Servlet如何将控制权转交给另一个页面

[dingding_hi]

package com.zxm.web;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class CompIntrDeal extends HttpServlet {

	public CompIntrDeal() {
		super();
	}

	
	public void destroy() {
		super.destroy(); 
	}
	
	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
		rd.forward(request, response);
	}

	public void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		doGet(request,response);
	}

	public void init() throws ServletException {
	}

}

本来预期结果是跳转到header.html页面。
但浏览器中却显示了下面的一条消息，实际上转到的并不是head.html页面：

引用

This is class com.zxm.web.CompIntrDeal, using the POST method

[dingding_hi]

我的servlet源代码是这样的：

package com.zxm.web;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class CompIntrDeal extends HttpServlet {

	public CompIntrDeal() {
		super();
	}

	
	public void destroy() {
		super.destroy(); 
	}
	
	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
		rd.forward(request, response);
	}

	public void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		doGet(request,response);
	}

	public void init() throws ServletException {
	}

}

[Trinx]

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[believefym]

form的action是怎么写的，
web.xml里servlet映射好了吗？

[dingding_hi]

/admin/compIntr.jsp中form表单的部分内容：

out.println("<form action=\"CompIntrDeal\" method=\"post\">");

web.xml的servlet映射：

  <servlet>
    <description>This is the description of my J2EE component</description>
    <display-name>This is the display name of my J2EE component</display-name>
    <servlet-name>CompIntrDeal</servlet-name>
    <servlet-class>com.zxm.web.CompIntrDeal</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>CompIntrDeal</servlet-name>
    <url-pattern>/admin/CompIntrDeal</url-pattern>
  </servlet-mapping>

映射应该是没有什么问题的，都是通过myeclipse自动产生的

[believefym]

把整个web.xml贴出来看看？

[wwwtyb]

如果Servlet配置没有问题的话，
可能是
RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
这个地方跳转页面路径的问题
改成：RequestDispatcher rd = request.getRequestDispatcher("header.html");
试试看....

[fdimaof]

试试看了

[dingding_hi]

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee   http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
 <context-param>
  <param-name>host</param-name>
  <param-value>localhost</param-value>
 </context-param>
 <context-param>
  <param-name>database</param-name>
  <param-value>website</param-value>
 </context-param>
 <context-param>
  <param-name>user</param-name>
  <param-value>root</param-value>
 </context-param>
 <context-param>
  <param-name>password</param-name>
  <param-value>123</param-value>
 </context-param>
 <context-param>
  <param-name>JDBCDriver</param-name>
  <param-value>com.mysql.jdbc.Driver</param-value>
 </context-param>
 <context-param>
  <param-name>dbPort</param-name>
  <param-value>3306</param-value>
 </context-param>
  <servlet>
    <description>This is the description of my J2EE component</description>
    <display-name>This is the display name of my J2EE component</display-name>
    <servlet-name>CompIntrDeal</servlet-name>
    <servlet-class>com.zxm.web.CompIntrDeal</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>CompIntrDeal</servlet-name>
    <url-pattern>/admin/CompIntrDeal</url-pattern>
  </servlet-mapping>
 <welcome-file-list>
  <welcome-file>index.jsp</welcome-file>
 </welcome-file-list>
 <login-config>
  <auth-method>BASIC</auth-method>
 </login-config>
</web-app>

[funlinihao]

考虑./admin/CompIntrDeal

[crazylaa]

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
rd.forward(request, response);
}

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet(request,response);
}

换一下试试看：

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request,response);

}

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
rd.forward(request, response);

}

[hwzjava]

RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
rd.forward(request, response);

[aloyise]

估计是 那个servlet的mapping没写好

[SambaGao]

[Quote=引用 6 楼 wwwtyb 的回复:]
如果Servlet配置没有问题的话，
可能是
RequestDispatcher rd = request.getRequestDispatcher("/admin/header.html");
这个地方跳转页面路径的问题
改成：RequestDispatcher rd = request.getRequestDispatcher("header.html");
试试看....
[/Quote]

试试

[dragon_java_li]

把action值改成post