gridview 点击一下链接，弹出一个小页面的问题！

[gaoxing_1985007]

在做一个企业站，其中招聘信息已经列表显示了，我想点击“查看该职位”，就能弹出一个小的页面，用表格的形式把该职位的详细信息显示出来，小页面不显示地址栏，工具栏，只显示页面中的内容。页面gridview代码如下：

 <asp:GridView ID="GVJobs" runat="server" AutoGenerateColumns="False" 
            Width="698px">
            <Columns>
                <asp:BoundField DataField="J_jobName" HeaderText="职位名称" />
                <asp:BoundField DataField="J_jobNumber" HeaderText="招聘人数" />
                <asp:BoundField DataField="J_jobEducation" HeaderText="学历要求" />
                <asp:BoundField DataField="J_jobTime" HeaderText="发布时间" />
             <asp:TemplateField>   
                 <ItemTemplate>
                 
                    <asp:LinkButton ID="LinkButton2" runat="server" Text="查看该职位" PostBackUrl='<%# "~/JobsView.aspx?J_jobId=" + Eval("J_jobId") %>' 
                      CausesValidation="False"></asp:LinkButton>
                    <asp:LinkButton ID="LinkButton1" runat="server" PostBackUrl='<%# "~/Apply.aspx?J_jobId=" + Eval("J_jobId") %>' 
                      CausesValidation="False" Text="应聘该职位"></asp:LinkButton>
                      
                 </ItemTemplate>
            </asp:TemplateField>
            </Columns>
        </asp:GridView>

[yjcel1988]

加个OnClientClick="window.open(...)"

[comzheng]

可以把<asp:LinkButton ID="LinkButton2" runat="server" Text="查看该职位" PostBackUrl='<%# "~/JobsView.aspx?J_jobId=" + Eval("J_jobId") %>'
CausesValidation="False"></asp:LinkButton>
改为。
<a href="#" onclick="javascript:window.open('改下路径../JobsView.aspx?J_jobId="+<%#Eval("J_jobId")%>+"','','width=430,height=450,scrollbars=1,resizable=0')">查看该职位</a>

[zgke]

模态窗 window.showModalDialog(

或则做个DIV position="absolute"; 把要显示的内容放DIV里 控制位置和显示不显示

[bojiansky]

function open() {
loc_x = document.body.scrollLeft + event.clientX - event.offsetX + 100;
loc_y = document.body.scrollTop + event.clientY - event.offsetY + 170;
window.showModalDialog("Default2.aspx", self, "edge:raised;scroll:0;status:0;help:0;resizable:1;dialogWidth:350px;dialogHeight:350px;dialogTop:" + loc_y + "px;dialogLeft:" + loc_x + "px");
}

模态窗口。

[Lovely_baby]

可以先通过打开窗体：

  function open() { 
            loc_x = document.body.scrollLeft + event.clientX - event.offsetX + 100; 
            loc_y = document.body.scrollTop + event.clientY - event.offsetY + 170; 
            window.showModalDialog("处理页", self, "edge:raised;scroll:0;status:0;help:0;resizable:1;dialogWidth:350px;dialogHeight:350px;dialogTop:" + loc_y + "px;dialogLeft:" + loc_x + "px"); 
        } 

在处理页上，进行数据的绑定和处理~~

[别递烟哥不会]

又是模态啊！
<script>
function open()
{
window.showmodaldialog('url' 参数....)
}
</script>

onclientclik="open()"

[chengcheng1253]

[Quote=引用 3 楼 zgke 的回复:]
模态窗  window.showModalDialog(

或则做个DIV  position="absolute";  把要显示的内容放DIV里 控制位置和显示不显示
[/Quote]
在加上ajax 就OK 了

[Aderlee]

在做弹出页面的功能时, 建议考虑浏览器的拦截问题,

也可以做成弹出层的方式.

[zhounet]

var div1 = document.createElement("div");
div1.innerHtml = 内容
内容在这里可以是一个table的html也可以是文本

[gaoxing_1985007]

方法好多啊

[xiezechang]

走马看野花

[itweichao]

首先给GridView中的<ItemTemplate>加入一个隐藏的控件
<asp:Label ID="lbl_Role" runat="server" Text='<%# Bind("J_jobName") %>' Visible="false"></asp:Label>
并且对于LinkButton1和LinkButton2各加入属性
CommandName="Command1"
CommandName="Command2"

然后给GridView加入事件
protected void GVJobs_RowCreated(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
LinkButton Search= (LinkButton)e.Row.FindControl("LinkButton1");

Search.CommandArgument = e.Row.RowIndex.ToString();
}
}

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
int index = Convert.ToInt32(e.CommandArgument);
if (e.CommandName == "Command1")
{
string role = ((Label)this.GridView1.Rows[index].FindControl("lbl_Role")).Text;
string url = "RoleManage.aspx?UserID=" + userID + "&type=1";//举例
ClientScript.RegisterStartupScript(this.GetType(), "pop", "popUp('" + url + "' ,600,450)", true);
}
if (e.CommandName == "Command2")
{
string role = ((Label)this.GridView1.Rows[index].FindControl("lbl_Role")).Text;
string url = "RoleManage.aspx?UserID=" + userID + "&type=2";//举例
ClientScript.RegisterStartupScript(this.GetType(), "pop", "popUp('" + url + "' ,600,450)", true);
}
}

最后在前台页面加入楼主想要的JS
<script type="text/javascript">
function popUp(url,width,height,winname,left,top)
{
var left = (left==''||left==null)?(screen.width - width)/2:left;
var top = (top==''||top==null)?(screen.height - height)/2:top;
var winnames = (winname=='')?'popUpWin':winname;
window.open(url, winnames, 'toolbar=no,location=no,directories=no,status=no,menubar=no,scrollbars=yes,resizable=no,copyhistory=yes,width='+width+',height='+height+',left='+left+', top='+top+',screenX='+left+',screenY='+top+'');
}
</script>

[itweichao]

protected void GVJobs_RowCreated(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
LinkButton Search= (LinkButton)e.Row.FindControl("LinkButton1");

Search.CommandArgument = e.Row.RowIndex.ToString();
LinkButton Apply= (LinkButton)e.Row.FindControl("LinkButton2");

Apply.CommandArgument = e.Row.RowIndex.ToString();
}
}
刚才少了一句

[wuyq11]

protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{

((HyperLink)e.Row.Cells[0].FindControl("HyperLink1")).Attributes.Add("onclick", "windows.open('')");

((HyperLink)e.Row.Cells[0].Controls[0]).Attributes.Add("onclick", "windows.open('')");
}
}

[gaoxing_1985007]

用js就是实现不了效果，用弹出层，不会啊

[gaoxing_1985007]

嗯

[Adechen]

用弹出一个div的方法，