java写的猜数字游戏

[xtuxucj]

java写的猜数字游戏。没有实现GUI界面，只能在Eclipse控制台输入玩玩。请各位高人根据源码，指出该程序的不足之处或者代码规范问题

package guessGame;

import java.util.*;
import java.io.*;

public class GuessDigit {
private ArrayList<Integer> digitArray ;
private boolean flag = true;
private static final int SIZE = 4;
private static int count = 7;


public GuessDigit(){
this(GuessDigit.count);
}

public GuessDigit(int count){

GuessDigit.count = count;
digitArray = new ArrayList<Integer>(SIZE);
Random r = new Random();
int n = 0;
while(n < SIZE){

int i = r.nextInt(9);
if(!digitArray.contains(i)){
digitArray.add(n, i);
n ++;
}
}

System.out.println("请输入4个不同的数字，你一共有"+count+"次机会:");
}

public String toString(){
String s = "";
for(int i = 0; i < digitArray.size(); i ++){
s += digitArray.get(i);
}
return s;
}

private void campare(String s){
String array = toString();
int A = 0, B = 0;
char c1, c2;
for(int i = 0 ;i < SIZE; i ++){
c1 = array.charAt(i);
c2 = s.charAt(i);
if(c1 == c2){
A ++;
}else if(array.indexOf(c2) != -1)
B ++;
}

System.out.println(s + " " + A + "A" + B + "B");

if(A == SIZE){
System.out.println("恭喜你猜对了！数字是" + this);
flag = false;
}

if(--count == 0 && A < SIZE ){
System.out.println("已达到规定次数，数字是："+this);
flag = false;
}
}

public void getConsole() throws IOException{
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
String s ;
boolean repeat;
int i;

while(flag){
s = stdin.readLine();
repeat = false;
i = 0;
if(s.matches("\\d{4}")){
while(!repeat && i < SIZE-1){
if(s.lastIndexOf(s.charAt(i)) != i){
System.out.println("请输入4不同的数字:");
repeat = true;
}
i ++;
}
if(!repeat)
campare(s);
}else
System.out.println("请检查输入值的格式:");



}
}

public static void main(String[] args) throws IOException {
GuessDigit g = new GuessDigit(); ;
//System.out.println(g);
g.getConsole();
}
}

[bigbug9002]

哈哈,我的小灵通上有这个小游戏,平时消磨时间时，就玩这个游戏。

楼主能不能把代码重贴一下？没有格式的代码，没有心情看啊。

[zWX19940]

复议

[bigbug9002]

最多7次,应该能猜出来.一般情况下5-6次.再少要看运气了.

[xtuxucj]

已经改不了了，说是有回复，我没权限修改。

[yubangqi]

package guessGame; 

import java.util.*; 
import java.io.*; 

public class GuessDigit { 
private ArrayList <Integer> digitArray ; 
private boolean flag = true; 
private static final int SIZE = 4; 
private static int count = 7; 


public GuessDigit(){ 
this(GuessDigit.count); 
} 

public GuessDigit(int count){ 

GuessDigit.count = count; 
digitArray = new ArrayList <Integer>(SIZE); 
Random r = new Random(); 
int n = 0; 
while(n < SIZE){ 

int i = r.nextInt(9); 
if(!digitArray.contains(i)){ 
digitArray.add(n, i); 
    n ++; 
} 
} 

System.out.println("请输入4个不同的数字，你一共有"+count+"次机会:"); 
} 

public String toString(){ 
String s = ""; 
for(int i = 0; i < digitArray.size(); i ++){ 
s += digitArray.get(i); 
} 
return s; 
} 

private void campare(String s){ 
String array = toString(); 
int A = 0, B = 0; 
char c1, c2; 
for(int i = 0 ;i < SIZE; i ++){ 
c1 = array.charAt(i); 
c2 = s.charAt(i); 
if(c1 == c2){ 
A ++; 
}else if(array.indexOf(c2) != -1) 
B ++; 
} 

System.out.println(s + " " + A + "A" + B + "B"); 

if(A == SIZE){ 
System.out.println("恭喜你猜对了！数字是" + this); 
flag = false; 
} 

if(--count == 0 && A < SIZE ){ 
System.out.println("已达到规定次数，数字是："+this); 
flag = false; 
} 
} 

public void getConsole() throws IOException{ 
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in)); 
String s ; 
boolean repeat; 
int i; 

while(flag){ 
s = stdin.readLine(); 
repeat = false; 
i = 0; 
if(s.matches("\\d{4}")){ 
while(!repeat && i < SIZE-1){ 
if(s.lastIndexOf(s.charAt(i)) != i){ 
System.out.println("请输入4不同的数字:"); 
repeat = true; 
} 
i ++; 
} 
if(!repeat) 
campare(s); 
}else 
System.out.println("请检查输入值的格式:"); 



} 
} 

public static void main(String[] args) throws IOException { 
GuessDigit g = new GuessDigit(); ; 
//System.out.println(g); 
g.getConsole(); 
} 
} 

[yubangqi]

友情帮该

[sunzerui]

楼主，我有个封装好的exe文件。

[dz007]

路过填格式…………

package guessGame;

import java.util.*;
import java.io.*;

public class GuessDigit {
	private ArrayList<Integer> digitArray;
	private boolean flag = true;
	private static final int SIZE = 4;
	private static int count = 7;

	public GuessDigit() {
		this(GuessDigit.count);
	}

	public GuessDigit(int count) {

		GuessDigit.count = count;
		digitArray = new ArrayList<Integer>(SIZE);
		Random r = new Random();
		int n = 0;
		while (n < SIZE) {

			int i = r.nextInt(9);
			if (!digitArray.contains(i)) {
				digitArray.add(n, i);
				n++;
			}
		}

