怎么把byte数组转换成Unicode格式的字符串，vb的StrConv好像有问题

2003-07-10 07:25:03 438 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

VB6/VBA中MD5哈希算法的高效实现与优化实战哈希算法是计算机科学中用于数据完整性校验和生成固定长度摘要的核心技术，其原理是将任意长度的输入通过特定计算映射为固定长度的输出。MD5作为一种经典的哈希算法，虽然因其碰撞漏洞已不适用于高安全场景，但在数据校验、生成唯一标识符和兼容老旧系统接口等方面仍有广泛应用价值。在Visual Basic 6.0或VBA这类经典开发环境中，实现MD5面临无符号整数缺失、位操作支持有限等挑战。本文通过构建模拟无符号运算的核心函数、优化四轮循环结构，并封装成高性能类模块，提供了一个可直接集成到遗留项目中的解决方案，有效解决了阅读详情

同标题，谢谢！！！

...全文

VB6实现AES加密：为遗留系统注入现代安全能力 AES（高级加密标准）作为当前应用最广泛的对称加密算法，其核心原理基于替换-置换网络，通过多轮迭代的字节代换、行移位、列混合和轮密钥加操作，实现对数据块的混淆与扩散，从而确保机密性。该算法因其安全性高、效率优异，已成为HTTPS、数据库加密、文件保护等众多场景的基石。在工程实践中，为Visual Basic 6.0等遗留技术栈集成AES能力，是满足现代数据安全法规与业务升级需求的关键技术手段。本文聚焦于在VB6环境中实现AES-CBC模式与PKCS7填充，深入剖析纯代码实现与DLL调用的方案选型、核心算法模阅读详情

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yunfeng007 2003-07-10

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Private Static Sub DecryptBlock(BlockData() As Byte)

Dim a As Long
Dim i As Long
Dim L(0 To 31) As Byte
Dim R(0 To 31) As Byte
Dim RL(0 To 63) As Byte
Dim sBox(0 To 31) As Byte
Dim LiRi(0 To 31) As Byte
Dim ERxorK(0 To 47) As Byte
Dim BinBlock(0 To 63) As Byte

'Convert the block into a binary array
'(I do believe this is the best solution
'in VB for the DES algorithm, but it is
'still slow as xxxx)
Call Byte2Bin(BlockData(), 8, BinBlock())

'Apply the IP permutation and split the
'block into two halves, L[] and R[]
For a = 0 To 31
L(a) = BinBlock(m_IP(a))
R(a) = BinBlock(m_IP(a + 32))
Next

'Apply the 16 subkeys on the block
For i = 16 To 1 Step -1
'E(R[i]) xor K[i]
ERxorK(0) = R(31) Xor m_Key(0, i)
ERxorK(1) = R(0) Xor m_Key(1, i)
ERxorK(2) = R(1) Xor m_Key(2, i)
ERxorK(3) = R(2) Xor m_Key(3, i)
ERxorK(4) = R(3) Xor m_Key(4, i)
ERxorK(5) = R(4) Xor m_Key(5, i)
ERxorK(6) = R(3) Xor m_Key(6, i)
ERxorK(7) = R(4) Xor m_Key(7, i)
ERxorK(8) = R(5) Xor m_Key(8, i)
ERxorK(9) = R(6) Xor m_Key(9, i)
ERxorK(10) = R(7) Xor m_Key(10, i)
ERxorK(11) = R(8) Xor m_Key(11, i)
ERxorK(12) = R(7) Xor m_Key(12, i)
ERxorK(13) = R(8) Xor m_Key(13, i)
ERxorK(14) = R(9) Xor m_Key(14, i)
ERxorK(15) = R(10) Xor m_Key(15, i)
ERxorK(16) = R(11) Xor m_Key(16, i)
ERxorK(17) = R(12) Xor m_Key(17, i)
ERxorK(18) = R(11) Xor m_Key(18, i)
ERxorK(19) = R(12) Xor m_Key(19, i)
ERxorK(20) = R(13) Xor m_Key(20, i)
ERxorK(21) = R(14) Xor m_Key(21, i)
ERxorK(22) = R(15) Xor m_Key(22, i)
ERxorK(23) = R(16) Xor m_Key(23, i)
ERxorK(24) = R(15) Xor m_Key(24, i)
ERxorK(25) = R(16) Xor m_Key(25, i)
ERxorK(26) = R(17) Xor m_Key(26, i)
ERxorK(27) = R(18) Xor m_Key(27, i)
ERxorK(28) = R(19) Xor m_Key(28, i)
ERxorK(29) = R(20) Xor m_Key(29, i)
ERxorK(30) = R(19) Xor m_Key(30, i)
ERxorK(31) = R(20) Xor m_Key(31, i)
ERxorK(32) = R(21) Xor m_Key(32, i)
ERxorK(33) = R(22) Xor m_Key(33, i)
ERxorK(34) = R(23) Xor m_Key(34, i)
ERxorK(35) = R(24) Xor m_Key(35, i)
ERxorK(36) = R(23) Xor m_Key(36, i)
ERxorK(37) = R(24) Xor m_Key(37, i)
ERxorK(38) = R(25) Xor m_Key(38, i)
ERxorK(39) = R(26) Xor m_Key(39, i)
ERxorK(40) = R(27) Xor m_Key(40, i)
ERxorK(41) = R(28) Xor m_Key(41, i)
ERxorK(42) = R(27) Xor m_Key(42, i)
ERxorK(43) = R(28) Xor m_Key(43, i)
ERxorK(44) = R(29) Xor m_Key(44, i)
ERxorK(45) = R(30) Xor m_Key(45, i)
ERxorK(46) = R(31) Xor m_Key(46, i)
ERxorK(47) = R(0) Xor m_Key(47, i)

