汇编基础问题！50分相送！

[ynkmhp]

代码：
dat segment
db 49,56,100,95,63,75,84,59,60,64,69,70,100,98,72,61,59,82,75,51
s1 db 0
s2 db 0
s3 db 0
s4 db 0
s5 db 0
s6 db 0
dat ends
cod segment
assume cs:cod,ds:dat
start :mov ax,dat
mov ds,ax
mov bx,0
mov cx,20
s1: mov al,[bx]
cmp al,60
jae next1
inc inc s1
next1:inc bx
loop s1

mov bx,0
mov cx,20
s2: mov al,[bx]
cmp al,60
jb next2
cmp 69
ja next2
inc inc s2
next2: inc bx
loop s2

mov bx,0
mov cx,20
s3: mov al,[bx]
cmp al,70
jb next3
cmp 79
ja next3
inc inc s3
next3: inc bx
loop s3

mov bx,0
mov cx,20
s4: mov al,[bx]
cmp al,80
jb next4
cmp 89
ja next4
inc inc s4
next4: inc bx
loop s4

mov bx,0
mov cx,20
s5: mov al,[bx]
cmp al,90
jb next4
cmp 99
ja next5
inc inc s5
next5: inc bx
loop s5

mov bx,0
mov cx,20
s6: mov al,[bx]
cmp al,100
jnz next6
inc inc s6
next6: inc bx
loop s6

mov ah,4c00h
int 21
cod ends
end start
编译obj文件报错：
11.ASM(3): error A2024: Segment parameters are changed
11.ASM(4): error A2024: Segment parameters are changed
11.ASM(5): error A2024: Segment parameters are changed
11.ASM(6): error A2024: Segment parameters are changed
11.ASM(7): error A2024: Segment parameters are changed
11.ASM(8): error A2024: Segment parameters are changed
11.ASM(16): error A2024: Segment parameters are changed
11.ASM(19): error A2009: Symbol not defined: INC
11.ASM(21): error A2026: Reference to multidefined symbol
11.ASM(25): error A2024: Segment parameters are changed
11.ASM(28): error A2056: Immediate mode illegal
11.ASM(30): error A2009: Symbol not defined: INC
11.ASM(31): error A2006: Phase error between passes
11.ASM(32): error A2026: Reference to multidefined symbol
11.ASM(36): error A2024: Segment parameters are changed
11.ASM(39): error A2056: Immediate mode illegal
11.ASM(41): error A2009: Symbol not defined: INC
11.ASM(42): error A2006: Phase error between passes
11.ASM(43): error A2026: Reference to multidefined symbol
11.ASM(47): error A2024: Segment parameters are changed
11.ASM(50): error A2056: Immediate mode illegal
11.ASM(52): error A2009: Symbol not defined: INC
11.ASM(53): error A2006: Phase error between passes
11.ASM(54): error A2026: Reference to multidefined symbol
11.ASM(58): error A2024: Segment parameters are changed
11.ASM(61): error A2056: Immediate mode illegal
11.ASM(63): error A2009: Symbol not defined: INC
11.ASM(64): error A2006: Phase error between passes
11.ASM(65): error A2026: Reference to multidefined symbol
11.ASM(69): error A2024: Segment parameters are changed
11.ASM(72): error A2009: Symbol not defined: INC
11.ASM(74): error A2026: Reference to multidefined symbol
11.ASM(76): error A2050: Value out of range

50466 + 450030 Bytes symbol space free

0 Warning Errors
33 Severe Errors
大侠们帮帮忙！谢谢

[ufofind]

