怎么把这段javascript函数转换成C#...

[gmkiy121]

function GetNum( Num_A, Num_B){
var out_Num=new Array();
var line,aRatio,nowRatio,bRatio;
var nowType="";
if (Num_A <= 1000 && Num_B <= 1000){
out_Num[0]=Num_A;
out_Num[1]=Num_B;
return out_Num;
}
line=2000 - ( Num_A + Num_B );
if (Num_A > Num_B){
aRatio=Num_B;
nowType="a"
}else{
aRatio = Num_A;
nowType="b"
}
if (((2000 - line) - aRatio) > 1000){

nowRatio = (aRatio + line) * (-1);
}else{

nowRatio=(2000 - line) - aRatio;
}
if (nowRatio < 0){
bRatio = Math.floor(Math.abs(1000 / nowRatio) * 1000) ;
}else{
bRatio = (2000 - line - nowRatio) ;
}
if (nowType == "a"){
out_Num[0]=aRatio;
out_Num[1]=bRatio;
}else{
out_Num[0]=bRatio;
out_Num[1]=aRatio;
}
return out_Num;
}
请教下.怎么把这段javascript函数转换成C#...

[我姓区不姓区]

逻辑及语法都很简单易懂啊，为什么不自己尝试一下呢

public int[] GetNum(int Num_A, int Num_B)
{
    int[] out_Num = new int[2];
    int line,aRatio,nowRatio,bRatio; 
    string nowType=""; 
    if (Num_A <= 1000 && Num_B <= 1000)
    { 
        out_Num[0] = Num_A;
        out_Num[1] = Num_B;
        return out_Num;
    } 
    line=2000 - ( Num_A + Num_B ); 
    aRatio = Math.Min(Num_A, Num_B);
    nowType = Num_A > Num_B ? "a" : "b";
    if (((2000 - line) - aRatio) > 1000)
         nowRatio = (aRatio + line) * (-1); 
    else
        nowRatio=(2000 - line) - aRatio; 
    if (nowRatio < 0)
        bRatio = (int)Math.Floor(Math.Abs(1000 / nowRatio) * 1000) ; 
    else
        bRatio = (2000 - line - nowRatio) ; 
    if (nowType == "a")
    { 
        out_Num[0]=aRatio;
        out_Num[1]=bRatio; 
    }
    else
    {
        out_Num[0]=bRatio;
        out_Num[1]=aRatio; 
    }
    return out_Num; 
}