'Apply the s-boxes
Call CopyMem(sBox(0), m_sBox(0, ERxorK(0), ERxorK(1), ERxorK(2), ERxorK(3), ERxorK(4), ERxorK(5)), 4)
Call CopyMem(sBox(4), m_sBox(1, ERxorK(6), ERxorK(7), ERxorK(8), ERxorK(9), ERxorK(10), ERxorK(11)), 4)
Call CopyMem(sBox(8), m_sBox(2, ERxorK(12), ERxorK(13), ERxorK(14), ERxorK(15), ERxorK(16), ERxorK(17)), 4)
Call CopyMem(sBox(12), m_sBox(3, ERxorK(18), ERxorK(19), ERxorK(20), ERxorK(21), ERxorK(22), ERxorK(23)), 4)
Call CopyMem(sBox(16), m_sBox(4, ERxorK(24), ERxorK(25), ERxorK(26), ERxorK(27), ERxorK(28), ERxorK(29)), 4)
Call CopyMem(sBox(20), m_sBox(5, ERxorK(30), ERxorK(31), ERxorK(32), ERxorK(33), ERxorK(34), ERxorK(35)), 4)
Call CopyMem(sBox(24), m_sBox(6, ERxorK(36), ERxorK(37), ERxorK(38), ERxorK(39), ERxorK(40), ERxorK(41)), 4)
Call CopyMem(sBox(28), m_sBox(7, ERxorK(42), ERxorK(43), ERxorK(44), ERxorK(45), ERxorK(46), ERxorK(47)), 4)

'L[i] xor P(R[i])
LiRi(0) = L(0) Xor sBox(15)
LiRi(1) = L(1) Xor sBox(6)
LiRi(2) = L(2) Xor sBox(19)
LiRi(3) = L(3) Xor sBox(20)
LiRi(4) = L(4) Xor sBox(28)
LiRi(5) = L(5) Xor sBox(11)
LiRi(6) = L(6) Xor sBox(27)
LiRi(7) = L(7) Xor sBox(16)
LiRi(8) = L(8) Xor sBox(0)
LiRi(9) = L(9) Xor sBox(14)
LiRi(10) = L(10) Xor sBox(22)
LiRi(11) = L(11) Xor sBox(25)
LiRi(12) = L(12) Xor sBox(4)
LiRi(13) = L(13) Xor sBox(17)
LiRi(14) = L(14) Xor sBox(30)
LiRi(15) = L(15) Xor sBox(9)
LiRi(16) = L(16) Xor sBox(1)
LiRi(17) = L(17) Xor sBox(7)
LiRi(18) = L(18) Xor sBox(23)
LiRi(19) = L(19) Xor sBox(13)
LiRi(20) = L(20) Xor sBox(31)
LiRi(21) = L(21) Xor sBox(26)
LiRi(22) = L(22) Xor sBox(2)
LiRi(23) = L(23) Xor sBox(8)
LiRi(24) = L(24) Xor sBox(18)
LiRi(25) = L(25) Xor sBox(12)
LiRi(26) = L(26) Xor sBox(29)
LiRi(27) = L(27) Xor sBox(5)
LiRi(28) = L(28) Xor sBox(21)
LiRi(29) = L(29) Xor sBox(10)
LiRi(30) = L(30) Xor sBox(3)
LiRi(31) = L(31) Xor sBox(24)

