如何在tomcat中启动配置rmi服务

[zzhangwa]

如何在tomcat中启动配置rmi服务

[zzhangwa]

up

[vcvj]

用J2EE吧

[jackyz]

首先，你需要有一个 RMIRunner

package com.your.rmi;

import java.rmi.*;
import java.rmi.registry.*;
import org.apache.log4j.Logger;

public class RMIRunner implements Runnable {

private static Logger log = Logger.getLogger( RMIRunner.class );

// ***********************

private void rmiStart() {
try {
Registry r = LocateRegistry.getRegistry(RMIExecutor.ServerPort);
if ( r != null) r = LocateRegistry.createRegistry(RMIExecutor.ServerPort);
RMIServer s = new RMIServerImpl();
Naming.rebind(RMIServer.ServerName, s);
log.info("rmiStart successful.");
} catch (Exception e) {
log.error("During rmiStart", e);
}
}

public void run() {
rmiStart();
}

}

然后，要写一支 servlet 来调用它

package com.your.web.RMIInit;

import javax.servlet.*;
import javax.servlet.http.*;
import com.your.rmi.RMIRunner;

public class RMIInit extends GenericServlet {

public void init( ServletConfig config ) throws ServletException {
RMIRunner rmiRunner = new RMIRunner();
Thread t = new Thread(rmiRunner);
t.start();
}

public void service( ServletRequest req, ServletResponse res ) throws ServletException, IOException { }

public void destroy() { }

}

最后，在 web.xml 中配置该 servlet 为 load-on-startup 的
....
<servlet>
<servlet-name>rmiInit</servlet-name>
<display-name>RMI Server Init</display-name>
<servlet-class>com.your.web.RMIInit</servlet-class>
<load-on-startup>3</load-on-startup>
</servlet>
....

搞定

[jackyz]

上诉代码有误，应为：

private void rmiStart() {
try {
Registry r = LocateRegistry.getRegistry(RMIServer.Port);
if ( r != null) r = LocateRegistry.createRegistry(RMIServer.Port);
RMIServer s = new RMIServerImpl();
Naming.rebind(RMIServer.Name, s);
log.info("rmiStart successful.");
} catch (Exception e) {
log.error("During rmiStart", e);
}
}