我靠你的错误也太多了
inc inc s1 你好好看一下书没有此类指令

[killbug2004]

data segment 
	db 49,56,100,95,63,75,84,59,60,64,69,70,100,98,72,61,59,82,75,51 
	c1 db 0 
	c2 db 0 
	c3 db 0 
	c4 db 0 
	c5 db 0 
	c6 db 0 
data ends 
	code segment 
	assume cs:code,ds:data 
start :
	mov  	ax,data 
	mov  	ds,ax 
	mov  	bx,0 
	mov  	cx,20 
s1:
	mov  	al,[bx] 
	cmp  	al,60 
	jae  	next1 
	inc  	c1
next1:
	inc    	bx 
	loop  	s1 
	
	mov  	bx,0 
	mov  	cx,20 
s2:
	mov  	al,[bx] 
	cmp  	al,60 
	jb   	next2 
	cmp  	al,69 
	ja   	next2 
	inc  	c2
next2:
	inc    	bx 
	loop  	s2 
	
	mov  	bx,0 
	mov  	cx,20 
s3:
	mov  	al,[bx] 
	cmp    	al,70 
	jb      next3 
	cmp    	al,79 
	ja      next3 
	inc	c3
next3:
	inc    	bx 
	loop   	s3 
	
	mov   	bx,0 
	mov   	cx,20 
s4:
	mov   	al,[bx] 
	cmp   	al,80 
	jb    	next4 
	cmp    	al,89 
	ja      next4 
	inc 	c4
next4:
	inc    	bx 
	loop  	s4 
	
	mov  	bx,0 
	mov  	cx,20 
s5:
	mov  	al,[bx] 
	cmp    	al,90 
	jb      next4 
	cmp  	al,99 
	ja      next5 
	inc	c5
next5:
	inc    	bx 
	loop  	s5 
	
	mov  	bx,0 
	mov  	cx,20 
s6:
	mov  	al,[bx] 
	cmp    	al,100 
	jnz     next6 
	inc	c6
next6:
	inc    	bx 
	loop  	s6 
	
	mov 	ax,4c00h 
	int 	21h
code ends 
end start 

还有bug 自己改改

[Tippisum]

我不知道你用什么编译器
我使用MASM6.14编译
Segment parameters are changed
不知道是为什么（我编译时没有）

symbol redefinition
s1-s6被你做了两次标号。
当然因此还带来了一些附加错误。

syntax error:inc
inc指令错误（你连写了两个inc）
cmp指令错误（你只给了一个操作数）

[buzuibuxiu]

本题别人已经帮你解决，但是算法上面还有很大的缺陷
你可以先将原数除以十并取其商，然后再减去5，将用来存储不及格的个数的
变量的编译地址传给DI然后直接用刚才所得到的结果加上DI将现在偏移地址里面的数值加一，将会在很大程度上
提高程序效率，减低储蓄的复杂度，有兴趣的话可以实现一下啊！

[simon_14]

data segment
score db 49,56,100,95,63,75,84,59,60,64,69,70,100,98,72,61,59,82,75,51
len db $-score
s6 dw 0
s7 dw 0
s8 dw 0
s9 dw 0
s10 dw 0
data ends

sta segment stack
dw 100h dup(?)
top label word
sta ends

code segment
assume cs:code,ds:data,ss:sta
main proc far
mov ax,sta
mov ss,ax
lea sp,top
push ds
xor ax,ax
push ax
mov ax,data
mov ds,ax

lea si,score
mov cl,len
xor ch,ch
l1: mov al,[si]
xor ah,ah
mov bl,10
div bl
cmp al,6
je l6
cmp al,7
je l7
cmp al,8
je l8
cmp al,9
je l9
cmp al,10
je l10
l2: inc si
loop l1
lea si,s6
mov cx,5
l3: mov dl,[si]
add dl,30H
mov ah,2
int 21h
add si,2
loop l3
ret
l6:
lea di,s6
inc word ptr [di]
jmp l2
l7:
lea di,s7
inc word ptr [di]
jmp l2
l8:
lea di,s8
inc word ptr [di]
jmp l2
l9:
lea di,s9
inc word ptr [di]
jmp l2
l10:
lea di,s10
inc word ptr [di]
jmp l2

main endp
code ends
end main

[mary0208]

学习

[nanlingcg]

到处都是s1.s2...s(n).编译器都被你搞糊了。不知那个s(n)对应那个s(n)...