怎么把byte数组转换成Unicode格式的字符串，vb的StrConv好像有问题

[yunfeng007]

同标题，谢谢！！！

[songhonda]

可以自己写一个函数进行转换，不会太复杂，我就是这样做的

[yunfeng007]

怎么转阿？我就是不会才过来的。能不能给个源程序看看先？

[三楼の郎]

Public Function strAnsi2Unicode(ByVal asContents As String) As String
'将Ansi编码的字符串，转换成Unicode编码的字符串
Dim len1, i As Long
Dim varchar As String
Dim varasc As Long

strAnsi2Unicode = ""
len1 = LenB(asContents)
If len1 = 0 Then Exit Function
For i = 1 To len1
varchar = MidB(asContents, i, 1)
varasc = AscB(varchar)
If varasc > 127 Then
strAnsi2Unicode = strAnsi2Unicode & Chr(AscW(MidB(asContents, i + 1, 1) & varchar))
i = i + 1
Else
strAnsi2Unicode = strAnsi2Unicode & Chr(varasc)
End If
Next
End Function

[sxs69]

什么问题呢?

[yunfeng007]

我要的是byteArray转换成Unicode格式字符串，你给的好像不是阿。有没有人知道呢？

[MyLf]

有问题吗，我好像没碰到过，最好贴出代码。

[yunfeng007]

是这样的。我再写des加密算法。我用的是网上下载的一个类包。其中加密、解密一个文件都没用问题，可就是加密、解密字符串的时候出现问题了。我看了一下源程序，问题就出在byteArray转换成Unicode格式字符串上了，源程序太长，我只能帖一部分
Public Function EncryptString(Text As String, Optional Key As String) As String

Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call EncryptByte(ByteArray(), Key)'这一部分的源码太长

'Convert the byte array back to a string
EncryptString = StrConv(ByteArray(), vbUnicode)

End Function
这个是加密部分

Public Function DecryptString(Text As String, Optional Key As String) As String

Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call DecryptByte(ByteArray(), Key)

'Convert the byte array back to a string
DecryptString = StrConv(ByteArray(), vbUnicode)

End Function
这个是解密部分

[yunfeng007]

我的水品不高，只会用别人写好的类用，可这个我还是用不了，惭愧，郁闷啊！

[rainstormmaster]

是在什么系统下，98下应该没有这个问题，2000下遇到过，可以用CopyMemory试试：

声明
Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)



另外：
Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call EncryptByte(ByteArray(), Key)'这一部分的源码太长

'Convert the byte array back to a string
EncryptString = StrConv(ByteArray(), vbUnicode)

把ByteArray()后面的括号去掉试试

[yunfeng007]

去掉了也不行。kao,头痛啊

[yunfeng007]

全部的
Option Explicit

'For progress notifications
Event Progress(Percent As Long)

'Key-dependant
Private m_Key(0 To 47, 1 To 16) As Byte

'Buffered key value
Private m_KeyValue As String

'Values given in the DES standard
Private m_E(0 To 63) As Byte
Private m_P(0 To 31) As Byte
Private m_IP(0 To 63) As Byte
Private m_PC1(0 To 55) As Byte
Private m_PC2(0 To 47) As Byte
Private m_IPInv(0 To 63) As Byte
Private m_EmptyArray(0 To 63) As Byte
Private m_LeftShifts(1 To 16) As Byte
Private m_sBox(0 To 7, 0 To 1, 0 To 1, 0 To 1, 0 To 1, 0 To 1, 0 To 1) As Long

Private Declare Sub CopyMem Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)
Private Static Sub Byte2Bin(ByteArray() As Byte, ByteLen As Long, BinaryArray() As Byte)

Dim a As Long
Dim ByteValue As Byte
Dim BinLength As Long

'Clear the destination array, faster than
'setting the data to zero in the loop below
Call CopyMem(BinaryArray(0), m_EmptyArray(0), ByteLen * 8)

