超难度问题，实现$merge方法。

[cn00439802]

mootools中有$merge方法能实现以下效果：

    var obj1 = {a: 0, b: 1};
    var obj2 = {c: 2, d: 3};
    var obj3 = {a: 4, d: 5};
    var merged = $merge(obj1, obj2, obj3); //returns {a: 4, b: 1, c: 2, d: 5}, (obj1, obj2, and obj3 are unaltered)
 
    var nestedObj1 = {a: {b: 1, c: 1}};
    var nestedObj2 = {a: {b: 2}};
    var nested = $merge(nestedObj1, nestedObj2); //returns: {a: {b: 2, c: 1}}

简单来说就是把几个对象的属性合并起来，难点就在于对象里面的属性是不确定的，可能无限嵌套。

[cn00439802]

偶滴神啊，钻石五角星们，都歇息了萨？自己顶自己下!!!!!!

[xmliy]

使用jQuery,

var obj = $.extend(true, obj1, obj2, obj3,......);

[cn00439802]

如果能用框架，我还发出来干嘛。。。

[xmliy]

不用框架，但可以把框架中的代码拷出来用

function $merge() 
{
  var target = arguments[0] || {}, i = 1, length = arguments.length, deep = false, options;
  if ( typeof target === "boolean" ) 
  {
    deep = target;
    target = arguments[1] || {};
    i = 2;
  }
  if ( typeof target !== "object" && target.toString() != "[object Function]" ) target = {};
  if ( length == i ) 
  {
    target = this;
    --i;
  }
  for ( ; i < length; i++ )
  {
    if ( (options = arguments[ i ]) != null )
    {
      for ( var name in options ) 
      {
        var src = target[ name ], copy = options[ name ];
        if ( target === copy ) continue;
        if ( deep && copy && typeof copy === "object" && !copy.nodeType )
          target[ name ] = $merge( deep, src || ( copy.length != null ? [ ] : { } ), copy );
        else if ( copy !== undefined )
          target[ name ] = copy;
      }
    }
  }
  return target;
};

  var obj = $merge(true, obj1, obj2, obj3, ......);

[fengsky491]

好像就是js的hash

[fengsky491]

没用过mootools，jquery也正在看，

function merge(){
 var target = [];

if(!arguments[0]){
  return null;
}
for(var i = 0;i < arguments.length;i++){
  for(var p in arguments[i]){
target[p] = arguments[i][p];
}
}

var tmp = [];

for(var p in target){
  tmp.push(p + ':' + target[p]);
}

arguments[0] = eavl('{' + tmp.join(',') + '}');

return arguments[0];
}

[fengsky491]

arguments[0] = eavl('{' + tmp.join(',') + '}');

return arguments[0];

改成：

eval('var t =' + '{' + tmp.join(',') + '}');
return t;