'Prepare for next round
Call CopyMem(L(0), R(0), 32)
Call CopyMem(R(0), LiRi(0), 32)
Next

'Concatenate R[]L[]
Call CopyMem(RL(0), R(0), 32)
Call CopyMem(RL(32), L(0), 32)

'Apply the invIP permutation
For a = 0 To 63
BinBlock(a) = RL(m_IPInv(a))
Next

'Convert the binaries into a byte array
Call Bin2Byte(BinBlock(), 8, BlockData())

End Sub

Public Sub EncryptByte(ByteArray() As Byte, Optional Key As String)

Dim a As Long
Dim Offset As Long
Dim OrigLen As Long
Dim CipherLen As Long
Dim CurrPercent As Long
Dim NextPercent As Long
Dim CurrBlock(0 To 7) As Byte
Dim CipherBlock(0 To 7) As Byte

'Set the key if provided
If (Len(Key) > 0) Then Me.Key = Key

'Get the size of the original array
OrigLen = UBound(ByteArray) + 1

'First we add 12 bytes (4 bytes for the
'length and 8 bytes for the seed values
'for the CBC routine), and the ciphertext
'must be a multiple of 8 bytes
CipherLen = OrigLen + 12
If (CipherLen Mod 8 <> 0) Then
CipherLen = CipherLen + 8 - (CipherLen Mod 8)
End If
ReDim Preserve ByteArray(CipherLen - 1)
Call CopyMem(ByteArray(12), ByteArray(0), OrigLen)

'Store the length descriptor in bytes [9-12]
Call CopyMem(ByteArray(8), OrigLen, 4)

'Store a block of random data in bytes [1-8],
'these work as seed values for the CBC routine
'and is used to produce different ciphertext
'even when encrypting the same data with the
'same key)
Call Randomize
Call CopyMem(ByteArray(0), CLng(2147483647 * Rnd), 4)
Call CopyMem(ByteArray(4), CLng(2147483647 * Rnd), 4)

'Encrypt the data in 64-bit blocks
For Offset = 0 To (CipherLen - 1) Step 8
'Get the next block of plaintext
Call CopyMem(CurrBlock(0), ByteArray(Offset), 8)

'XOR the plaintext with the previous
'ciphertext (CBC, Cipher-Block Chaining)
For a = 0 To 7
CurrBlock(a) = CurrBlock(a) Xor CipherBlock(a)
Next

'Encrypt the block
Call EncryptBlock(CurrBlock())

'Store the block
Call CopyMem(ByteArray(Offset), CurrBlock(0), 8)

'Store the cipherblock (for CBC)
Call CopyMem(CipherBlock(0), CurrBlock(0), 8)

'Update the progress if neccessary
If (Offset >= NextPercent) Then
CurrPercent = Int((Offset / CipherLen) * 100)
NextPercent = (CipherLen * ((CurrPercent + 1) / 100)) + 1
RaiseEvent Progress(CurrPercent)
End If
Next

'Make sure we return a 100% progress
If (CurrPercent <> 100) Then RaiseEvent Progress(100)

End Sub

yunfeng007 2003-07-10

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Option Explicit

'For progress notifications
Event Progress(Percent As Long)

'Key-dependant
Private m_Key(0 To 47, 1 To 16) As Byte

'Buffered key value
Private m_KeyValue As String

'Values given in the DES standard
Private m_E(0 To 63) As Byte
Private m_P(0 To 31) As Byte
Private m_IP(0 To 63) As Byte
Private m_PC1(0 To 55) As Byte
Private m_PC2(0 To 47) As Byte
Private m_IPInv(0 To 63) As Byte
Private m_EmptyArray(0 To 63) As Byte
Private m_LeftShifts(1 To 16) As Byte
Private m_sBox(0 To 7, 0 To 1, 0 To 1, 0 To 1, 0 To 1, 0 To 1, 0 To 1) As Long

Private Declare Sub CopyMem Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)
Private Static Sub Byte2Bin(ByteArray() As Byte, ByteLen As Long, BinaryArray() As Byte)