'Add binary 1's where needed
BinLength = 0
For a = 0 To (ByteLen - 1)
ByteValue = ByteArray(a)
If (ByteValue And 128) Then BinaryArray(BinLength) = 1
If (ByteValue And 64) Then BinaryArray(BinLength + 1) = 1
If (ByteValue And 32) Then BinaryArray(BinLength + 2) = 1
If (ByteValue And 16) Then BinaryArray(BinLength + 3) = 1
If (ByteValue And 8) Then BinaryArray(BinLength + 4) = 1
If (ByteValue And 4) Then BinaryArray(BinLength + 5) = 1
If (ByteValue And 2) Then BinaryArray(BinLength + 6) = 1
If (ByteValue And 1) Then BinaryArray(BinLength + 7) = 1
BinLength = BinLength + 8
Next

End Sub
Private Static Sub Bin2Byte(BinaryArray() As Byte, ByteLen As Long, ByteArray() As Byte)

Dim a As Long
Dim ByteValue As Byte
Dim BinLength As Long

'Calculate byte values
BinLength = 0
For a = 0 To (ByteLen - 1)
ByteValue = 0
If (BinaryArray(BinLength) = 1) Then ByteValue = ByteValue + 128
If (BinaryArray(BinLength + 1) = 1) Then ByteValue = ByteValue + 64
If (BinaryArray(BinLength + 2) = 1) Then ByteValue = ByteValue + 32
If (BinaryArray(BinLength + 3) = 1) Then ByteValue = ByteValue + 16
If (BinaryArray(BinLength + 4) = 1) Then ByteValue = ByteValue + 8
If (BinaryArray(BinLength + 5) = 1) Then ByteValue = ByteValue + 4
If (BinaryArray(BinLength + 6) = 1) Then ByteValue = ByteValue + 2
If (BinaryArray(BinLength + 7) = 1) Then ByteValue = ByteValue + 1
ByteArray(a) = ByteValue
BinLength = BinLength + 8
Next

End Sub
Private Static Sub EncryptBlock(BlockData() As Byte)

Dim a As Long
Dim i As Long
Dim L(0 To 31) As Byte
Dim R(0 To 31) As Byte
Dim RL(0 To 63) As Byte
Dim sBox(0 To 31) As Byte
Dim LiRi(0 To 31) As Byte
Dim ERxorK(0 To 47) As Byte
Dim BinBlock(0 To 63) As Byte

'Convert the block into a binary array
'(I do believe this is the best solution
'in VB for the DES algorithm, but it is
'still slow as xxxx)
Call Byte2Bin(BlockData(), 8, BinBlock())

'Apply the IP permutation and split the
'block into two halves, L[] and R[]
For a = 0 To 31
L(a) = BinBlock(m_IP(a))
R(a) = BinBlock(m_IP(a + 32))
Next

