java byte转16进制

[dlgz888]

public static final String toHex(byte[] data, int off, int length) {
// double size, two bytes (hex range) for one byte
StringBuffer buf = new StringBuffer(data.length * 2);
for (int i = off; i < length; i++) {
// don't forget the second hex digit
if (((int) data[i] & 0xff) < 0x10) {
buf.append("0");
}
buf.append(Long.toString((int) data[i] & 0xff, 16));
/* if (i < data.length - 1) {
buf.append(" ");
} */
}
return buf.toString().toUpperCase();
}
请问以上方法我把byte数组转成16进制的形式，使用该方法时候如果遇到11字节的数据就会丢失。。请问是什么原因？？

[火龙果被占用了]

public class Test2 {
    
    private final static char[] HEX = "0123456789abcdef".toCharArray();
    
    public static void main(String[] args) {
        byte[] bys = { 0x7e, (byte)0x8f, 0x7c, (byte)0xa9 };
        System.out.println(toHex(bys, 0, 3));
    }
    
    public static String toHex(byte[] bys, int start, int length) {
        if(bys == null || bys.length == 0) {
            throw new IllegalArgumentException("byte array is empty");
        }
        if(start < 0) {
            throw new IllegalArgumentException("start is array index that greater than or equal 0");
        }
        if(length < 1) {
            throw new IllegalArgumentException("length must be greater than 0");
        }
        if(start + length > bys.length) {
            throw new IllegalArgumentException("array max length is " + bys.length);
        }
        char[] chs = new char[length * 2];
        for(int i = start, k = start + length, n = 0; i < k; i++) {
            chs[n++] = HEX[bys[i] >> 4 & 0xf];
            chs[n++] = HEX[bys[i] & 0xf];
        }
        return new String(chs);
    }
}