一个javascript的函数，控制form1.in_dt1的值在上月的26到本月的25日,如何实现？

2003-06-24 08:34:54 159 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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一个javascript的函数，控制form1.in_dt1的值在上月的26到本月的25日，如不是返回false，
函数如下，但不起作用，请问如何解决
<SCRIPT LANGUAGE=javascript>

</SCRIPT>

...全文

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linuxsun999 2003-06-25

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没人回复自己又考虑了下，原来是把条件写错了。
if ((d2<d_start) || (d2>d_end))
不过还是很感谢 Laone(Laone！

Laone 2003-06-24

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给你一个JS版的DateDiff和DateAdd，你自己参考一下怎么写，功能和vbs的相似
function TimeCom(dateValue){
var newCom = new Date(dateValue);
this.year = newCom.getYear();
this.month = newCom.getMonth()+1;
this.day = newCom.getDate();
this.hour = newCom.getHours();
this.minute = newCom.getMinutes();
this.second = newCom.getSeconds();
this.msecond = newCom.getMilliseconds();
this.week = newCom.getDay();
}

function DateDiff(interval,date1,date2){
var TimeCom1 = new TimeCom(date1);
var TimeCom2 = new TimeCom(date2);
var result;
switch(String(interval).toLowerCase()){
case "y":
case "year":
result = TimeCom1.year-TimeCom2.year;
break;
case "n":
case "month":
result = (TimeCom1.year-TimeCom2.year)*12+(TimeCom1.month-TimeCom2.month);
break;
case "d":
case "day":
result = Math.round((Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day))/(1000*60*60*24));
break;
case "h":
case "hour":
result = Math.round((Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day,TimeCom1.hour)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day,TimeCom2.hour))/(1000*60*60));
break;
case "m":
case "minute":
result = Math.round((Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day,TimeCom1.hour,TimeCom1.minute)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day,TimeCom2.hour,TimeCom2.minute))/(1000*60));
break;
case "s":
case "second":
result = Math.round((Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day,TimeCom1.hour,TimeCom1.minute,TimeCom1.second)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day,TimeCom2.hour,TimeCom2.minute,TimeCom2.second))/1000);
break;
case "ms":
case "msecond":
result = Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day,TimeCom1.hour,TimeCom1.minute,TimeCom1.second,TimeCom1.msecond)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day,TimeCom2.hour,TimeCom2.minute,TimeCom2.second,TimeCom1.msecond);
break;
case "w":
case "week":
result = Math.round((Date.UTC(TimeCom1.year,TimeCom1.month-1,TimeCom1.day)-Date.UTC(TimeCom2.year,TimeCom2.month-1,TimeCom2.day))/(1000*60*60*24)) % 7;
break;
default:
result = "invalid";
}
return(result);
}

function DateAdd(interval, num, dateValue){
var newCom = new TimeCom(dateValue);
switch(String(interval).toLowerCase()){
case "y": case "year": newCom.year += num; break;
case "n": case "month": newCom.month += num; break;
case "d": case "day": newCom.day += num; break;
case "h": case "hour": newCom.hour += num; break;
case "m": case "minute": newCom.minute += num; break;
case "s": case "second": newCom.second += num; break;
case "ms": case "msecond": newCom.msecond += num; break;
case "w": case "week": newCom.day += num*7; break;
default: return("invalid");
}
var now = newCom.year+"/"+newCom.month+"/"+newCom.day+" "+newCom.hour+":"+newCom.minute+":"+newCom.second;
return(new Date(now));
}

linuxsun999 2003-06-24

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没人回答？

一个javascript的函数，控制form1.in_dt1的值在上月的26到本月的25日,如何实现？

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