用递归程序输出机器人打开盒子、拿糖、关闭盒子的动作过程~

[chidanly]

有三个大小不等的盒子及一块糖，将糖放在第3个盒子中，第3个盒子关上后放在第2个盒子中，第2个盒子关上后放在第1个盒子中。现在一个机器人来取这块糖，取走后，关上所有盒子。机器人的动作过程描述如下：
open the 1 box
open the 2 box
open the 3 box
get a sugar
close the 3 box
close the 2 box
close the 1 box
编写一个递归程序，要求从键盘输入盒子数后，输出如上所示的机器人的动作过程。

[do_fork]

#include <iostream>

template <int n> void get_sugar(int x)
{
    if (x>n)
        return;
    std::cout<<"open the "<<x<<"box\n";
    if (x==n)
        std::cout<<"get a sugar \n";
    get_sugar<n>(x+1);
    std::cout<<"close the "<<x<<"box\n";
}

template <int n> void bot_get()
{
    get_sugar<n>(1);
}

int main()
{
    bot_get<3>();
}

[chidanly]

#include <iostream>
using namespace std;

void open(int n,int i)
{
int j=0;
j=n-i+1;
if(i>0)
{
cout<<"open the "<<j<<" box"<<endl;
open(n,i-1);
}
}

void close(int n)
{
if(n>0)
{
cout<<"close the "<<n<<" box"<<endl;
close(n-1);
}
}

int main()
{
int n,i;
cout<<"Please input the number of boxs:"<<endl;
cin>>n;
i=n;
open(n,i);
cout<<"get a sugar"<<endl;
close(n);
return 0;
}

[pengs88]

#include<iostream>
#include<iomanip>
using namespace std;

void robot_open(int n=3);
void robot_close(int m=3);

int main()
{
int n=0;

cout<<"please input a number: ";
cin>>n;

robot_open();
cout<<setw(5*8)<<"get the sugar !"<<endl;
robot_close();

robot_open(n);
cout<<setw(8*(n+2))<<"get the sugar !"<<endl;
robot_close(n);

return 0;
}


void robot_open(int n)
{
if(n>0)
{
robot_open(n-1);
cout<<setw(8*n)<<"open the "<<n<<"box!"<<endl;
}
}

void robot_close(int m)
{
while(m>0)
cout<<setw(8*m+8)<<"Close the "<<m--<<"box!"<<endl;

}

[hecha]

int box_count = 1;
void get_candy(int box_level)
{
    if (box_level == 0)
    {
        cout << "get a candy" << endl;
    }
    else
    {
        cout << "open box " << box_count++ << endl;
        get_candy(box_level - 1);
        cout << "close box " << box_count-- << endl;
    }
}