find()函数的奇怪结果

[imeng99]

#include <iostream>
#include <string>

using namespace std;

int main()
{
const string name( "AnnaBelle" );
for( int i = 0; i < name.size(); ++ i )
{
cout << i << endl;
string::size_type pos = name.find( "Belle", 0, i );
if( pos == string::npos )
cout << "Belle not found!\n";
else
cout << "Belle found at pos: " << pos << endl;
}

return 0;
}
/*
// 输出结果
1
Belle found at pos: 4
2
Belle found at pos: 4
3
Belle found at pos: 4
4
Belle found at pos: 4
5
Belle found at pos: 4
6
Belle not found!
7
Belle not found!
8
Belle not found!
Press any key to continue
*/
这个结果完全和我想象的不同，为什么会有这样的结果？

[小笨和漂向北方]

你想要什么？find的第三个参数指明匹配的字符数的
我想你要的是这个
#include <iostream>
#include <string>

using namespace std;

int main()
{
const string name( "AnnaBelle" );
for( int i = 0; i < name.size(); ++ i )
{
cout << i << endl;
string::size_type pos = name.find( "Belle", i, 5 ); //!
if( pos == string::npos )
cout << "Belle not found!\n";
else
cout << "Belle found at pos: " << pos << endl;
}

return 0;
}
0
Belle found at pos: 4
1
Belle found at pos: 4
2
Belle found at pos: 4
3
Belle found at pos: 4
4
Belle found at pos: 4
5
Belle found at pos: 4
6
Belle not found!
7
Belle not found!
8
Belle not found!
Press any key to continue

[imeng99]

to micropentium6(小笨)：
find的第二个参数指明查找的开始位置，第三个参数指明查找的结束位置。

[fixopen]

size_type find(const value_type* p, size_type off = 0, size_type count) const;

如果micropentium6(小笨)那样的程序，得出这样的结果是正常的。

那 imeng99(凌晨两三点) 的结果怎样理解呢？BTW
结果是：
0
Belle found at pos: 0
1
Belle found at pos: 4
2
Belle found at pos: 4
3
Belle found at pos: 4
4
Belle found at pos: 4
5
Belle found at pos: 4
6
Belle not found!
7
Belle not found!
8
Belle not found!

我的第零个结果是0

惊讶于结果，不懂count参数的含义

[njtu]

同意micropentium6(小笨)

to fixopen(dup) ( ):
name.find( "Belle", 0, 0 ); 返回 0（第一个位置）