Dim a As Long
Dim ByteValue As Byte
Dim BinLength As Long

'Clear the destination array, faster than
'setting the data to zero in the loop below
Call CopyMem(BinaryArray(0), m_EmptyArray(0), ByteLen * 8)

'Add binary 1's where needed
BinLength = 0
For a = 0 To (ByteLen - 1)
ByteValue = ByteArray(a)
If (ByteValue And 128) Then BinaryArray(BinLength) = 1
If (ByteValue And 64) Then BinaryArray(BinLength + 1) = 1
If (ByteValue And 32) Then BinaryArray(BinLength + 2) = 1
If (ByteValue And 16) Then BinaryArray(BinLength + 3) = 1
If (ByteValue And 8) Then BinaryArray(BinLength + 4) = 1
If (ByteValue And 4) Then BinaryArray(BinLength + 5) = 1
If (ByteValue And 2) Then BinaryArray(BinLength + 6) = 1
If (ByteValue And 1) Then BinaryArray(BinLength + 7) = 1
BinLength = BinLength + 8
Next

End Sub
Private Static Sub Bin2Byte(BinaryArray() As Byte, ByteLen As Long, ByteArray() As Byte)

Dim a As Long
Dim ByteValue As Byte
Dim BinLength As Long

'Calculate byte values
BinLength = 0
For a = 0 To (ByteLen - 1)
ByteValue = 0
If (BinaryArray(BinLength) = 1) Then ByteValue = ByteValue + 128
If (BinaryArray(BinLength + 1) = 1) Then ByteValue = ByteValue + 64
If (BinaryArray(BinLength + 2) = 1) Then ByteValue = ByteValue + 32
If (BinaryArray(BinLength + 3) = 1) Then ByteValue = ByteValue + 16
If (BinaryArray(BinLength + 4) = 1) Then ByteValue = ByteValue + 8
If (BinaryArray(BinLength + 5) = 1) Then ByteValue = ByteValue + 4
If (BinaryArray(BinLength + 6) = 1) Then ByteValue = ByteValue + 2
If (BinaryArray(BinLength + 7) = 1) Then ByteValue = ByteValue + 1
ByteArray(a) = ByteValue
BinLength = BinLength + 8
Next

End Sub
Private Static Sub EncryptBlock(BlockData() As Byte)

Dim a As Long
Dim i As Long
Dim L(0 To 31) As Byte
Dim R(0 To 31) As Byte
Dim RL(0 To 63) As Byte
Dim sBox(0 To 31) As Byte
Dim LiRi(0 To 31) As Byte
Dim ERxorK(0 To 47) As Byte
Dim BinBlock(0 To 63) As Byte

'Convert the block into a binary array
'(I do believe this is the best solution
'in VB for the DES algorithm, but it is
'still slow as xxxx)
Call Byte2Bin(BlockData(), 8, BinBlock())

'Apply the IP permutation and split the
'block into two halves, L[] and R[]
For a = 0 To 31
L(a) = BinBlock(m_IP(a))
R(a) = BinBlock(m_IP(a + 32))
Next