'Apply the 16 subkeys on the block
For i = 1 To 16
'E(R[i]) xor K[i]
ERxorK(0) = R(31) Xor m_Key(0, i)
ERxorK(1) = R(0) Xor m_Key(1, i)
ERxorK(2) = R(1) Xor m_Key(2, i)
ERxorK(3) = R(2) Xor m_Key(3, i)
ERxorK(4) = R(3) Xor m_Key(4, i)
ERxorK(5) = R(4) Xor m_Key(5, i)
ERxorK(6) = R(3) Xor m_Key(6, i)
ERxorK(7) = R(4) Xor m_Key(7, i)
ERxorK(8) = R(5) Xor m_Key(8, i)
ERxorK(9) = R(6) Xor m_Key(9, i)
ERxorK(10) = R(7) Xor m_Key(10, i)
ERxorK(11) = R(8) Xor m_Key(11, i)
ERxorK(12) = R(7) Xor m_Key(12, i)
ERxorK(13) = R(8) Xor m_Key(13, i)
ERxorK(14) = R(9) Xor m_Key(14, i)
ERxorK(15) = R(10) Xor m_Key(15, i)
ERxorK(16) = R(11) Xor m_Key(16, i)
ERxorK(17) = R(12) Xor m_Key(17, i)
ERxorK(18) = R(11) Xor m_Key(18, i)
ERxorK(19) = R(12) Xor m_Key(19, i)
ERxorK(20) = R(13) Xor m_Key(20, i)
ERxorK(21) = R(14) Xor m_Key(21, i)
ERxorK(22) = R(15) Xor m_Key(22, i)
ERxorK(23) = R(16) Xor m_Key(23, i)
ERxorK(24) = R(15) Xor m_Key(24, i)
ERxorK(25) = R(16) Xor m_Key(25, i)
ERxorK(26) = R(17) Xor m_Key(26, i)
ERxorK(27) = R(18) Xor m_Key(27, i)
ERxorK(28) = R(19) Xor m_Key(28, i)
ERxorK(29) = R(20) Xor m_Key(29, i)
ERxorK(30) = R(19) Xor m_Key(30, i)
ERxorK(31) = R(20) Xor m_Key(31, i)
ERxorK(32) = R(21) Xor m_Key(32, i)
ERxorK(33) = R(22) Xor m_Key(33, i)
ERxorK(34) = R(23) Xor m_Key(34, i)
ERxorK(35) = R(24) Xor m_Key(35, i)
ERxorK(36) = R(23) Xor m_Key(36, i)
ERxorK(37) = R(24) Xor m_Key(37, i)
ERxorK(38) = R(25) Xor m_Key(38, i)
ERxorK(39) = R(26) Xor m_Key(39, i)
ERxorK(40) = R(27) Xor m_Key(40, i)
ERxorK(41) = R(28) Xor m_Key(41, i)
ERxorK(42) = R(27) Xor m_Key(42, i)
ERxorK(43) = R(28) Xor m_Key(43, i)
ERxorK(44) = R(29) Xor m_Key(44, i)
ERxorK(45) = R(30) Xor m_Key(45, i)
ERxorK(46) = R(31) Xor m_Key(46, i)
ERxorK(47) = R(0) Xor m_Key(47, i)

'Apply the s-boxes
Call CopyMem(sBox(0), m_sBox(0, ERxorK(0), ERxorK(1), ERxorK(2), ERxorK(3), ERxorK(4), ERxorK(5)), 4)
Call CopyMem(sBox(4), m_sBox(1, ERxorK(6), ERxorK(7), ERxorK(8), ERxorK(9), ERxorK(10), ERxorK(11)), 4)
Call CopyMem(sBox(8), m_sBox(2, ERxorK(12), ERxorK(13), ERxorK(14), ERxorK(15), ERxorK(16), ERxorK(17)), 4)
Call CopyMem(sBox(12), m_sBox(3, ERxorK(18), ERxorK(19), ERxorK(20), ERxorK(21), ERxorK(22), ERxorK(23)), 4)
Call CopyMem(sBox(16), m_sBox(4, ERxorK(24), ERxorK(25), ERxorK(26), ERxorK(27), ERxorK(28), ERxorK(29)), 4)
Call CopyMem(sBox(20), m_sBox(5, ERxorK(30), ERxorK(31), ERxorK(32), ERxorK(33), ERxorK(34), ERxorK(35)), 4)
Call CopyMem(sBox(24), m_sBox(6, ERxorK(36), ERxorK(37), ERxorK(38), ERxorK(39), ERxorK(40), ERxorK(41)), 4)
Call CopyMem(sBox(28), m_sBox(7, ERxorK(42), ERxorK(43), ERxorK(44), ERxorK(45), ERxorK(46), ERxorK(47)), 4)

