请求一份多线程的代码样例。

[mQney]

刚接触多线程，自己看了一点书，想写点东西，但是理论联系实际还有点困难，不知道方法和我需要实现的目的之间的联系，希望通过代码样例快速找到其中联系。

for(int i=0; i<100; i++){
System.out.println(i+1);
}

就是这段小程序，如何用5个线程实现。我的理解就是，有五个线程同时打印。

[shine333]

public class Test extends Thread {

private final int num;

public Test(int num) {
this.num = num;
}

@Override
public void run() {
for (int i = 0; i < 100; i++) {
System.out.println((i + 1) + " in thread " + num);
try {
// 为了突出效果
sleep(10);
} catch (InterruptedException e) {
}
}
}

public static void main(String[] args) throws Exception {
for (int i = 0; i < 5; i++) {
new Test(i).start();
}
}

}

[ikaoni]

要求每个线程都输出1-100，还是分别输出其中的不重复的数（并集是1-100）?

[bawgiitx]

/**每个线程各从1打印到100
*/
public class Main{
    public static void main(String[] args) throws Exception {
        class runn implements Runnable {

            final String robj = "";

            public void run() {
                for (int i = 0; i < 100; i++) {
                    synchronized (robj) {
                        System.out.println("线程:" + Thread.currentThread() + ",i=" + (i + 1));
                        System.out.flush();
                    }
                    try {
                        Thread.sleep(0);
                    } catch (InterruptedException ex) {
                        Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
                    }
                }
            }
        }
        runn r = new runn();
        for (int i = 0; i < 5; i++) {
            new Thread(r).start();
        }
    }

/**五线程加起来一共从1-100
*/
class runn implements Runnable {

    final String robj = "";
    static int i = 0;

    public void run() {
        for (; i < 100;) {
            synchronized (robj) {
                System.out.println("线程:" + Thread.currentThread() + ",i=" + (++i));
                System.out.flush();
            }
            try {
                Thread.sleep(0);
            } catch (InterruptedException ex) {
                Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
            }
        }
    }
}

public class Main {

    public static void main(String[] args) throws Exception {

        runn r = new runn();
        for (int i = 0; i < 5; i++) {
            new Thread(r).start();
        }
    }

[bawgiitx]

将第二个的
static int i = 0;
改为int i = 0;
就是第一个等价

[princess_rosie]

路过……