'Apply the 16 subkeys on the block
For i = 1 To 16
'E(R[i]) xor K[i]
ERxorK(0) = R(31) Xor m_Key(0, i)
ERxorK(1) = R(0) Xor m_Key(1, i)
ERxorK(2) = R(1) Xor m_Key(2, i)
ERxorK(3) = R(2) Xor m_Key(3, i)
ERxorK(4) = R(3) Xor m_Key(4, i)
ERxorK(5) = R(4) Xor m_Key(5, i)
ERxorK(6) = R(3) Xor m_Key(6, i)
ERxorK(7) = R(4) Xor m_Key(7, i)
ERxorK(8) = R(5) Xor m_Key(8, i)
ERxorK(9) = R(6) Xor m_Key(9, i)
ERxorK(10) = R(7) Xor m_Key(10, i)
ERxorK(11) = R(8) Xor m_Key(11, i)
ERxorK(12) = R(7) Xor m_Key(12, i)
ERxorK(13) = R(8) Xor m_Key(13, i)
ERxorK(14) = R(9) Xor m_Key(14, i)
ERxorK(15) = R(10) Xor m_Key(15, i)
ERxorK(16) = R(11) Xor m_Key(16, i)
ERxorK(17) = R(12) Xor m_Key(17, i)
ERxorK(18) = R(11) Xor m_Key(18, i)
ERxorK(19) = R(12) Xor m_Key(19, i)
ERxorK(20) = R(13) Xor m_Key(20, i)
ERxorK(21) = R(14) Xor m_Key(21, i)
ERxorK(22) = R(15) Xor m_Key(22, i)
ERxorK(23) = R(16) Xor m_Key(23, i)
ERxorK(24) = R(15) Xor m_Key(24, i)
ERxorK(25) = R(16) Xor m_Key(25, i)
ERxorK(26) = R(17) Xor m_Key(26, i)
ERxorK(27) = R(18) Xor m_Key(27, i)
ERxorK(28) = R(19) Xor m_Key(28, i)
ERxorK(29) = R(20) Xor m_Key(29, i)
ERxorK(30) = R(19) Xor m_Key(30, i)
ERxorK(31) = R(20) Xor m_Key(31, i)
ERxorK(32) = R(21) Xor m_Key(32, i)
ERxorK(33) = R(22) Xor m_Key(33, i)
ERxorK(34) = R(23) Xor m_Key(34, i)
ERxorK(35) = R(24) Xor m_Key(35, i)
ERxorK(36) = R(23) Xor m_Key(36, i)
ERxorK(37) = R(24) Xor m_Key(37, i)
ERxorK(38) = R(25) Xor m_Key(38, i)
ERxorK(39) = R(26) Xor m_Key(39, i)
ERxorK(40) = R(27) Xor m_Key(40, i)
ERxorK(41) = R(28) Xor m_Key(41, i)
ERxorK(42) = R(27) Xor m_Key(42, i)
ERxorK(43) = R(28) Xor m_Key(43, i)
ERxorK(44) = R(29) Xor m_Key(44, i)
ERxorK(45) = R(30) Xor m_Key(45, i)
ERxorK(46) = R(31) Xor m_Key(46, i)
ERxorK(47) = R(0) Xor m_Key(47, i)

'Apply the s-boxes
Call CopyMem(sBox(0), m_sBox(0, ERxorK(0), ERxorK(1), ERxorK(2), ERxorK(3), ERxorK(4), ERxorK(5)), 4)
Call CopyMem(sBox(4), m_sBox(1, ERxorK(6), ERxorK(7), ERxorK(8), ERxorK(9), ERxorK(10), ERxorK(11)), 4)
Call CopyMem(sBox(8), m_sBox(2, ERxorK(12), ERxorK(13), ERxorK(14), ERxorK(15), ERxorK(16), ERxorK(17)), 4)
Call CopyMem(sBox(12), m_sBox(3, ERxorK(18), ERxorK(19), ERxorK(20), ERxorK(21), ERxorK(22), ERxorK(23)), 4)
Call CopyMem(sBox(16), m_sBox(4, ERxorK(24), ERxorK(25), ERxorK(26), ERxorK(27), ERxorK(28), ERxorK(29)), 4)
Call CopyMem(sBox(20), m_sBox(5, ERxorK(30), ERxorK(31), ERxorK(32), ERxorK(33), ERxorK(34), ERxorK(35)), 4)
Call CopyMem(sBox(24), m_sBox(6, ERxorK(36), ERxorK(37), ERxorK(38), ERxorK(39), ERxorK(40), ERxorK(41)), 4)
Call CopyMem(sBox(28), m_sBox(7, ERxorK(42), ERxorK(43), ERxorK(44), ERxorK(45), ERxorK(46), ERxorK(47)), 4)