'L[i] xor P(R[i])
LiRi(0) = L(0) Xor sBox(15)
LiRi(1) = L(1) Xor sBox(6)
LiRi(2) = L(2) Xor sBox(19)
LiRi(3) = L(3) Xor sBox(20)
LiRi(4) = L(4) Xor sBox(28)
LiRi(5) = L(5) Xor sBox(11)
LiRi(6) = L(6) Xor sBox(27)
LiRi(7) = L(7) Xor sBox(16)
LiRi(8) = L(8) Xor sBox(0)
LiRi(9) = L(9) Xor sBox(14)
LiRi(10) = L(10) Xor sBox(22)
LiRi(11) = L(11) Xor sBox(25)
LiRi(12) = L(12) Xor sBox(4)
LiRi(13) = L(13) Xor sBox(17)
LiRi(14) = L(14) Xor sBox(30)
LiRi(15) = L(15) Xor sBox(9)
LiRi(16) = L(16) Xor sBox(1)
LiRi(17) = L(17) Xor sBox(7)
LiRi(18) = L(18) Xor sBox(23)
LiRi(19) = L(19) Xor sBox(13)
LiRi(20) = L(20) Xor sBox(31)
LiRi(21) = L(21) Xor sBox(26)
LiRi(22) = L(22) Xor sBox(2)
LiRi(23) = L(23) Xor sBox(8)
LiRi(24) = L(24) Xor sBox(18)
LiRi(25) = L(25) Xor sBox(12)
LiRi(26) = L(26) Xor sBox(29)
LiRi(27) = L(27) Xor sBox(5)
LiRi(28) = L(28) Xor sBox(21)
LiRi(29) = L(29) Xor sBox(10)
LiRi(30) = L(30) Xor sBox(3)
LiRi(31) = L(31) Xor sBox(24)

'Prepare for next round
Call CopyMem(L(0), R(0), 32)
Call CopyMem(R(0), LiRi(0), 32)
Next

'Concatenate R[]L[]
Call CopyMem(RL(0), R(0), 32)
Call CopyMem(RL(32), L(0), 32)

'Apply the invIP permutation
For a = 0 To 63
BinBlock(a) = RL(m_IPInv(a))
Next

'Convert the binaries into a byte array
Call Bin2Byte(BinBlock(), 8, BlockData())

End Sub

[yunfeng007]

Private Static Sub DecryptBlock(BlockData() As Byte)

Dim a As Long
Dim i As Long
Dim L(0 To 31) As Byte
Dim R(0 To 31) As Byte
Dim RL(0 To 63) As Byte
Dim sBox(0 To 31) As Byte
Dim LiRi(0 To 31) As Byte
Dim ERxorK(0 To 47) As Byte
Dim BinBlock(0 To 63) As Byte

'Convert the block into a binary array
'(I do believe this is the best solution
'in VB for the DES algorithm, but it is
'still slow as xxxx)
Call Byte2Bin(BlockData(), 8, BinBlock())

'Apply the IP permutation and split the
'block into two halves, L[] and R[]
For a = 0 To 31
L(a) = BinBlock(m_IP(a))
R(a) = BinBlock(m_IP(a + 32))
Next

