求一SQL语句，分组合并，详情见内

[lzy6204]

数据：
======================
CardNo CardName
----------------------
001 AA
001 BB
001 CC
002 DD
002 EE
003 FF


结果
====================
CardNo CardName
--------------------
001 AA BB CC
002 DD EE
003 FF

SQL2000或SQL2005，谢谢！

[lzy6204]

CardName 用空格隔开
帮顶有分，谢谢

[usher_gml]

合并列值 
--*******************************************************************************************
表结构，数据如下： 
id    value 
----- ------ 
1    aa 
1    bb 
2    aaa 
2    bbb 
2    ccc 

需要得到结果： 
id    values 
------ ----------- 
1      aa,bb 
2      aaa,bbb,ccc 
即：group by id, 求 value 的和（字符串相加） 

1. 旧的解决方法(在sql server 2000中只能用函数解决。) 
--=============================================================================
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
--1. 创建处理函数 
CREATE FUNCTION dbo.f_strUnite(@id int) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ',' + value FROM tb WHERE id=@id 
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 
-- 调用函数 
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id 
drop table tb 
drop function dbo.f_strUnite 
go
/* 
id          value      
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
（所影响的行数为 2 行） 
*/ 
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
-- 查询处理 
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( 
        SELECT [values]= STUFF(REPLACE(REPLACE( 
            ( 
                SELECT value FROM tb N 
                WHERE id = A.id 
                FOR XML AUTO 
            ), ' <N value="', ','), '"/>', ''), 1, 1, '') 
)N 
drop table tb 

/* 
id          values 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 行受影响) 
*/ 

--SQL2005中的方法2 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') 
from tb 
group by id 

/* 
id          values 
----------- -------------------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 row(s) affected) 

*/ 

drop table tb 



本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/usher_gml/archive/2009/04/27/4128092.aspx

[--小F--]

SQL code问题描述：
无论是在sql 2000，还是在 sql 2005 中,都没有提供字符串的聚合函数，
  所以，当我们在处理下列要求时，会比较麻烦：
有表tb, 如下：
id    value
----- ------
1     aa
1     bb
2     aaa
2     bbb
2     ccc
需要得到结果：
id     values
------ -----------
1      aa,bb
2      aaa,bbb,ccc
即， group by id, 求 value 的和（字符串相加）

1. 旧的解决方法

-- 1. 创建处理函数
CREATE FUNCTION dbo.f_str(@id int)
RETURNS varchar(8000)
AS
BEGIN
    DECLARE @r varchar(8000)
    SET @r = ''
    SELECT @r = @r + ',' + value
    FROM tb
    WHERE id=@id
    RETURN STUFF(@r, 1, 1, '')
END
GO
-- 调用函数

SELECt id, values=dbo.f_str(id) 
FROM tb 
GROUP BY id

-- 2. 新的解决方法 
-- 示例数据
DECLARE @t TABLE(id int, value varchar(10))
INSERT @t SELECT 1, 'aa'
UNION ALL SELECT 1, 'bb'
UNION ALL SELECT 2, 'aaa'
UNION ALL SELECT 2, 'bbb'
UNION ALL SELECT 2, 'ccc'

-- 查询处理
SELECT *
FROM(
    SELECT DISTINCT 
        id
    FROM @t
)A
OUTER APPLY(
    SELECT 
        [values]= STUFF(REPLACE(REPLACE(
            (
                SELECT value FROM @t N
                WHERE id = A.id
                FOR XML AUTO
            ), '<N value="', ','), '"/>', ''), 1, 1, '')
)N

/*--结果
id          values
----------- ----------------
1           aa,bb
2           aaa,bbb,ccc
(2 行受影响)
--*/

[wgqqgw]

如果表数据量不是非常大的话，用游标吧。

[playwarcraft]

合併？？

Create table T(id int,name varchar(10))
insert into T select 1,'A'
insert into T select 1,'B'
insert into T select 2,'C'
insert into T select 3,'D'
insert into T select 3,'E'
GO

--sql 2000 function
Create function dbo.fn_test(@id int)
returns varchar(100)
as
begin
declare @return varchar(100)
set @return=''
select @return=@return+','+rtrim(name) from T where id=@id

set @return=stuff(@return,1,1,'')
return @return
end
GO
select id,dbo.fn_test(id) as [name] from T group by id

--sql 2000 臨時表
Create proc dbo.usp_test
as
select id,convert(varchar(100),name) as [name]
into #temp from T 
order by id

declare @id int,@name varchar(100)

update #temp
set @name=case when id=@id then @name+','+rtrim(name)
			else rtrim(name)
			end,
    @id=id,
    name=@name

select A.*
from #temp A
inner join
  (
   select id,max(len(name)) as name_len
   from #temp
   group by id
   ) B
on A.id=B.id and len(A.name)=B.name_len

GO

exec usp_test

GO

--SQL2005

select A.id,B.name_together
from 
 (select distinct id from T) as A
outer apply
  (select stuff (replace(replace((select [name] from T where id=A.id for XML auto),'<T name="',','),'"/>',''),1,1,'') as [name_together]
   ) as B


drop table T
drop function dbo.fn_test
drop proc usp_test

[ai_li7758521]

--合并分拆表
/********************************************************
合并分拆表数据

整理人：中国风(Roy)

日期:2008.06.06
*********************************************************/

--> --> (Roy)生成測試數據
 
if not object_id('Tab') is null
    drop table Tab
Go
Create table Tab([Col1] int,[Col2] nvarchar(1))
Insert Tab
select 1,N'a' union all
select 1,N'b' union all
select 1,N'c' union all
select 2,N'd' union all
select 2,N'e' union all
select 3,N'f'
Go

select * from Tab
--合并表:

