跪求：使用swig转化C++为python代码中的数组问题

[songqiangqiang]

最近在学习swig，网上的例子可以通过，但是试着转化数组的时候出了问题下面贴出各个文件
请教打印数组内容的方法：
使用的是linux系统库的生成方法如下：
swig -c++ -python md52.i
g++ -fpic -c -I/usr/include/python2.4 -I/usr/lib/python2.4/config md52.cpp md52_wrap.cxx
g++ -shared -o _md52.so md52.o md52_wrap.o -L/usr/lib/python2.4 -lpython2.4

具体使用的时候
[@66.223 md5]# python
Python 2.4.3 (#1, Sep 17 2008, 16:07:08)
[GCC 4.1.2 20071124 (Red Hat 4.1.2-41)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import md52
>>> a=md52.md5_long_128()
>>> a.intData[0]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: unsubscriptable object
>>>



md52.i
//////////////////////////////////////////////
%module md52
%{
/* Includes the header in the wrapper code */
#include "md52.h"
%}

/* Parse the header file to generate wrappers */
%include "md52.h"


md52.h
////////////////////////////////////////////

struct md5_long_128{

unsigned int intData [4];

// union{
// char byteData[16]; /*data stored in md5-byte format*/
// unsigned int intData [4]; /*data stored in int format*/
// }data; /*output vector union of Md5 Algorithm*/

/*-------------------------------------
compare fuction definition of
output vector of length 128
--------------------------------------*/
bool
operator ==(
const md5_long_128 & a /*the other md5 output vector of length 128*/
)const
{
return (intData[0]==a.intData[0])&&
(intData[1]==a.intData[1])&&
(intData[2]==a.intData[2])&&
(intData[3]==a.intData[3]);
}

};

md5_long_128 getSign128(const char * inputStr, int inputLen=-1);

md5.cpp
//////////////////////////////////////////////////////////////////////////
#include "md52.h"
#include <string.h>
#include <stdio.h>


md5_long_128 getSign128(const char * inputStr , int inputLen)
{
md5_long_128 digest; /*output vector of the md5 procedure */

printf("a");

return digest;

}

[thy38]

前一阵子看过SWIG，一个月不用又忘了不少。回头我看看

[thy38]

刚刚去SWIG官网的文档看了一下：Unfortunately, our Python version suffers a number of drawbacks. Most notably, there is no way for us to access any of the grid data (which is easily accomplished in C++). However, there are ways to fix this :

也就是说，直接访问不行，可以问其它方法包装一下，加一层Wrapper函数：

%module pde
%{
#include "pde.h"
%}

%include pde.h

// Add a few "helper" functions to extract grid data 
%inline %{
double  Grid2d_get(Grid2d *g, int i, int j) {
      return g->data[i][j];
}
void    Grid2d_set(Grid2d *g, int i, int j, double val) {
      g->data[i][j] = val;
}
%}

在Python中：

# An example using our set/get functions

from pde import *

# Set up an initial condition
def initcond(h):
	h.set_temp(0.0)
	nx = h.grid.xpoints
	for i in range(0,nx):
		Grid2d_set(h.grid,i,0,1.0)                        # Set grid values

# Dump out to a file
def dump(h,filename):
	f = open(filename,"w")
	nx = h.grid.xpoints
	ny = h.grid.ypoints
	for i in range(0,nx):
		for j in range(0,ny):
			f.write(str(Grid2d_get(h.grid,i,j))+"\n")  # Get grid value
	f.close()

# Set up a problem and run it

h = Heat2d(50,50)
initcond(h)
fileno = 1
for i in range(0,25):
	h.solve(100)
	dump(h,"Dat"+str(fileno))
	print "time = ", h.time
	fileno = fileno+1