'Apply the 16 subkeys on the block
For i = 16 To 1 Step -1
'E(R[i]) xor K[i]
ERxorK(0) = R(31) Xor m_Key(0, i)
ERxorK(1) = R(0) Xor m_Key(1, i)
ERxorK(2) = R(1) Xor m_Key(2, i)
ERxorK(3) = R(2) Xor m_Key(3, i)
ERxorK(4) = R(3) Xor m_Key(4, i)
ERxorK(5) = R(4) Xor m_Key(5, i)
ERxorK(6) = R(3) Xor m_Key(6, i)
ERxorK(7) = R(4) Xor m_Key(7, i)
ERxorK(8) = R(5) Xor m_Key(8, i)
ERxorK(9) = R(6) Xor m_Key(9, i)
ERxorK(10) = R(7) Xor m_Key(10, i)
ERxorK(11) = R(8) Xor m_Key(11, i)
ERxorK(12) = R(7) Xor m_Key(12, i)
ERxorK(13) = R(8) Xor m_Key(13, i)
ERxorK(14) = R(9) Xor m_Key(14, i)
ERxorK(15) = R(10) Xor m_Key(15, i)
ERxorK(16) = R(11) Xor m_Key(16, i)
ERxorK(17) = R(12) Xor m_Key(17, i)
ERxorK(18) = R(11) Xor m_Key(18, i)
ERxorK(19) = R(12) Xor m_Key(19, i)
ERxorK(20) = R(13) Xor m_Key(20, i)
ERxorK(21) = R(14) Xor m_Key(21, i)
ERxorK(22) = R(15) Xor m_Key(22, i)
ERxorK(23) = R(16) Xor m_Key(23, i)
ERxorK(24) = R(15) Xor m_Key(24, i)
ERxorK(25) = R(16) Xor m_Key(25, i)
ERxorK(26) = R(17) Xor m_Key(26, i)
ERxorK(27) = R(18) Xor m_Key(27, i)
ERxorK(28) = R(19) Xor m_Key(28, i)
ERxorK(29) = R(20) Xor m_Key(29, i)
ERxorK(30) = R(19) Xor m_Key(30, i)
ERxorK(31) = R(20) Xor m_Key(31, i)
ERxorK(32) = R(21) Xor m_Key(32, i)
ERxorK(33) = R(22) Xor m_Key(33, i)
ERxorK(34) = R(23) Xor m_Key(34, i)
ERxorK(35) = R(24) Xor m_Key(35, i)
ERxorK(36) = R(23) Xor m_Key(36, i)
ERxorK(37) = R(24) Xor m_Key(37, i)
ERxorK(38) = R(25) Xor m_Key(38, i)
ERxorK(39) = R(26) Xor m_Key(39, i)
ERxorK(40) = R(27) Xor m_Key(40, i)
ERxorK(41) = R(28) Xor m_Key(41, i)
ERxorK(42) = R(27) Xor m_Key(42, i)
ERxorK(43) = R(28) Xor m_Key(43, i)
ERxorK(44) = R(29) Xor m_Key(44, i)
ERxorK(45) = R(30) Xor m_Key(45, i)
ERxorK(46) = R(31) Xor m_Key(46, i)
ERxorK(47) = R(0) Xor m_Key(47, i)

'Apply the s-boxes
Call CopyMem(sBox(0), m_sBox(0, ERxorK(0), ERxorK(1), ERxorK(2), ERxorK(3), ERxorK(4), ERxorK(5)), 4)
Call CopyMem(sBox(4), m_sBox(1, ERxorK(6), ERxorK(7), ERxorK(8), ERxorK(9), ERxorK(10), ERxorK(11)), 4)
Call CopyMem(sBox(8), m_sBox(2, ERxorK(12), ERxorK(13), ERxorK(14), ERxorK(15), ERxorK(16), ERxorK(17)), 4)
Call CopyMem(sBox(12), m_sBox(3, ERxorK(18), ERxorK(19), ERxorK(20), ERxorK(21), ERxorK(22), ERxorK(23)), 4)
Call CopyMem(sBox(16), m_sBox(4, ERxorK(24), ERxorK(25), ERxorK(26), ERxorK(27), ERxorK(28), ERxorK(29)), 4)
Call CopyMem(sBox(20), m_sBox(5, ERxorK(30), ERxorK(31), ERxorK(32), ERxorK(33), ERxorK(34), ERxorK(35)), 4)
Call CopyMem(sBox(24), m_sBox(6, ERxorK(36), ERxorK(37), ERxorK(38), ERxorK(39), ERxorK(40), ERxorK(41)), 4)
Call CopyMem(sBox(28), m_sBox(7, ERxorK(42), ERxorK(43), ERxorK(44), ERxorK(45), ERxorK(46), ERxorK(47)), 4)