'L[i] xor P(R[i])
LiRi(0) = L(0) Xor sBox(15)
LiRi(1) = L(1) Xor sBox(6)
LiRi(2) = L(2) Xor sBox(19)
LiRi(3) = L(3) Xor sBox(20)
LiRi(4) = L(4) Xor sBox(28)
LiRi(5) = L(5) Xor sBox(11)
LiRi(6) = L(6) Xor sBox(27)
LiRi(7) = L(7) Xor sBox(16)
LiRi(8) = L(8) Xor sBox(0)
LiRi(9) = L(9) Xor sBox(14)
LiRi(10) = L(10) Xor sBox(22)
LiRi(11) = L(11) Xor sBox(25)
LiRi(12) = L(12) Xor sBox(4)
LiRi(13) = L(13) Xor sBox(17)
LiRi(14) = L(14) Xor sBox(30)
LiRi(15) = L(15) Xor sBox(9)
LiRi(16) = L(16) Xor sBox(1)
LiRi(17) = L(17) Xor sBox(7)
LiRi(18) = L(18) Xor sBox(23)
LiRi(19) = L(19) Xor sBox(13)
LiRi(20) = L(20) Xor sBox(31)
LiRi(21) = L(21) Xor sBox(26)
LiRi(22) = L(22) Xor sBox(2)
LiRi(23) = L(23) Xor sBox(8)
LiRi(24) = L(24) Xor sBox(18)
LiRi(25) = L(25) Xor sBox(12)
LiRi(26) = L(26) Xor sBox(29)
LiRi(27) = L(27) Xor sBox(5)
LiRi(28) = L(28) Xor sBox(21)
LiRi(29) = L(29) Xor sBox(10)
LiRi(30) = L(30) Xor sBox(3)
LiRi(31) = L(31) Xor sBox(24)

'Prepare for next round
Call CopyMem(L(0), R(0), 32)
Call CopyMem(R(0), LiRi(0), 32)
Next

'Concatenate R[]L[]
Call CopyMem(RL(0), R(0), 32)
Call CopyMem(RL(32), L(0), 32)

'Apply the invIP permutation
For a = 0 To 63
BinBlock(a) = RL(m_IPInv(a))
Next

'Convert the binaries into a byte array
Call Bin2Byte(BinBlock(), 8, BlockData())

End Sub

yunfeng007 2003-07-10

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去掉了也不行。kao,头痛啊

rainstormmaster 2003-07-10

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是在什么系统下，98下应该没有这个问题，2000下遇到过，可以用CopyMemory试试：

声明
Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)

另外：
Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call EncryptByte(ByteArray(), Key)'这一部分的源码太长

'Convert the byte array back to a string
EncryptString = StrConv(ByteArray(), vbUnicode)

把ByteArray()后面的括号去掉试试

yunfeng007 2003-07-10

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我的水品不高，只会用别人写好的类用，可这个我还是用不了，惭愧，郁闷啊！

yunfeng007 2003-07-10

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是这样的。我再写des加密算法。我用的是网上下载的一个类包。其中加密、解密一个文件都没用问题，可就是加密、解密字符串的时候出现问题了。我看了一下源程序，问题就出在byteArray转换成Unicode格式字符串上了，源程序太长，我只能帖一部分
Public Function EncryptString(Text As String, Optional Key As String) As String

Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call EncryptByte(ByteArray(), Key)'这一部分的源码太长

'Convert the byte array back to a string
EncryptString = StrConv(ByteArray(), vbUnicode)

End Function
这个是加密部分

Public Function DecryptString(Text As String, Optional Key As String) As String

Dim ByteArray() As Byte

'Convert the text into a byte array
ByteArray() = StrConv(Text, vbFromUnicode)

'Encrypt the byte array
Call DecryptByte(ByteArray(), Key)

'Convert the byte array back to a string
DecryptString = StrConv(ByteArray(), vbUnicode)

End Function
这个是解密部分

MyLf 2003-07-10

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有问题吗，我好像没碰到过，最好贴出代码。

yunfeng007 2003-07-10

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我要的是byteArray转换成Unicode格式字符串，你给的好像不是阿。有没有人知道呢？

sxs69 2003-07-10

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什么问题呢?

三楼の郎 2003-07-10

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Public Function strAnsi2Unicode(ByVal asContents As String) As String
'将Ansi编码的字符串，转换成Unicode编码的字符串
Dim len1, i As Long
Dim varchar As String
Dim varasc As Long

strAnsi2Unicode = ""
len1 = LenB(asContents)
If len1 = 0 Then Exit Function
For i = 1 To len1
varchar = MidB(asContents, i, 1)
varasc = AscB(varchar)
If varasc > 127 Then
strAnsi2Unicode = strAnsi2Unicode & Chr(AscW(MidB(asContents, i + 1, 1) & varchar))
i = i + 1
Else
strAnsi2Unicode = strAnsi2Unicode & Chr(varasc)
End If
Next
End Function

yunfeng007 2003-07-10

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怎么转阿？我就是不会才过来的。能不能给个源程序看看先？

songhonda 2003-07-10

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可以自己写一个函数进行转换，不会太复杂，我就是这样做的

怎么把byte数组转换成Unicode格式的字符串，vb的StrConv好像有问题

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