfo[1].sText = "横分";
t_ItemInfo[1].uIdNormal = IDI_ICON3;
t_ItemInfo[1].uIdSelect = IDI_ICON4;
t_PopMenu.AppendMenu(MF_OWNERDRAW, 1, (LPCTSTR)(&(t_ItemInfo[1])));

然后t_Menu.AppendMenu(MF_OWNERDRAW, 0, (LPCTSTR)(&(t_ItemInfo[0])));
改为：
t_Menu.AppendMenu(MF_OWNERDRAW|MF_POPUP,(UINT)t_PopMenu.m_hMenu, (LPCTSTR)(&(t_ItemInfo[0])));