'L[i] xor P(R[i])
LiRi(0) = L(0) Xor sBox(15)
LiRi(1) = L(1) Xor sBox(6)
LiRi(2) = L(2) Xor sBox(19)
LiRi(3) = L(3) Xor sBox(20)
LiRi(4) = L(4) Xor sBox(28)
LiRi(5) = L(5) Xor sBox(11)
LiRi(6) = L(6) Xor sBox(27)
LiRi(7) = L(7) Xor sBox(16)
LiRi(8) = L(8) Xor sBox(0)
LiRi(9) = L(9) Xor sBox(14)
LiRi(10) = L(10) Xor sBox(22)
LiRi(11) = L(11) Xor sBox(25)
LiRi(12) = L(12) Xor sBox(4)
LiRi(13) = L(13) Xor sBox(17)
LiRi(14) = L(14) Xor sBox(30)
LiRi(15) = L(15) Xor sBox(9)
LiRi(16) = L(16) Xor sBox(1)
LiRi(17) = L(17) Xor sBox(7)
LiRi(18) = L(18) Xor sBox(23)
LiRi(19) = L(19) Xor sBox(13)
LiRi(20) = L(20) Xor sBox(31)
LiRi(21) = L(21) Xor sBox(26)
LiRi(22) = L(22) Xor sBox(2)
LiRi(23) = L(23) Xor sBox(8)
LiRi(24) = L(24) Xor sBox(18)
LiRi(25) = L(25) Xor sBox(12)
LiRi(26) = L(26) Xor sBox(29)
LiRi(27) = L(27) Xor sBox(5)
LiRi(28) = L(28) Xor sBox(21)
LiRi(29) = L(29) Xor sBox(10)
LiRi(30) = L(30) Xor sBox(3)
LiRi(31) = L(31) Xor sBox(24)

'Prepare for next round
Call CopyMem(L(0), R(0), 32)
Call CopyMem(R(0), LiRi(0), 32)
Next

'Concatenate R[]L[]
Call CopyMem(RL(0), R(0), 32)
Call CopyMem(RL(32), L(0), 32)

'Apply the invIP permutation
For a = 0 To 63
BinBlock(a) = RL(m_IPInv(a))
Next

'Convert the binaries into a byte array
Call Bin2Byte(BinBlock(), 8, BlockData())

End Sub

Public Sub EncryptByte(ByteArray() As Byte, Optional Key As String)

Dim a As Long
Dim Offset As Long
Dim OrigLen As Long
Dim CipherLen As Long
Dim CurrPercent As Long
Dim NextPercent As Long
Dim CurrBlock(0 To 7) As Byte
Dim CipherBlock(0 To 7) As Byte

'Set the key if provided
If (Len(Key) > 0) Then Me.Key = Key

'Get the size of the original array
OrigLen = UBound(ByteArray) + 1

'First we add 12 bytes (4 bytes for the
'length and 8 bytes for the seed values
'for the CBC routine), and the ciphertext
'must be a multiple of 8 bytes
CipherLen = OrigLen + 12
If (CipherLen Mod 8 <> 0) Then
CipherLen = CipherLen + 8 - (CipherLen Mod 8)
End If
ReDim Preserve ByteArray(CipherLen - 1)
Call CopyMem(ByteArray(12), ByteArray(0), OrigLen)

'Store the length descriptor in bytes [9-12]
Call CopyMem(ByteArray(8), OrigLen, 4)

'Store a block of random data in bytes [1-8],
'these work as seed values for the CBC routine
'and is used to produce different ciphertext
'even when encrypting the same data with the
'same key)
Call Randomize
Call CopyMem(ByteArray(0), CLng(2147483647 * Rnd), 4)
Call CopyMem(ByteArray(4), CLng(2147483647 * Rnd), 4)

'Encrypt the data in 64-bit blocks
For Offset = 0 To (CipherLen - 1) Step 8
'Get the next block of plaintext
Call CopyMem(CurrBlock(0), ByteArray(Offset), 8)

'XOR the plaintext with the previous
'ciphertext (CBC, Cipher-Block Chaining)
For a = 0 To 7
CurrBlock(a) = CurrBlock(a) Xor CipherBlock(a)
Next

'Encrypt the block
Call EncryptBlock(CurrBlock())

'Store the block
Call CopyMem(ByteArray(Offset), CurrBlock(0), 8)

'Store the cipherblock (for CBC)
Call CopyMem(CipherBlock(0), CurrBlock(0), 8)

'Update the progress if neccessary
If (Offset >= NextPercent) Then
CurrPercent = Int((Offset / CipherLen) * 100)
NextPercent = (CipherLen * ((CurrPercent + 1) / 100)) + 1
RaiseEvent Progress(CurrPercent)
End If
Next

'Make sure we return a 100% progress
If (CurrPercent <> 100) Then RaiseEvent Progress(100)

End Sub