两个图片碰撞检测

[nileileini]

______ _______
| | | |
| A | | B |
------ -------

我做一个贪吃蛇游戏，导入两个ＢＩＴＭＡＰ类型的图片，现在的问题是检测Ａ和Ｂ接触的条件．

　１．用ＲＥＣＴ吗？怎么样把图片弄进ＲＥＣＴ里，A的up坐标＝＝Ｂ的top坐标　Ａ的right坐标==B的left坐标

　新手，不大会用这些函数，不知道怎样把图片弄成坐标

[schlafenhamster]

IntersectRect
The IntersectRect function calculates the intersection of two source rectangles and places the coordinates of the intersection rectangle into the destination rectangle. If the source rectangles do not intersect, an empty rectangle (in which all coordinates are set to zero) is placed into the destination rectangle.
BOOL IntersectRect(
LPRECT lprcDst, // pointer to structure for intersection
CONST RECT *lprcSrc1, // pointer to structure with first rectangle
CONST RECT *lprcSrc2 // pointer to structure with second rectangle
);
//
IsRectEmpty
The IsRectEmpty function determines whether the specified rectangle is empty. A empty rectangle is one that has no area; that is, the coordinate of the right side is less than or equal to the coordinate of the left side, or the coordinate of the bottom side is less than or equal to the coordinate of the top side.

BOOL IsRectEmpty(
CONST RECT *lprc // pointer to structure with rectangle
);

[jwybobo2007]

无非是判断坐标是否相交,想想中学学的直角坐标系,是怎么判断相交的

[lizhigang34]

位图是矩形的,要通过矩形来进行碰撞检测,最好做点处理..比如下面两张图片,A,B;
图片的矩形区域用-和|圈出来了,而实际的区域用*圈出,些时两张图片是相撞的,但图片中的真实内容并没有碰撞,所以游戏的效果可能就很假了.可以根据需要,取图片的m/n来作为碰撞检测的矩形.

         |-----------
         |  *       | 
----------- * *     |
|   **** || *  *    |
|  *   * || *   *   |
| *  A * || *  B *  |
| ****** || *     * |
         |  ********|