请教一下结构体赋值的问题

[a6610293847]

typedef struct _HOST_INFORMATION{
ULONG Address;
USHORT Port;
USHORT HostNameLength;
UCHAR HostName[256];
} HOST_INFORMATION, *PHOST_INFORMATION;
int main()
{
PHOST_INFORMATION inf;
inf = (HOST_INFORMATION *)malloc(sizeof(HOST_INFORMATION)+strlen("192.168.205.42"));
memset(
inf,
0,
sizeof(HOST_INFORMATION) + strlen("192.168.205.42")
);
inf->Port = 2009;
inf->Address = inet_addr("192.168.205.42");
char *FileName = "192.168.0.1";
strcpy(inf->FileName, FileName);
printf("%s\n",inf->FileName);
//如果是.cpp文件提示'strcpy' : cannot convert parameter 1 from 'unsigned char [1]' to 'char *'
//如果是.c文件就能正确运行
}
为什么上面的程序在C中能运行，而在C++中会提示错误呢？是不是编译方式不同导致的呢？那在cpp中如何改写赋值呢?

[I_NBFA]

C++对类型的转换要求更严格，编译器不允许直接将unsigned char[]/*直接转换为char*,
用reinterpret_case强制一下吧．
另外你HOST_INFORMATION里没FileName啊？
unsigned char[1]才1个字节，拷过去就非法访问了．

[jingzhongrong]

PHOST_INFORMATION inf;
inf = (HOST_INFORMATION *)malloc(sizeof(HOST_INFORMATION));
memset(inf,0,sizeof(HOST_INFORMATION));
inf->Port = 2009;
inf->Address = inet_addr("192.168.205.42");
char *FileName = "192.168.0.1";
strcpy(inf->HostName, (UCHAR)FileName);

[xylicon]

C++的程序强制转换一下就是了。

strcpy((char*)(inf->HostName), FileName);

[MoXiaoRab]

strcpy(inf->HostName, (UCHAR)FileName);

[Ghost90]

#include <windows.h>  //要加这个头文件


typedef struct _HOST_INFORMATION{ 
    ULONG  Address; 
    USHORT  Port; 
    USHORT  HostNameLength; 
    UCHAR  HostName[256]; 
} HOST_INFORMATION, *PHOST_INFORMATION; 

void main() 
{ 
	PHOST_INFORMATION inf; 
	inf = (HOST_INFORMATION *)malloc(sizeof(HOST_INFORMATION)+strlen("192.168.205.42")); 
	memset( 
		inf, 
		0, 
		sizeof(HOST_INFORMATION) + strlen("192.168.205.42") 
		); 
	inf->Port = 2009; 
	//inf->Address = inet_addr("192.168.205.42");   注释掉因为inet_addr 函数需要一个Socket的静态库
	char *FileName = "192.168.0.1"; 
	strcpy((char*)inf->HostName, FileName); //这个地方要强制转化下
	printf("%s\n",inf->HostName); 
	//如果是.cpp文件提示'strcpy' : cannot convert parameter 1 from 'unsigned char [1]' to 'char *' 
	//如果是.c文件就能正确运行 

} 

[xy_dream]

strcpy(inf->FileName, FileName);
是不是错了,结构体中没有FileName呀,
是不是inf->HostName
强制转换一下
strcpy((char*)inf->FileName, FileName);

[danxuezx]

基本上是类型转换的问题，c++是强类型语言。解决方法如楼上几位所说。

[andylauxing]

新手上路,看不懂

[a6610293847]

非常感谢大家的指点,结贴给分！！！