怎么取出多个数组中的相同元素？

[dehong]

$a = array("a","b","c","d");
$b = array("a","x","s","f","g");
$c = array("k","w","a","n","b","x");
$d = array("p","q","j","v","f","x");

我的目的是查个数组元素中相同的值，然后输出数组名与相应的值。如：

$a = $b = $c 值为 a
$a = $c 值为 b
$b = $c = $d 值为 x

……

从第一个数组元素开始查别的数组是否存在这个元素，查完后输出存在这个元素的所有数组名，以及这个元素。

[xiaolei1982]

php里面有现成的取数组交集的函数，不知是否满足你的需要

[wang_feng1984]

array_intersect -- 计算数组的交集

$array1 = array("a" => "green", "red", "blue");
$array2 = array("b" => "green", "yellow", "red");
$result = array_intersect($array1, $array2);


这使得 $result 成为：

Array
(
[a] => green
[0] => red
)

[dzxccsu]

仅仅交集是不够的，下班了，回去看下！

[梁宽]

把数组合并后循环 应该能吧

[billhu001]

1，将各个数组排列组合，然后计算各个组合的交集。
2，对交集函数的结果进行分析，如果有交集就输出当前的数组组合+相同的元素。

应当就能实现你说的功能了。

[阿_布]

<?php
$a = array("a","b","c","d"); 
$b = array("a","x","s","f","g"); 
$c = array("k","w","a","n","b","x"); 
$d = array("p","q","j","v","f","x"); 
$arr_join = array_merge($a,$b,$c,$d);
$arr_uni = array_unique($arr_join);
foreach ($arr_uni as $arr){
	echo "值$arr  ";
	if(in_array($arr,$a)) echo "数组a  ";
	if(in_array($arr,$b)) echo "数组b  ";
	if(in_array($arr,$c)) echo "数组c  ";
	if(in_array($arr,$d)) echo "数组d  ";
	echo "<br>"; 
}
?>

[dehong]

谢谢！大家的帮助，以后我要常来这逛，向大家多学习学习。

[ms_X0828]

到这里是要常来的，自己有什么问题大家可以帮我一起解决，你也可以帮别人解决问题。
这样对提升自己的php努力是有很大的帮助的。

[江南昆虫]

<pre>
<?php
$a = array("a","b","c","d"); 
$b = array("a","x","s","f","g"); 
$c = array("k","w","a","n","b","x"); 
$d = array("p","q","j","v","f","x"); 
$arr_arr = array('a','b','c','d');
$out = array();

for ($i=0;$i<count($arr_arr)-1;$i++){
	foreach (${$arr_arr[$i]} as $v){
		if (!array_key_exists($v,$out)){
			$out[$v][] = '$'.$arr_arr[$i];
			for ($j=$i+1;$j<count($arr_arr);$j++){
				if (in_array($v,${$arr_arr[$j]})) $out[$v][] = '$'.$arr_arr[$j];
			}
		}
	}
}

foreach ($out as $k => $row){
	if (count($row)>1){echo implode(' = ',$row).' 值为 '.$k."\n";}
}
?>
</pre>