jspt跳转servlet问题

[jxndsujing]

<form name="form1" action="/servlet/UserServlet" method="post" onSubmit="return check(form1)">
<p>
用户名：<input type="text" name="username" value=""/>
</p>
<p>
密码：<input type="password" name="pwd1" value=""/>
</p>
<p>
确认密码：<input type="password" name="pwd2" value=""/>
</p>
<p>
邮箱：<input type="text" name="eamil" value="" onBlur="isEmail(this.value)"/>
</p>
<p>
确认邮箱：<input type="text" name="reamil" value=""/>
</p>
<input type="submit" value="注册"/>
</form>


web.xml



<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>UserServlet</servlet-name>
<servlet-class>/servlet/UserServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UserServlet</servlet-name>
<url-pattern>/servlet/UserServlet</url-pattern>
</servlet-mapping>

报错：
HTTP Status 404 - /servlet/UserServlet

--------------------------------------------------------------------------------

type Status report

message /servlet/UserServlet

description The requested resource (/servlet/UserServlet) is not available.


--------------------------------------------------------------------------------

Apache Tomcat/6.0.16



控制台什么信息都没打印

[sangshusen_1988]

你把method修改成get看看路径提交到哪里了？应该是/localhost:8080/servlet/UserServlet这个路径了，
在路径上加上工程名应该就好了

[fys249931556]

<servlet-class>/servlet/UserServlet </servlet-class>


这里错误，应该写包的路径，而不是URL地址。。

看下Servlet基础。