SQL2000用函数:

go
if object_id('F_Str') is not null
    drop function F_Str
go
create function F_Str(@Col1 int)
returns nvarchar(100)
as
begin
    declare @S nvarchar(100)
    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1
    return @S
end
go

Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab
go


/*        STUFF学习

SELECT STUFF('abcdef', 2, 3, 'ijklmn')
SELECT STUFF('abcdef', 2, 1, 'ijklmn')
SELECT STUFF('abcdef', 2, 0, 'ijklmn')
SELECT STUFF('abcdef', 1, 0, 'ijklmn')
GO*/
           

/***********************************
SQL2005用XML:
***********************************/
--方法1:

select 
    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')
from 
    (select distinct COl1 from Tab) a
Cross apply
    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b

方法2:

select 
    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))
from 
    (select distinct COl1 from Tab) a
cross apply
    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)
                .query('<Tab>
                {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}
                {concat("",string(/Tab[last()]/@COl2))}
                </Tab>')
                )b

SQL05用CTE:

;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
,Roy2 as
(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 
union all 
select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)


生成结果:
/*
Col1        COl2
----------- ------------
1           a,b,c
2           d,e
3           f

(3 行受影响)
*/

[jiangshun]

if object_id('[tb]') is not null drop table [tb]
create table [tb]([CardNo] varchar(3),[CardName] varchar(2))
insert [tb]
select '001','AA' union all
select '001','BB' union all
select '001','CC' union all
select '002','DD' union all
select '002','EE' union all
select '003','FF'

CREATE FUNCTION dbo.f_strUnite(@CardNo varchar(20)) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ' ' + CardName FROM tb WHERE CardNo=@CardNo
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 

select CardNo,CardName=dbo.f_strUnite(CardNo) from tb group by CardNo

/*
CardNo CardName                                                                                                                                                                                                                                                         
------ ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 
001    AA BB CC
002    DD EE
003    FF

（所影响的行数为 3 行）
*/

[feixianxxx]

[Quote=引用 7 楼 jiangshun 的回复:]
SQL code
if object_id('[tb]') is not null drop table [tb]
create table [tb]([CardNo] varchar(3),[CardName] varchar(2))
insert [tb]
select '001','AA' union all
select '001','BB' union all
select '001','CC' union all
select '002','DD' union all
select '002','EE' union all
select '003','FF'

CREATE FUNCTION dbo.f_strUnite(@CardNo varchar(20))
RETURNS varchar(8000)
AS
BEGIN
DE…
[/Quote]
UP 字符合并 太多了

[usher_gml]

create table tb (CardNo int,CardName varchar(10))
insert tb
select 001,        'AA' union all
select 001,        'BB' union all
select 001,        'CC' union all
select 002,        'DD' union all
select 002,        'EE' union all
select 003,        'FF'
go
CREATE FUNCTION dbo.f_tb(@id int) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ' ' + CardName FROM tb WHERE CardNo=@id 
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 

SELECT CardNo, CardName = dbo.f_tb(CardNo) FROM tb GROUP BY CardNo 
drop table tb 
drop function dbo.f_tb 
go

[ai_li7758521]

CREATE TABLE tb(CardNo nvarchar(10),CardName nvarchar(10))
insert tb
SELECT 001,'AA' UNION ALL
SELECT 001,'BB' UNION ALL 
SELECT 001,'CC' UNION ALL
SELECT 002,'DD' UNION ALL 
SELECT 002,'EE' UNION ALL
SELECT 002,'FF'


if object_id('F_Str') is not null
    drop function F_Str
go
create function F_Str(@Col1 int)
returns nvarchar(100)
as
begin
    declare @S nvarchar(100)
    select @S=isnull(@S+' ','')+CardName from tb where CardNo=@Col1
    return @S
end
go

Select distinct CardNo,Col2=dbo.F_Str(CardNo) from tb
go

CardNo     Col2
---------- ---------------
1          AA BB CC
2          DD EE FF

(2 行受影响)

[--小F--]

----------------------------------------------------------------
-- Author :fredrickhu(小F 向高手学习)
-- Date   :2009-06-23 11:14:19
----------------------------------------------------------------
--> 测试数据：[tb]
if object_id('[tb]') is not null drop table [tb]
create table [tb]([CardNo] varchar(3),[CardName] varchar(2))
insert [tb]
select '001','AA' union all
select '001','BB' union all
select '001','CC' union all
select '002','DD' union all
select '002','EE' union all
select '003','FF'
--------------开始查询--------------------------
CREATE FUNCTION dbo.f_strUnite(@CardNo varchar(20)) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ' ' + CardName FROM tb WHERE CardNo=@CardNo
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 

select CardNo,CardName=dbo.f_strUnite(CardNo) from tb group by CardNo
drop table tb 
drop function dbo.f_strUnite 
go
----------------结果----------------------------
/*
CardNo CardName                                                                                                                                                                                                                                                         
------ ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 
001    AA BB CC
002    DD EE
003    FF
*/

[数字化从业者老高]

以上都很多了。
总结一下：
1、如果是SQL2000，那么只有一种方法，用自定义函数来实现。
2、如果是2005，两种方式，一种是XML，一种是CTE。

[lzy6204]

testing……

[zuzuou]

如果数据量很大，游标是肯定慢的，不建议使用。
如果可以确定每个CardNo最多可能有多少个值，可以用下面的语句来实现:
假设每个cardno最多可能有5个值，
select cardno
,max(case when id=1 then CardName end)+
max(case when id=2 then CardName end)+
max(case when id=3 then CardName end)+
max(case when id=4 then CardName end)+
max(case when id=5 then CardName end)
as CardName
from
(
select cardno
, CardName
,rank() over(cardno order by CardName ) as id--此处rank函数具体的语法不记得了
from tb
)a