python 爬取网页是出现的错误

[zhongkouwei]

代码:
timeout = 10
socket.setdefaulttimeout(timeout)
sock = urllib2.urlopen(url)
html = sock.read()
一般情况能行，运行没问题，可有常常会突然报错
Traceback (most recent call last):
File "/usr/local/lib/python2.5/threading.py", line 486, in __bootstrap_inner
self.run()
File "spider_eastmoney.py", line 150, in run
next_page = parse_ (mysqlDB, http, html, mod_name)
File "spider_eastmoney.py", line 94, in parse_
page_html= http.get_html(pageurl)
File "/home/Spider/News/genericHttp.py", line 47, in get_html
File "/home/Spider/News/genericHttp.py", line 47, in get_html
html = sock.read()
File "/usr/local/lib/python2.5/socket.py", line 304, in read
data = self._sock.recv(rbufsize)
File "/usr/local/lib/python2.5/httplib.py", line 529, in read
s = self.fp.read(amt)
File "/usr/local/lib/python2.5/socket.py", line 328, in read
data = self._sock.recv(left)
timeout: timed out
这是什么问题，以前没遇过，我用了多线程，线程数我设为1，会不会是这个原因。

[zhongkouwei]

我说，是什么原因造成的

[Semigod]

这不是很明显地写着receive timeout吗

[mrshelly]

网络情况造成的...

很正常....

[wangzheng7912]

这种情况需要你对它的Exception做个处理，具体可以参考python的网络编程

[DDGG]

用try...except把html = sock.read()包起来，在except里对异常进行捕捉，该忽略忽略，该重试重试。

[lsesunny]

[Quote=引用 5 楼 ddgg 的回复:]
用try...except把html = sock.read()包起来，在except里对异常进行捕捉，该忽略忽略，该重试重试。
[/Quote]
test

[mrshelly]

while True:
try:

except:
time.sleep(2)
continue

if 数据正常 :
break

[zouhailin]

高人, 学到一招.