写一个方法，找出数组中相同的数字和个数

[yezilove7374521]

一个数组中找出相同数字和个数

[coolyama]

#include <vector>
#include <iostream>
#include <algorithm>

using namespace std;

vector<int> int_vec;
vector<int> int_vec_backup;

void my_count() {
	for ( vector<int>::const_iterator iter = int_vec.begin();iter != int_vec.end(); ++iter ) {
		if ( int_vec_backup.end() == find( int_vec_backup.begin(), int_vec_backup.end(), *iter ) ) {
			cout << *iter << "appears" << count( int_vec.begin(), int_vec.end(), *iter ) << "time(s)" << endl;
			int_vec_backup.push_back( *iter );
		}
		else {
			// nothing to do.
		}
	}

}
int main()
{
	int n = 0;
	cout << "please input next number :" << endl;
	while ( cin >> n ) {
		cout << "please input next number :" << endl;
		int_vec.push_back( n );
	}
	my_count();
	system( "pause" );
	return 0;
}

一开始会提出输入数字，输入\n程序会停止要求输入数字并打印相同数字的个数。

[超级管理员9527]

use std::map<int, int> number-count