菜鸟一个问题问两遍--郁闷

[Emert_Hill]

#include "stdafx.h"
#include <iostream>
#include <string>

int main()
{
using namespace std;
struct car
{
string Manufacturer;
int ProductionYear;
};

cout << "How many cars do you wish to catalog ? ";
int n;
cin >> n;
car * cars = new car[n];
for(int i= 0;i < n; i++)
{
cout << "car #"<< i + 1 << ":\n" << "please enter the make:";
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？
cout << "please enter the year made:";
cin >> cars[i].ProductionYear;
};
cout << "Here is your collection:\n";
for(int i= 0;i < n; i++)
cout << cars[i].ProductionYear << "\t" << cars[i].Manufacturer << endl;
};

[lingyin55]

for(int i= 0;i < n; i++)
{
cout < < "car #" < < i + 1 < < ":\n" < < "please enter the make:";
fflush(stdin);///加个清空缓冲的操作试试
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？
cout < < "please enter the year made:";
cin >> cars[i].ProductionYear;
};

[Emert_Hill]

[Quote=引用 1 楼 lingyin55 的回复:]
for(int i= 0;i < n; i++)
{
cout < < "car #" < < i + 1 < < ":\n" < < "please enter the make:";
fflush(stdin);///加个清空缓冲的操作试试
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？
cout < < "please enter the year made:";
cin >> cars[i].ProductionYear;
};
[/Quote]
貌似无效啊！！！

[lingyin55]

for(int i= 0;i < n; i++)
{
cout << "car #" << i + 1 << endl << "please enter the make:";
fflush(stdin);///
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？
cout << "please enter the year made:";
fflush(stdin);////////////
cin >> cars[i].ProductionYear;
};

[liao05050075]

#include "stdafx.h" 
#include <iostream> 
#include <string> 

int main() 
{ 
using namespace std; 
struct car 
{ 
string Manufacturer; 
int ProductionYear; 
}; 

cout << "How many cars do you wish to catalog ? "; 
int n; 
    cin >> n; 
	
car * cars = new car[n]; 
for(int i= 0;i < n; i++) 
{ 
cout << "car #" << i + 1 << ":\n" << "please enter the make:"; 
	getchar();getchar();
    getline(cin,cars[i].Manufacturer);  // 执行到此处，未等待输入，直接执行下一行，为什么？ 
    cout << "please enter the year made:"; 
    cin >> cars[i].ProductionYear; 
}; 
cout << "Here is your collection:\n"; 
    for(i= 0;i < n; i++) 
cout << cars[i].ProductionYear << "\t" << cars[i].Manufacturer << endl; 
};

[Emert_Hill]

[Quote=引用 3 楼 lingyin55 的回复:]
for(int i= 0;i < n; i++)
{
cout < < "car #" < < i + 1 < < endl < < "please enter the make:";
fflush(stdin);///
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？
cout < < "please enter the year made:";
fflush(stdin);////////////
cin >> cars[i].ProductionYear;
};
[/Quote]
确实见效，高手能给解释下吗？

[Emert_Hill]

[Quote=引用 4 楼 liao05050075 的回复:]
C/C++ code
#include "stdafx.h"
#include <iostream>
#include <string>

int main()
{
using namespace std;
struct car
{
string Manufacturer;
int ProductionYear;
};

cout << "How many cars do you wish to catalog ? ";
int n;
cin >> n;

car * cars = new car[n];
for(int i= 0;i < n; i++)
{
cout << "car #" << i + 1 << ":\n" << "please enter the make:";
…
[/Quote]
貌似这样也可以，能解释一下吗？谢谢！！

[liao05050075]

因为你的上一次输入之后，残留了一个回车下来。
之后你再getline就不会停，只读到一个回车

[Emert_Hill]

[Quote=引用 7 楼 liao05050075 的回复:]
因为你的上一次输入之后，残留了一个回车下来。
之后你再getline就不会停，只读到一个回车
[/Quote]
谢谢啊，看来不实践即使看书看到了也想不起来啊，多谢你了!!!

[lixing01]

#include "stdafx.h"
#include <iostream>
#include <string>

int main()
{
using namespace std;
struct car
{
string Manufacturer;
int ProductionYear;
};

cout < < "How many cars do you wish to catalog ? ";
int n;
cin >> n; // cin获得输入的数据，换行符仍留在输入流中
car * cars = new car[n];
for(int i= 0;i < n; i++)
{
cout < < "car #" < < i + 1 < < ":\n" < < "please enter the make:";
//因为前面的cin获得输入后把换行符留在了输入流中，所以下面的getline相当于获得了一个空行
while (cin.get() != '\n') //先清除输入流中的所有字符，包括换行符
continue;
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？

cout < < "please enter the year made:";
cin >> cars[i].ProductionYear;
};
cout < < "Here is your collection:\n";
for(int i= 0;i < n; i++)
cout < < cars[i].ProductionYear < < "\t" < < cars[i].Manufacturer < < endl;
};

[lixing01]

#include "stdafx.h"
#include <iostream>
#include <string>

int main()
{
using namespace std;
struct car
{
string Manufacturer;
int ProductionYear;
};

cout < < "How many cars do you wish to catalog ? ";
int n;
cin >> n; // cin获得输入的数据，换行符仍留在输入流中
car * cars = new car[n];
for(int i= 0;i < n; i++)
{
cout < < "car #" < < i + 1 < < ":\n" < < "please enter the make:";
//因为前面的cin获得输入后把换行符留在了输入流中，所以下面的getline相当于获得了一个空行
while (cin.get() != '\n') //先清除输入流中的所有字符，包括换行符
continue;
getline(cin,cars[i].Manufacturer); // 执行到此处，未等待输入，直接执行下一行，为什么？

cout < < "please enter the year made:";
cin >> cars[i].ProductionYear;
};
cout < < "Here is your collection:\n";
for(int i= 0;i < n; i++)
cout < < cars[i].ProductionYear < < "\t" < < cars[i].Manufacturer < < endl;
};

[yangkunhenry]

#include <iostream> 
#include <string> 
using namespace std;
int main() 
{ 
	using namespace std; 
	struct car 
	{ 
		string Manufacturer; 
		int ProductionYear; 
	}; 

	cout << "How many cars do you wish to catalog ? "; 
	int n; 
	cin >> n; 
	cin.ignore();			//Here
	car * cars = new car[n]; 
	for(int i= 0;i < n; i++) 
	{ 
		cout << "car #" << i + 1 << ":\n" << "please enter the make:"; 
		getline(cin,cars[i].Manufacturer);  // 执行到此处，未等待输入，直接执行下一行，为什么？ 
		cout << "please enter the year made:"; 
		cin >> cars[i].ProductionYear; 
		cin.ignore();		//Here
	}; 
	cout << "Here is your collection:\n"; 
	for(int i= 0;i < n; i++) 
		cout << cars[i].ProductionYear << "\t" << cars[i].Manufacturer << endl; 
};
//cin.ignore()这个方法用于将cin对象中缓冲区的部份字符丢弃,缺省状态是丢一个字符
//这个地方丢弃了你的回车符