		System.out.println("请输入4个不同的数字，你一共有" + count + "次机会:");
	}

	public String toString() {
		String s = "";
		for (int i = 0; i < digitArray.size(); i++) {
			s += digitArray.get(i);
		}
		return s;
	}

	private void campare(String s) {
		String array = toString();
		int A = 0, B = 0;
		char c1, c2;
		for (int i = 0; i < SIZE; i++) {
			c1 = array.charAt(i);
			c2 = s.charAt(i);
			if (c1 == c2) {
				A++;
			} else if (array.indexOf(c2) != -1)
				B++;
		}

		System.out.println(s + " " + A + "A" + B + "B");

		if (A == SIZE) {
			System.out.println("恭喜你猜对了！数字是" + this);
			flag = false;
		}

		if (--count == 0 && A < SIZE) {
			System.out.println("已达到规定次数，数字是：" + this);
			flag = false;
		}
	}

	public void getConsole() throws IOException {
		BufferedReader stdin = new BufferedReader(new InputStreamReader(
				System.in));
		String s;
		boolean repeat;
		int i;

		while (flag) {
			s = stdin.readLine();
			repeat = false;
			i = 0;
			if (s.matches("\\d{4}")) {
				while (!repeat && i < SIZE - 1) {
					if (s.lastIndexOf(s.charAt(i)) != i) {
						System.out.println("请输入4不同的数字:");
						repeat = true;
					}
					i++;
				}
				if (!repeat)
					campare(s);
			} else
				System.out.println("请检查输入值的格式:");

		}
	}

	public static void main(String[] args) throws IOException {
		GuessDigit g = new GuessDigit();
		;
		// System.out.println(g);
		g.getConsole();
	}
}

[bigbug9002]

感谢楼上的，我也重排了一下格式。先玩一把：

import java.util.*; 
import java.io.*; 

public class GuessDigit { 
	private ArrayList <Integer> digitArray ; 
	private boolean flag = true; 
	private static final int SIZE = 4; 
	private static int count = 7; 
	
	
	public GuessDigit(){ 
		this(GuessDigit.count); 
	} 
	
	public GuessDigit(int count){ 
		GuessDigit.count = count; 
		digitArray = new ArrayList <Integer>(SIZE); 
		Random r = new Random(); 
		int n = 0; 
		while(n < SIZE){ 
			int i = r.nextInt(9); 
			if(!digitArray.contains(i)){ 
				digitArray.add(n, i); 
				n ++; 
			} 
		}
		
		System.out.println("请输入4个不同的数字，你一共有"+count+"次机会:"); 
	}
	
	public String toString(){ 
		String s = ""; 
		for(int i = 0; i < digitArray.size(); i ++){ 
			s += digitArray.get(i); 
		} 
		return s; 
	}
	private void campare(String s){ 
		String array = toString(); 
		int A = 0, B = 0; 
		char c1, c2; 
		for(int i = 0 ;i < SIZE; i ++){ 
			c1 = array.charAt(i); 
			c2 = s.charAt(i); 
			if(c1 == c2){ 
				A ++; 
			}else if(array.indexOf(c2) != -1) 
			    B ++; 
		} 
		System.out.println(s + " " + A + "A" + B + "B"); 
		if(A == SIZE){ 
			System.out.println("恭喜你猜对了！数字是" + this); 
			flag = false; 
		}
		
		if(--count == 0 && A < SIZE ){ 
			System.out.println("已达到规定次数，数字是："+this); 
			flag = false; 
		}
	}
	public void getConsole() throws IOException{ 
		BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in)); 
		String s ; 
		boolean repeat; 
		int i; 
		while(flag){ 
			s = stdin.readLine(); 
			repeat = false; 
			i = 0; 
			if(s.matches("\\d{4}")){ 
				while(!repeat && i < SIZE-1){ 
					if(s.lastIndexOf(s.charAt(i)) != i){ 
						System.out.println("请输入4不同的数字:"); 
						repeat = true; 
					} 
					i ++; 
				} 
				if(!repeat) 
				campare(s); 
			}else 
			System.out.println("请检查输入值的格式:"); 
		}
	}
	
	public static void main(String[] args) throws IOException { 
		GuessDigit g = new GuessDigit(); ; 
		//System.out.println(g); 
		g.getConsole(); 
	} 
} 

请输入4个不同的数字，你一共有7次机会:
1234
1234 0A2B
5678
5678 0A1B
0956
0956 0A2B
6078
6078 0A1B
7508
7508 2A0B
2503
2503 4A0B
恭喜你猜对了！数字是2503

[feishare]

不错，先玩两局~~

[bigbug9002]

找到一小BUG，
i = r.nextInt(9);
这个只会产生0～8的随机数，不会产生9

[feishare]

1357
1357 1A1B
2468
2468 1A1B
1458
1458 2A1B
1059
1059 1A0B
4587
4587 1A3B
8457
8457 1A3B
4758
4758 4A0B
恭喜你猜对了！数字是4758

[bigbug9002]

      while (!repeat && i < SIZE - 1) {
                    if (s.lastIndexOf(s.charAt(i)) != i) {
                        System.out.println("请输入4不同的数字:");
                        repeat = true;
                    }
                    i++;
                }

判断四个不同的数字的方法值得学习.

[my_firstlove]

while (!repeat && i < SIZE - 1) {
if (s.lastIndexOf(s.charAt(i)) != i) {
System.out.println("请输入4不同的数字:");
repeat = true;
}
i++;
}

[smallsmallworld]

不错，顶一个