求一算法

[king2003]

两字符串
"2,3,4,6,7,8,9,10,12,13"
"1,2,3,4,5,6,7,8,9,10,11,12,13"
得到以下字符串
2,3,4
6,7,8,9,10
12,13

[starj1]

???
稀里糊涂中...

[梦里开天]

先提取放入数组
再2层循环判断
只有思路 懒得coding

[wowosbpro]

搞不懂问的啥意思

[wuyi8808]

/*
两字符串
"2,3,4,6,7,8,9,10,12,13"
"1,2,3,4,5,6,7,8,9,10,11,12,13"
得到以下字符串
2,3,4
6,7,8,9,10
12,13
*/

using System;
using System.Collections.Generic;

class Program
{
  static string[] GetStr(string s1, string s2)
  {
    string[] ss = s1.Split(',');
    List<string> ls = new List<string>();

    for (int i = 0; i < ss.Length; i++)
    {
      List<string> li = new List<string>();
      int x, x0;
      int.TryParse(ss[i], out x);
      li.Add(x.ToString());
      x0 = x;
      for (i++; i < ss.Length; i++)
      {
        int.TryParse(ss[i], out x);
        if (x == x0 + 1)
        {
          li.Add(x.ToString());
          x0 = x;
        }
        else { i--; break; }
      }
      ls.Add(string.Join(",", li.ToArray()));
    }
    return ls.ToArray();
  }

  static void Main()
  {
    string s1 = "2,3,4,6,7,8,9,10,12,13";
    string s2 = "1,2,3,4,5,6,7,8,9,10,11,12,13";
    string[] array = GetStr(s1, s2);  // <--- 这就你要的！
    foreach (string s in array)
    {
      Console.WriteLine(s);
    }
  }
}
/* 程序输出：
2,3,4
6,7,8,9,10
12,13
*/

[yulinlover]

public string[] GetSameItems(string s1,string s2)
{
int i=0;

for(i=0;i<s2.length,i++)
{
if (s1.indexof(s2[i])<0)
{
s2[i]='|';
}
}
return s2.split(new char[]{'|'});   //刨除数组中的空字符串就是你要的结果
}
GetSameItems("2,3,4,6,7,8,9,10,12,13","1,2,3,4,5,6,7,8,9,10,11,12,13")

以上代码只是示意，没有调试，我想你应该明白。

[wuyi8808]

/*
两字符串
"2,3,4,6,7,8,9,10,12,13"
"1,2,3,4,5,6,7,8,9,10,11,12,13,"
得到以下字符串
2,3,4
6,7,8,9,10
12,13
*/

using System;
using System.Collections.Generic;
using System.Text.RegularExpressions;

class Program
{
  static string[] GetStr(string s1, string s2)
  {
    string p1 = Regex.Replace(s1, "([^,]+,)", "$1|");
    string p2 = string.Format(@"(?!{0})\b[^,]+,?", p1);
    string s3 = Regex.Replace(s2, p2, "!").Trim('!');
    return Regex.Split(s3, ",?!+");
  }

  static void Main()
  {
    string s1 = "2,3,4,6,7,8,9,10,12,13";
    string s2 = "1,2,3,4,5,6,7,8,9,10,11,12,13";
    string[] array = GetStr(s1, s2);  // <--- 这就你要的！
    foreach (string s in array)
    {
      Console.WriteLine(s);
    }
  }
}
/* 程序输出：
2,3,4
6,7,8,9,10
12,13
*/

[king2003]

这么专业的程序...

[十八道胡同]

[Quote=引用 8 楼 king2003 的回复:]
这么专业的程序...
[/Quote]
呵呵，2层循环暴力也可求得。
不过空军的代码要仔细看看

[king2003]

public static void GetItems(List<string> list1, List<string> list2)
{

int beginIndex = -1;
int endIndex = 0;
int same = 1;
foreach (string s in list1)
{
if (beginIndex == -1)
{
beginIndex = list2.IndexOf(s);

continue;
}

endIndex = list2.IndexOf(s);
if (endIndex - beginIndex == same)
{
same++;
if (list1.IndexOf(s) == list1.Count - 1)
{
list2.GetRange(beginIndex, same).ForEach(o => Console.Write(o));
break;

}
}
else
{
list2.GetRange(beginIndex, same).ForEach(o => Console.Write(o));
Console.WriteLine();
beginIndex = endIndex;
same = 1;

if (list1.IndexOf(s) == list1.Count - 1)
{
list2.GetRange(beginIndex, same).ForEach(o => Console.Write(o));
}
}

}
}

[king2003]

看我写的多简单

[king2003]

Document transformations: ~/CMSTransformations
Shared layouts: ~/CMSLayouts
Custom page template layouts: ~/CMSTemplateLayouts
Web part layouts: ~/CMSWebPartLayouts
Ad-hoc template layouts: ~/CMSAdhocTemplateLayouts

[jiangshun]

            string A= "2,3,4,6,7,8,9,10,12,13";
            string B = "1,2,3,4,5,6,7,8,9,10,11,12,13";
            string[] _A = A.Split(',');

            List<string> _list = new List<string>();
            string str = "";
            for (int i = 0; i < _A.Length; i++)
            {
                str += _A[i] + ',';
                if (B.IndexOf(str) < 0)
                {
                    _list.Add(str);
                    str = "";
                }
            }

            foreach(string s in _list)
            {
                Console.WriteLine(s+"\r\n");
            }

[jiangshun]

稍微修改了一下在,也就是str += _A[i] + ',';的位置

            string A= "2,3,4,6,7,8,9,10,12,13";
            string B = "1,2,3,4,5,6,7,8,9,10,11,12,13";
            string[] _A = A.Split(',');

            List<string> _list = new List<string>();
            string str = "";
            for (int i = 0; i < _A.Length; i++)
            {

                if (B.IndexOf(str + _A[i] + ',') < 0)
                {
                    _list.Add(str);
                    str = "";
                }
                str += _A[i] + ',';
            }

            foreach(string s in _list)
            {
                Console.WriteLine(s+"\r\n");
            }

[ChrisAK]

显示两个字符串共有的数字?

string A = "2,3,4,6,7,8,9,10,12,13";
string B = "1,2,3,4,5,6,7,8,9,10,11,12,13";
string[] a = A.Split(',');
string[] b = B.Split(',');

var ab = from i in b where a.Contains(i) select i;
Console.WriteLine (string.Join (",",ab.ToArray ()));

不知道LZ是不是这个意思.

[cqsfd]

[Quote=引用 7 楼 wuyi8808 的回复:]
C# code/*
两字符串
"2,3,4,6,7,8,9,10,12,13"
"1,2,3,4,5,6,7,8,9,10,11,12,13,"
得到以下字符串
2,3,4
6,7,8,9,10
12,13*/using System;using System.Collections.Generic;using System.Text.RegularExpressions;class Progra¡­
[/Quote]
很巧妙，代码简洁，赞！
但每次看到用高级语言，封装函数来写算法总感觉怪怪的。

[986753421]

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