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分享ajax与.net问题，急等，请救援
function GetData()
{
var xmlReceive=createAjaxObj();
try{
//xmlReceive.abort();
xmlReceive.open("GET","~/setting/mytest1.aspx?action=inithtml&ID=13",true);
xmlReceive.setRequestHeader("Content-type", "text/html;charset=gb2312");
xmlReceive.setRequestHeader("If-Modified-Since","0");
xmlReceive.setRequestHeader("Content-length", 0);
xmlReceive.setRequestHeader("Connection", "close");
xmlReceive.onreadystatechange=function ShowComment1()
{
if(xmlReceive.readyState==4 && xmlReceive.status==200)
$("ShowData").innerHTML=xmlReceive.responseText;
}
xmlReceive.send(null);
}catch(ex){}
}
如上，小弟想在test.htm文件加裁时，向服务器请求数据，test.htm如下：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<body onload ="javascript:GetData();" >
。。。
现在的问题是xmlReceive.status的值经测试后为3，xmlTeceive.readyState=4正常，xmlReceive.statusText=unknown
亦即请求后，返回不了数据，是何问题？
补充：我现在的环境是VS2005+sqlServer2005！
{
var xmlReceive=createAjaxObj();
try{
//xmlReceive.abort();
xmlReceive.open("GET","~/setting/mytest1.aspx?action=inithtml&ID=13",true);
xmlReceive.setRequestHeader("Content-type", "text/html;charset=gb2312");
xmlReceive.setRequestHeader("If-Modified-Since","0");
xmlReceive.setRequestHeader("Content-length", 0);
xmlReceive.setRequestHeader("Connection", "close");
xmlReceive.onreadystatechange=function ShowComment1()
{
if(xmlReceive.readyState==4 && xmlReceive.status==200)
$("ShowData").innerHTML=xmlReceive.responseText;
}
xmlReceive.send(null);
}catch(ex){}
}
如上，小弟想在test.htm文件加裁时，向服务器请求数据，test.htm如下：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<body onload ="javascript:GetData();" >
。。。
现在的问题是xmlReceive.status的值经测试后为3，xmlTeceive.readyState=4正常，xmlReceive.statusText=unknown
亦即请求后，返回不了数据，是何问题？
补充：我现在的环境是VS2005+sqlServer2005！
...全文
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kldx5092 2009-06-18
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xmlReceive.open("GET","~/setting/mytest1.aspx?action=inithtml&ID=13",true);
url中~换成.或者..试试
url中~换成.或者..试试
yanm7788 2009-06-18
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xmlReceive.open("GET","~/setting/mytest1.aspx?action=inithtml&ID=13",true);
这里能取到值吗?
这里能取到值吗?
修改一下昵称 2009-06-18
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帮顶。
wts_net 2009-06-18
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帮顶。
walkghost 2009-06-18
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xmlReceive.open("GET","~/setting/mytest1.aspx?action=inithtml&ID=13",true);
xmlReceive.open("GET","../setting/mytest1.aspx?action=inithtml&ID=13",true);
xmlReceive.open("GET","../setting/mytest1.aspx?action=inithtml&ID=13",true);
psy0324 2009-06-17
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建议楼主用Jquery 实现AJax效果 很容易。。。。
xutongfu 2009-06-16
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我试过了，还是不对哦！
maddemon 2009-06-16
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是不是你的ContextType有问题啊？ application/x-www-form-urlencoded
